I'd like to use sed to remove tabs from otherwise blank lines. For example a line containing only \t\n
should change to \n
. What's the syntax for this?
sed
does not know about escape sequences like \t
. So you will have to literally type a tab
on your console:
sed 's/^ *$//g' <filename>
If you are on bash, then you can't type tab
on the console. You will have to do ^V
and then press tab
. (Ctrl-V
and then tab
) to print a literal tab.
The other posted solution will work when there is 1 (and only 1) tab in the line. Note that Raze2dust points out that sed requires you to type a literal tab. An alternative is:
sed '/[^ ]/!s/ //g' file-name.txt
Which substitues away tabs from lines that only have tabs. The inverted class matches lines that contain anything bug a tab - the following '!' causes it to not match those lines - meaning only lines that have only tabs. The substitution then only runs on those lines, removing all tabs.
To replace arbitrary whitespace lines with an empty line, use
sed -r 's/^\s+$//'
The -r flag says to use extended regular expressions, and the ^\s+$ pattern matches all lines with some whitespace but no other characters.
What worked for me was:
sed -r '/^\s+$/d' my_file.txt > output.txt
I've noticed \t is not recognized by UNIX. Being said, use the actual key. In the code below, TAB represents pressing the tab key.
$ sed 's/TAB//g' oldfile > newfile
Friendly tip: to ensure you have tabs in the file you are trying to remove tabs from use the following code to see if \t appears
$ od -c filename
grep -o ".*" file > a; mv a file;
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sed $'s/^\t*$//g'
, because using a dollar-sign on a single-quoted string formats escape codes such as \t. – Mireyamiriam