Misbehavior when trying to store a string set using SharedPreferences
Asked Answered
D

6

79

I'm trying to store a set of strings using the SharedPreferences API.

Set<String> stringSet = sharedPrefs.getStringSet("key", new HashSet<String>());
stringSet.add(new_element);

SharedPreferences.Editor editor = sharedPrefs.edit();
editor.putStringSet(stringSet);
editor.commit()

The first time I execute the code above, stringSet is set to the default value (the just created and empty HashSet) and it is stored without problems.

The second and subsequent times I execute this code, a stringSet object is returned with the first element added. I can add the element and, during the program execution, it is apparently stored in the SharedPreferences. However, when the program is killed and the SharedPreferences is loaded again from persistent storage, the newer values are lost.

How can the second and subsequent elements be stored so that they don't get lost?

Duplex answered 25/12, 2012 at 23:51 Comment(2)
shouldn't the code be calling editor.putStringSet()?Chaker
@Chaker super old comment but I fixed that line since it seems the OP has abandoned it.Hertzfeld
D
182

This "problem" is documented on SharedPreferences.getStringSet.

The SharedPreferences.getStringSet returns a reference of the stored HashSet object inside the SharedPreferences. When you add elements to this object, they are added in fact inside the SharedPreferences.

That is ok, but the problem comes when you try to store it: Android compares the modified HashSet that you are trying to save using SharedPreferences.Editor.putStringSet with the current one stored on the SharedPreference, and both are the same object!!!

A possible solution is to make a copy of the Set<String> returned by the SharedPreferences object:

Set<String> s = new HashSet<String>(sharedPrefs.getStringSet("key", new HashSet<String>()));

That makes s a different object, and the strings added to s will not be added to the set stored inside the SharedPreferences.

Other workaround that will work is to use the same SharedPreferences.Editor transaction to store another simpler preference (like an integer or boolean), the only thing you need is to force that the stored value are different on each transaction (for example, you could store the string set size).

Duplex answered 25/12, 2012 at 23:51 Comment(4)
I already +1 but could you please provide a link to the source backing up your claim that : "Android compares the modified HashSet that you are trying to save using SharedPreferences.Editor.putStringSet with the current one stored on the SharedPreference"Curnin
The second option (save a counter) worked fine for me. Thanks!Hacienda
Spent 9 hours staring at my code on this one. Thanks a ton.Arthur
@Curnin and anyone interested I've added a source code explanation answer: https://mcmap.net/q/76014/-misbehavior-when-trying-to-store-a-string-set-using-sharedpreferencesHertzfeld
O
13

This behaviour is documented so it is by design:

from getStringSet:

"Note that you must not modify the set instance returned by this call. The consistency of the stored data is not guaranteed if you do, nor is your ability to modify the instance at all."

And it seems quite reasonable especially if it is documented in the API, otherwise this API would have to make copy on each access. So the reason for this design was probably performance. I suppose they should make this function return result wrapped in unmodifiable class instance, but this once again requires allocation.

Owen answered 26/12, 2012 at 8:7 Comment(1)
I edited my own answer this afternoon. I realized that it is properly documented, but when you are writing code many times you don't look to the documentation in things like that. This is the only reason to keep this ask+answer, IMHO, because it is a utility class and this kind of explanation can help anyone. Thanks for your clarification tooDuplex
D
7

Was searching for a solution for the same issue, resolved it by:

1) Retrieve the existing set from the shared preferences

2) Make a copy of it

3) Update the copy

4) Save the copy

SharedPreferences.Editor editor = sharedPrefs.edit();
Set<String> oldSet = sharedPrefs.getStringSet("key", new HashSet<String>());

//make a copy, update it and save it
Set<String> newStrSet = new HashSet<String>();    
newStrSet.add(new_element);
newStrSet.addAll(oldSet);

editor.putStringSet("key",newStrSet); edit.commit();

Why

Dinsdale answered 18/11, 2016 at 1:15 Comment(0)
H
6

Source Code Explanation

While the other good answers on here have correctly pointed out that this potential issue is documented in SharedPreferences.getStringSet(), basically "Don't modify the returned Set because the behavior isn't guaranteed", I'd like to actually contribute the source code that causes this problem/behavior for anyone that wants to dive deeper.

