I have a Spring Boot application that uses Spring Security and Thymeleaf template. I am trying to display the logged-in user's first name and last name in a template when the controller is managed by a subclass of WebConfigurerAdapter.
So, say my WebConfigurerAdapter subclass looks like this
@Configuration
public class MvcConfig extends WebMvcConfigurerAdapter{
@Override
public void addViewControllers(ViewControllerRegistry registry){
registry.addViewController("/some-logged-in-page").setViewName("some-logged-in-page");
registry.addViewController("/login").setViewName("login");
}
....
}
My User entity class looks like this
@Entity
@Table(name = "user")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id", nullable = false, updatable = false)
private Long id;
@Column(name="first_name", nullable = false)
private String firstName;
public String getFirstName() {
return firstName;
}
...
}
In my template, I have tried using code like
<div sec:authentication="firstName"></div>
But it didn't work.
I know it is possible to use a ControllerAdvise as follows:
@ControllerAdvice
public class CurrentUserControllerAdvice {
@ModelAttribute("currentUser")
public UserDetails getCurrentUser(Authentication authentication) {
return (authentication == null) ? null : (UserDetails) authentication.getPrincipal();
}
}
and then access the details in the template using code like:
<span th:text ="${currentUser.getUser().getFirstName()}"></span>
But this doesn't work with any view controller registered with my class MvcConfig. Rather I will need to make sure each of my controllers are separate classes.
So, could someone kindly point me to a way to automatically insert the logged-in user details to my view, e.g. some-logged-in-page.html in this example? Thanks
