Delete vs operator delete (and void pointer)

Question

Does delete ptr differ from operator delete(ptr) only in this, that delete calls ptr destructor? Or in other words, does delete ptr first call a destructor of ptr and then operator delete(ptr) to free allocated memory? Then is delete ptr technically equivalent to the following:

T * ptr = new T;

//delete ptr equivalent:
ptr->~T();
::operator delete(static_cast<void *>(ptr));

?

Dissert

Yes, that's the only difference, besides the fact that you can overload operator delete. – Nelan

Answer 1

delete ptr will do overload resolution for operator delete, so it may not call the global ::operator delete

But otherwise, yes. The delete operator calls the relevant destructor, if any, and then calls operator delete.

Galumph