How to get human-readable event type from QEvent?
Asked Answered
T

2

15

I want to debug event handling code and would like to convert QEvent::Type enum's value to a human-readable string. QEvent has a Q_GADGET macro, so presumably there's a way of pulling that off?

Tuneless answered 20/3, 2014 at 14:7 Comment(0)
T
27

Recent versions of Qt do the right thing when outputting events to the debug stream, so the below isn't neccessary. If you get an error similar to warning C4273: 'operator <<' : inconsistent dll linkage, it means that your version of Qt already supports this without need for the code below.

The Q_GADGET macro adds a QMetaObject staticMetaObject member to the class. The static metaobject's definition is generated by moc, and it - in the case of QEvent - contains the enumeration information.

Below is an example of how to leverage that to give a more reasonable QDebug output of events.

#include <QEvent>
#include <QMetaEnum>
#include <QDebug>   

/// Gives human-readable event type information.
QDebug operator<<(QDebug str, const QEvent * ev) {
   static int eventEnumIndex = QEvent::staticMetaObject
         .indexOfEnumerator("Type");
   str << "QEvent";
   if (ev) {
      QString name = QEvent::staticMetaObject
            .enumerator(eventEnumIndex).valueToKey(ev->type());
      if (!name.isEmpty()) str << name; else str << ev->type();
   } else {
      str << (void*)ev;
   }
   return str.maybeSpace();
}

Use example:

void MyObject::event(QEvent* ev) {
  qDebug() << "handling an event" << ev;
}
Tuneless answered 20/3, 2014 at 14:7 Comment(2)
Recent versions of Qt do the right thing when outputting events to the debug stream, so the below isn't neccessary. Could you please more specific what version please?Chitter
Given the date the answer was edited, it would be at least the version available back then, and that is 5.8. Possibly earlier versions too.Phocaea
C
7

Q_GADGET and Q_ENUM can be combined to get the following template:

template<typename EnumType>
QString ToString(const EnumType& enumValue)
{
    const char* enumName = qt_getEnumName(enumValue);
    const QMetaObject* metaObject = qt_getEnumMetaObject(enumValue);
    if (metaObject)
    {
        const int enumIndex = metaObject->indexOfEnumerator(enumName);
        return QString("%1::%2::%3").arg(metaObject->className(), enumName, metaObject->enumerator(enumIndex).valueToKey(enumValue));
    }

    return QString("%1::%2").arg(enumName).arg(static_cast<int>(enumValue));
}

Example:

void MyObject::event(QEvent* ev) 
{
    qDebug() << ToString(ev->type());
}
Cetology answered 21/2, 2017 at 11:40 Comment(0)

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