How to sort by length and then alphabetically

Question

Assume I had the following Javascript array. How do you sort by length, then alphabetically?

Assume the following array:

var array = ["a", "aaa", "bb", "bbb", "c"];

When sorted it should produce: a, c, bb, aaa, bbb. Thank you in advance!

Libratory

Answer 1

You can first sort by length and then use localeCompare() to sort alphabetically.

var array = ["a", "aaa", "bb", "bbb", "c"];
array.sort(function(a, b) {
  return a.length - b.length || a.localeCompare(b)
})

console.log(array)

Bikol

Also works: return a.length === b.length ? a.localeCompare(b) : a.length - b.length – Negrete

Answer 2

Sort by length first then alphabetically using the || operator for more than one criteria. However, in your case, a simple sort will do.

var array = ["a", "aaa", "bb", "bbb", "c"];

array.sort(function(a, b) {
  return a.length - b.length || a.localeCompare(b);
});

console.log(array);

Or

var array =["c", "aa", "bb", "bbb", "b", "aaa", "a"].sort();

array.sort(function(a, b) {
  return a.length - b.length || 0;
});

console.log(array);

Clack

Just a heads up about sort, it changes the source array so you don't need to assign it to a new variable. developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… – Sri

If you don't want to change the original array you can make a copy first like this #9593240 – Sri

Answer 3

arr.sort((a, b) => a.length - b.length || this)

Chromogenic