Approaches for spatial geodesic latitude longitude clustering in R with geodesic or great circle distances
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H

1

14

I would like to apply some basic clustering techniques to some latitude and longitude coordinates. Something along the lines of clustering (or some unsupervised learning) the coordinates into groups determined either by their great circle distance or their geodesic distance. NOTE: this could be a very poor approach, so please advise.

Ideally, I would like to tackle this in R.

I have done some searching, but perhaps I missed a solid approach? I have come across the packages: flexclust and pam -- however, I have not come across a clear-cut example(s) with respect to the following:

  1. Defining my own distance function.
  2. Do either flexclut (via kcca or cclust) or pam take into account random restarts?
  3. Icing on the cake = does anyone know of approaches/packages that would allow one to specify the minimum number of elements in each cluster?
Harod answered 13/1, 2014 at 15:23 Comment(0)
P
20

Regarding your first question: Since the data is long/lat, one approach is to use earth.dist(...) in package fossil (calculates great circle dist):

library(fossil)
d = earth.dist(df)    # distance object

Another approach uses distHaversine(...) in the geosphere package:

geo.dist = function(df) {
  require(geosphere)
  d <- function(i,z){         # z[1:2] contain long, lat
    dist <- rep(0,nrow(z))
    dist[i:nrow(z)] <- distHaversine(z[i:nrow(z),1:2],z[i,1:2])
    return(dist)
  }
  dm <- do.call(cbind,lapply(1:nrow(df),d,df))
  return(as.dist(dm))
}

The advantage here is that you can use any of the other distance algorithms in geosphere, or you can define your own distance function and use it in place of distHaversine(...). Then apply any of the base R clustering techniques (e.g., kmeans, hclust):

km <- kmeans(geo.dist(df),centers=3)  # k-means, 3 clusters
hc <- hclust(geo.dist(df))            # hierarchical clustering, dendrogram
clust <- cutree(hc, k=3)              # cut the dendrogram to generate 3 clusters

Finally, a real example:

setwd("<directory with all files...>")
cities <- read.csv("GeoLiteCity-Location.csv",header=T,skip=1)
set.seed(123)
CA     <- cities[cities$country=="US" & cities$region=="CA",]
CA     <- CA[sample(1:nrow(CA),100),]   # 100 random cities in California
df     <- data.frame(long=CA$long, lat=CA$lat, city=CA$city)

d      <- geo.dist(df)   # distance matrix
hc     <- hclust(d)      # hierarchical clustering
plot(hc)                 # dendrogram suggests 4 clusters
df$clust <- cutree(hc,k=4)

library(ggplot2)
library(rgdal)
map.US  <- readOGR(dsn=".", layer="tl_2013_us_state")
map.CA  <- map.US[map.US$NAME=="California",]
map.df  <- fortify(map.CA)
ggplot(map.df)+
  geom_path(aes(x=long, y=lat, group=group))+
  geom_point(data=df, aes(x=long, y=lat, color=factor(clust)), size=4)+
  scale_color_discrete("Cluster")+
  coord_fixed()

The city data is from GeoLite. The US States shapefile is from the Census Bureau.

Edit in response to @Anony-Mousse comment:

It may seem odd that "LA" is divided between two clusters, however, expanding the map shows that, for this random selection of cities, there is a gap between cluster 3 and cluster 4. Cluster 4 is basically Santa Monica and Burbank; cluster 3 is Pasadena, South LA, Long Beach, and everything south of that.

K-means clustering (4 clusters) does keep the area around LA/Santa Monica/Burbank/Long Beach in one cluster (see below). This just comes down to the different algorithms used by kmeans(...) and hclust(...).

km <- kmeans(d, centers=4)
df$clust <- km$cluster

It's worth noting that these methods require that all points must go into some cluster. If you just ask which points are close together, and allow that some cities don't go into any cluster, you get very different results.

Perishable answered 13/1, 2014 at 21:25 Comment(2)
Hmm... LA split into two by the clustering algorithm? looks like there is something wrong.Conventionalism
wouldn't this cause an issue if you are running on a data size > 2million recordsObscure

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