How to build a simple RSS reader in Python 3.7?
Asked Answered
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3

17

I built a simple RSS reader on Python and it is not working. In addition, I want to get the featured image source link of every post and I didn't find a way to do so.

it shows me the Error: Traceback (most recent call last): File "RSS_reader.py", line 7, in feed_title = feed['feed']['title']

If there are some other RSS feeds that work fine. So I don't understand why there are some RSS feeds that are working and others that aren't

So I would like to understand why the code doesn't work and also how to get the featured image source link of a post I attached the code, is written on Python 3.7

import feedparser
import webbrowser

feed = feedparser.parse("https://finance.yahoo.com/rss/")

feed_title = feed['feed']['title']
feed_entries = feed.entries

for entry in feed.entries:

    article_title = entry.title
    article_link = entry.link
    article_published_at = entry.published # Unicode string
    article_published_at_parsed = entry.published_parsed # Time object
    article_author = entry.author
    content = entry.summary
    article_tags = entry.tags


    print ("{}[{}]".format(article_title, article_link))
    print ("Published at {}".format(article_published_at))
    print ("Published by {}".format(article_author))
    print("Content {}".format(content))
    print("catagory{}".format(article_tags))
Kenway answered 1/5, 2019 at 12:20 Comment(0)
A
12

A few things.

1) First feed['feed']['title'] does not exist.
2) At least for this site entry.author, entry.tags do not exist
3) It seems feedparser is not compatible with python3.7 (it gives me KeyError, "object doesn't have key 'category')

So as a starting point try to run the following code in python 3.6 and go from there.

import feedparser
import webbrowser

feed = feedparser.parse("https://finance.yahoo.com/rss/")

# feed_title = feed['feed']['title']  # NOT VALID
feed_entries = feed.entries

for entry in feed.entries:

    article_title = entry.title
    article_link = entry.link
    article_published_at = entry.published # Unicode string
    article_published_at_parsed = entry.published_parsed # Time object
    # article_author = entry.author  DOES NOT EXIST
    content = entry.summary
    # article_tags = entry.tags  DOES NOT EXIST


    print ("{}[{}]".format(article_title, article_link))
    print ("Published at {}".format(article_published_at))
    # print ("Published by {}".format(article_author)) 
    print("Content {}".format(content))
    # print("catagory{}".format(article_tags))

Good luck.

Amimia answered 3/5, 2019 at 1:7 Comment(1)
Can anyone confirm that whether feedparser is supported for now? It says it requires Python >= 3.6 at the moment.Oralee
C
7

You can also use xml parser libraries like beatifulsoup (https://www.crummy.com/software/BeautifulSoup/bs4/doc/) and create custom parsers. A sample customer parser code can be found here (https://github.com/vintageplayer/RSS-Parser). A walk through the same can read here (https://towardsdatascience.com/rss-feed-parser-in-python-553b1857055c)

Though libraries can be useful, beautifulsoup is an extremely handy library to try out.

Coleoptile answered 24/11, 2019 at 18:27 Comment(0)
R
2

I have used BeautifulSoup for a beginner RSS feed reader project (You need to install lxml for it to work since we are dealing with xml):

from bs4 import BeautifulSoup
import requests
url = requests.get('https://realpython.com/atom.xml')

soup = BeautifulSoup(url.content, 'xml')
entries = soup.find_all('entry')

for i in entries:
  title = i.title.text
  link = i.link['href']
  summary = i.summary.text
  print(f'Title: {title}\n\nSummary: {summary}\n\nLink: {link}\n\n------------------------\n') 

You can find the Youtube video here: https://www.youtube.com/watch?v=8HbqO-TfjlI

Rosenfeld answered 30/6, 2021 at 8:54 Comment(0)

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