I have this code that emits some IL
instructions that calls string.IndexOf
on a null
object:
MethodBuilder methodBuilder = typeBuilder.DefineMethod(
"Foo",
MethodAttributes.Public,
typeof(void), Array.Empty<Type>());
var methodInfo = typeof(string).GetMethod("IndexOf", new[] {typeof(char)});
ILGenerator ilGenerator = methodBuilder.GetILGenerator();
ilGenerator.Emit(OpCodes.Ldnull);
ilGenerator.Emit(OpCodes.Ldc_I4_S, 120);
ilGenerator.Emit(OpCodes.Call, methodInfo);
ilGenerator.Emit(OpCodes.Ret);
This is the generated IL
code:
.method public instance int32 Foo() cil managed
{
// Code size 12 (0xc)
.maxstack 2
IL_0000: ldnull
IL_0001: ldc.i4.s 120
IL_0003: nop
IL_0004: nop
IL_0005: nop
IL_0006: call instance int32 [mscorlib]System.String::IndexOf(char)
IL_000b: ret
} // end of method MyDynamicType::Foo
As you can see there are three nop
instructions before the call
instruction.
First I thought about Debug/Release build but this is not compiler generated code, I am emitting raw IL code and expect to see it as is.
So my question is why are there three nop
instruction when I hadn't emitted any?