How i can delete whitespace in each line of file, using bash For instance, file1.txt. Before:
gg g
gg g
t ttt
after:
gg g
gg g
t ttt
How i can delete whitespace in each line of file, using bash For instance, file1.txt. Before:
gg g
gg g
t ttt
after:
gg g
gg g
t ttt
sed -i 's/ //g' your_file
will do it, modifying the file inplace.
To delete only the whitespaces at the beginning of one single line, use sed -i 's/^ *//' your_file
In the first expression, we replace all spaces with nothing.
In the second one, we replace at the beginning using the ^
keyword
s/^ *//
deletes leading whitespace if that's what you want ... but perhaps you should also edit your question then. –
Lillalillard /g
is redundant but harmless in that case, the regex already takes care of substituting all leading whitespace in one go. –
Lillalillard 's/^\s*//'
so it removes tabs, too? –
Trucking tr
(delete all whitespaces):$ tr -d ' ' <input.txt >output.txt
$ mv output.txt input.txt
sed
(delete leading whitespaces)$ sed -i 's/^ *//' input.txt
use can use perl -i for in place replacement.
perl -p -e 's/^ *//' file
perl -pi -e 's/^[\ \t]+|[\ \t]+$//g' [file]
does exactly what I needed. –
Absorbefacient To delete the white spaces before start of the line if the pattern matches. Use the following command. For example your foo.in has pattern like this
This is a test
Lolll
blaahhh
This is a testtt
After issuing following command
sed -e '/This/s/ *//' < foo.in > foo.out
The foo.out will be
This is a test
Lolll
blaahhh
This is a testtt
"Whitespace" can include both spaces AND tabs. The solutions presented to date will only match and operate successfully on spaces; they will fail if the whitespace takes the form of a tab.
The below has been tested on the OP's specimen data set with both spaces AND tabs, matching successfully & operating on both:
sed 's/^[[:blank:]]*//g' yourFile
After testing, supply the -i
switch to sed
to make the changes persistent-
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