I want to make a type that can be inherited from by types in the same assembly, but cannot be inherited from outside of the assembly. I do want the type to be visible outside of the assembly.
Is this possible?
I want to make a type that can be inherited from by types in the same assembly, but cannot be inherited from outside of the assembly. I do want the type to be visible outside of the assembly.
Is this possible?
You can make the constructor internal:
public class MyClass
{
internal MyClass() { }
}
Every class that derives from a base class must call a constructor of the base class in its constructor. Since it can't call the constructor if the base class is in a different assembly, the derived class doesn't compile.
public class EvilInternalClass : MyClass { public EvilInternalClass() { } }
–
Interfluent static
variables/static
methods/const
values should be marked as internal
or private
as well. –
Vexation I think this question could still benefit from a semantically correct answer... which is "no". You can't declare a type as "sealed to external assemblies only".
Don't get me wrong: dtb's answer is a good one. An internal constructor is the closest you can get from the desired result.
However, I think that anyone reading this should be aware that in this example, MyClass
wouldn't be described as being sealed at runtime. It is unlikely that this will ever be a problem, but if may cause logic based on reflection (from your code or a 3rd party library) to act differently on this particular type. It's something to keep in mind.
And now, to further expand on dtb's sample code:
public class MyClass
{
internal MyClass() { }
// This factory method will be accessible from external assemblies, making your class instantiable yet still "sealed"
public static MyClass Create()
{
return new MyClass();
}
}
This way you can still create instances of MyClass
from outside the owning assembly, while still keeping control over inheritance.
© 2022 - 2024 — McMap. All rights reserved.