How to replace string in Go template?
Asked Answered
S

1

15

I use "text/template" module.

I have struct like this to parse XML from Blogger

type Media struct {
    ThumbnailUrl string `xml:"url,attr"`
}


type Entry struct {
    ID string `xml:"id"`
    Published Date `xml:"published"`
    Updated Date `xml:"updated"`
    Draft Draft `xml:"control>draft"`
    Title string `xml:"title"`
    Content string `xml:"content"`
    Tags Tags `xml:"category"`
    Author Author `xml:"author"`
    Media Media `xml:"thumbnail"`
    Extra string
}

Then I create Go Template like this

[image]
    src = "{{ replace .Media.ThumbnailUrl 's72-c' 's1600' }}"
    link = ""
    thumblink = "{{ .Media.ThumbnailUrl }}"
    alt = ""
    title = ""
    author = ""
    license = ""
    licenseLink = ""

The replace function not defined. I want to replace URL from {{ .Media.ThumbnailUrl }}

For example:

from this URL

https://2.bp.blogspot.com/-DEeRanrBa6s/WGWGwA2qW5I/AAAAAAAADg4/feGUc-g9rXc9B7hXpKr0ecG9UOMXU3_VQCK4B/s72-c/pemrograman%2Bjavascript%2B-%2Bpetanikode.png

To this URL

https://2.bp.blogspot.com/-DEeRanrBa6s/WGWGwA2qW5I/AAAAAAAADg4/feGUc-g9rXc9B7hXpKr0ecG9UOMXU3_VQCK4B/s1600/pemrograman%2Bjavascript%2B-%2Bpetanikode.png

Shaniceshanie answered 14/1, 2017 at 7:33 Comment(1)
Uh, set the variable of ThumbnailUrl to the url you want in whatever is calling the template? I don't think replace is a thing in go templates.Quinte
N
12

You can write a helper view function like this

func replace(input, from,to string) string {
    return strings.Replace(input,from,to, -1)
}

funcMap := template.FuncMap{
        "replace":  replace,
}
template := template.New("").Funcs(funcMap)

and use the template to render the view.

code ref links

  1. https://github.com/sairam/kinli/blob/master/template_funcs.go#L57-L59
  2. https://github.com/sairam/kinli/blob/master/templates.go#L48
Neuroblast answered 14/1, 2017 at 7:53 Comment(0)

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