The following section of my code gives me this messege when executing * glibc detected ./a.out: double free or corruption (fasttop): 0x08e065d0 **
i have gone through the code many times but i cant clealry see how i am misusing the free (temp2)
bool found= false;
int x=0;
for ( x=0; x<=312500; x++)
{
while (count <=32)
{
fscanf (file, "%d", &temp->num);
temp->ptr=NULL;
newNode = (NODE *)malloc(sizeof(NODE));
newNode->num=temp->num;
newNode->ptr=NULL;
if (first != NULL)
{
temp2=(NODE *)malloc(sizeof(NODE));
temp2=first;
while (temp2 != NULL && !found)
{
if (temp2->num == newNode->num)
{found=true;}
temp2= temp2->ptr;
}
free(temp2);
if (!found)
{
last->ptr=newNode;
last=newNode;
count=count+1;
}
}
else
{
first = newNode;
last = newNode;
count=count+1;
}
fflush(stdin);
}
temp2=(NODE *)malloc(sizeof(NODE)); temp2=first;
will at least leak memory. – Washbowl