Get the last day of the current year as date

Question

How can I get the last day (Dec 31) of the current year as a date using PHP?

I tried the following but this doesn't work:

$year = date('Y');
$yearEnd =  strtotime($year . '-12-31');

What I need is a date that looks like 2014-12-31 for the current year.

Madelene

Answer 1

PHP strtotime() uses the current date/time as a basis (so it will use this current year), and you need date() to format:

$yearEnd = date('Y-m-d', strtotime('Dec 31'));

//or

$yearEnd = date('Y-m-d', strtotime('12/31'));

Martingale

Answer 2

You can just concatenate actual year with required date

$year = date('Y') . '-12-31';
echo $year;
//output 2014-12-31

Ellaelladine

... or even date('Y-12-31') – Olmsted

I'll go for the second option - thanks a lot for the quick help ! – Madelene

Answer 3

DateTime is perfectly capable of doing this:

$endOfYear = new \DateTime('last day of December this year');

You can even combine it with more modifiers to get the end of next year:

$endOfNextYear = new \DateTime('last day of December this year +1 years');

Biracial

How can i pass an year as a parameter and get the last day of the year ? – Monaxial

In that case simply pass the year $endOfYear = new \DateTime('last day of December 2019'); but bear in mind that this only works for years >1000 as for lower years you will get a 'Failed to parse time string' exception. – Biracial

Note that the string "last day of December this year" can be useful to use with the modify() function. – Fane

To get the last day of last year use "last day of december last year" – Farsighted

Answer 4

Another way to do this is use the Relative Formats of strtotime()

$yearEnd = date('Y-m-d', strtotime('last day of december this year'));

// or

$yearEnd = date('Y-m-d', strtotime('last day of december'));

Brandeebranden