Python dateutil parser fails

Question

I am attempting to parse the following date strings obtained from email headers:

from dateutil import parser
d1 = parser.parse('Tue, 28 Jun 2011 01:46:52 +0200')
d2 = parser.parse('Mon, 11 Jul 2011 10:01:56 +0200 (CEST)')
d3 = parser.parse('Wed, 13 Jul 2011 02:00:01 +0000 (GMT+00:00)')

The third one fails; am I missing something obvious?

Shumate

have you tried parser.parse('...', fuzzy=True)? – Maus

phimuemue, add that as an answer and I will accept it! – Shumate

eryksun, that is a good suggestion. – Shumate

Answer 1

have you tried parser.parse('...', fuzzy=True)? (I suppose it works :))

Maus

Yes it works. The problem is the extra "+00:00" after "GMT", as pointed out below. The "fuzzy" option ignores this. – Shumate

Answer 2

Give a try to parsedatetime library.

In [16]: import parsedatetime.parsedatetime as pdt

In [17]: p = pdt.Calendar()

In [18]: p.parse("Wed, 13 Jul 2011 02:00:01 +0000 (GMT+00:00)")
Out[18]: ((2011, 7, 20, 0, 0, 0, 2, 201, -1), 3)

Jaleesa

But is it correct? I have difficulty interpreting the tuple. Where is the "13", for example? – Shumate

It seems that this parser is confused and thinks the "Wed" refers to tomorrow July 20, which is the closest Wednesday. – Shumate

Looks like parsedatetime always takes future dates. it has a comment in the source code: # if that day and month have already passed in this year, then increment the year by 1 – Engram