Taking a look at SharedPreferencesImpl (source code as of Android Pie) we can see that in SharedPreferencesImpl.commitToMemory() there is a comparison that occurs between the original value (a Set<String> in our case) and the newly modified value:

private MemoryCommitResult commitToMemory() {
    // ... other code

    // mModified is a Map of all the key/values added through the various put*() methods.
    for (Map.Entry<String, Object> e : mModified.entrySet()) {
        String k = e.getKey();
        Object v = e.getValue();
        // ... other code

        // mapToWriteToDisk is a copy of the in-memory Map of our SharedPreference file's
        // key/value pairs.
        if (mapToWriteToDisk.containsKey(k)) {
            Object existingValue = mapToWriteToDisk.get(k);
            if (existingValue != null && existingValue.equals(v)) {
                continue;
            }
        }
        mapToWriteToDisk.put(k, v);
    }

So basically what's happening here is that when you try to write your changes to file this code will loop through your modified/added key/value pairs and check if they already exist, and will only write them to file if they don't or are different from the existing value that was read into memory.

The key line to pay attention to here is if (existingValue != null && existingValue.equals(v)). You're new value will only be written to disk if existingValue is null (doesn't already exist) or if existingValue's contents are different from the new value's contents.

This the the crux of the issue. existingValue is read from memory. The SharedPreferences file that you are trying to modify is read into memory and stored as Map<String, Object> mMap; (later copied into mapToWriteToDisk each time you try to write to file). When you call getStringSet() you get back a Set from this in-memory Map. If you then add a value to this same Set instance, you are modifying the in-memory Map. Then when you call editor.putStringSet() and try to commit, commitToMemory() gets executed, and the comparison line tries to compare your newly modified value, v, to existingValue which is basically the same in-memory Set as the one you've just modified. The object instances are different, because the Sets have been copied in various places, but the contents are identical.

So you're trying to compare your new data to your old data, but you've already unintentionally updated your old data by directly modifying that Set instance. Thus your new data will not be written to file.

But why are the values stored initially but disappear after the app is killed?

As the OP stated, it seems as if the values are stored while you're testing the app, but then the new values disappear after you kill the app process and restart it. This is because while the app is running and you're adding values, you're still adding the values to the in-memory Set structure, and when you call getStringSet() you're getting back this same in-memory Set. All your values are there and it looks like it's working. But after you kill the app, this in-memory structure is destroyed along with all the new values since they were never written to file.

Solution

As others have stated, just avoid modifying the in-memory structure, because you're basically causing a side-effect. So when you call getStringSet() and want to reuse the contents as a starting point, just copy the contents into a different Set instance instead of directly modifying it: new HashSet<>(getPrefs().getStringSet()). Now when the comparison happens, the in-memory existingValue will actually be different from your modified value v.

Hertzfeld answered 12/6, 2019 at 1:14 Comment(1)
Basically it won't work because Set is a reference type and the implementation of SharedPreferences only compares the reference not the content. The reference won't change if you change the content.Organza
D
2

I tried all the above answers none worked for me. So I did the following steps

  1. before adding new element to the list of old shared pref, make a copy of it
  2. call a method with the above copy as a param to that method.
  3. inside that method clear the shared pref which are holding that values.
  4. add the values present in copy to the cleared shared preference it will treat it as new.

    public static void addCalcsToSharedPrefSet(Context ctx,Set<String> favoriteCalcList) {
    
    ctx.getSharedPreferences(FAV_PREFERENCES, 0).edit().clear().commit();
    
    SharedPreferences sharedpreferences = ctx.getSharedPreferences(FAV_PREFERENCES, Context.MODE_PRIVATE);
    SharedPreferences.Editor editor = sharedpreferences.edit();
    editor.putStringSet(FAV_CALC_NAME, favoriteCalcList);
    editor.apply(); }
    

I was facing issue with the values not being persistent, if i reopen the app after cleaning the app from background only first element added to the list was shown.

Desmarais answered 23/9, 2017 at 10:27 Comment(0)
A
1

Just as a note, Shared Preferences can't just be overwritten. If you have assigned a value to it, you have to remove it first by the method remove(KEY) and then commit() to destroy the key. Then you can assign a new value to it.

https://developer.android.com/reference/android/content/SharedPreferences.html#getStringSet(java.lang.String,%20java.util.Set%3Cjava.lang.String%3E)

Ahouh answered 24/6, 2021 at 5:34 Comment(0)

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