PHP and MySQL: Order by most recent date and limit 10

Question

I am building a notes system on my site and I've got to the stage where users can post notes into the MySQL database using PHP and then PHP prints them out on a page. However, when they print/echo out, the oldest one appears first but I want the most recent first. I also want them to be limited to 10, so only 10 appear on the page. Here is my PHP code, your help will be much appreciated:

// initialize some variables
$notedisplaylist = "";
$myObject = "";
$result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY         date_time");

while($row = mysql_fetch_array($result)){
  $note_title = $row["note_title"];
  $note_body = $row["note_body"];
  $date = $row["date_time"];
  $notedisplaylist .= '<h2>' . $note_title . '</h2><br /><p>' . $note_body . '</p><hr /><p>Noted: ' . $date . '</p><hr /><br />';
}

Concenter

Answer 1

This should do it :

$result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 0, 10");

Paregoric

Answer 2

use:

SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 10

DESC : descending order ( from newest to oldest ) LIMIT 10: first 10 records found.

Nonanonage

Answer 3

Try

$result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 10");

For a more detailed explanation on ORDER and LIMIT, visit the MySQL doc's articles about sorting rows and the basic select syntax (look for a bullet describing LIMIT).

Berriman

Answer 4

give like

 ORDER BY date_time DESC

otherwise you are sorting them in ascending order.. thats why older ones come first

Cumbrous

Answer 5

Do this

$result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 0, 10");

Theodicy

Answer 6

If in case you want your LIMIT to be a variable, here I named it $limit:

"SELECT * FROM tbl ORDER BY input_date DESC LIMIT 0, $limit";

Orpah