Is it possible to make json4s not to throw exception when required field is missing?
Asked Answered
W

2

16

Is it possible to make json4s not to throw exception when required field is missing ?

When I "extract" object from raw json string it throws exception like this one

org.json4s.package$MappingException: No usable value for pager
No usable value for rpp
Did not find value which can be converted into byte
    at org.json4s.reflect.package$.fail(package.scala:98)
    at org.json4s.Extraction$ClassInstanceBuilder.org$json4s$Extraction$ClassInstanceBuilder$$buildCtorArg(Extraction.scala:388)
    at org.json4s.Extraction$ClassInstanceBuilder$$anonfun$11.apply(Extraction.scala:396)

Is it possible just to let it be null ?

Waldemar answered 11/4, 2013 at 8:23 Comment(0)
M
20

It's quite simple, you have to use Option and its potentials, Some and None.

val json = ("name" -> "joe") ~ ("age" -> Some(35));
val json = ("name" -> "joe") ~ ("age" -> (None: Option[Int]))

Beware though, in the above case a match will be performed for your Option. If it's None, it will be completely removed from the string, so it won't feed back null.

In the same pattern, to parse incomplete JSON, you use a case class with Option.

case class someModel(
    age: Option[Int],
    name: Option[String]
);
val json = ("name" -> "joe") ~ ("age" -> None);
parse(json).extract[someModel];

There is a method which won't throw any exception, and that is extractOpt

parse(json).extractOpt[someModel];

A way to replicate that with the scala API would be to use scala.util.Try:

Try { parse(json).extract[someModel] }.toOption
Manchu answered 11/4, 2013 at 8:54 Comment(0)
P
7

I've dealt with this problem when dealing with data migrations, and I wanted default values to fill undefined fields.

My solution was to merge the defaults into the JValue before extracting the result.

  val defaultsJson = Extraction.decompose(defaults)
  val valueJson = JsonUtil.jValue(v)
  (defaultsJson merge valueJson).extract[T]

JsonUtil.scala

  import org.json4s._

  object JsonUtil {
    import java.nio.charset.StandardCharsets.UTF_8
    import java.io.{InputStreamReader, ByteArrayInputStream}

    def jValue(json: String): JValue = {
      jValue(json.getBytes(UTF_8))
    }

    def jValue(json: Array[Byte]): JValue = {
      val reader = new InputStreamReader(new ByteArrayInputStream(json), UTF_8)
      native.JsonParser.parse(reader)
    }
  }
Pepperandsalt answered 22/9, 2014 at 21:26 Comment(0)

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