indexOf in a string array

Question

Is there anyway to get indexOf like you would get in a string.

output.add("1 2 3 4 5 6 7 8 9 10);  
String bigger[] = output.get(i).split(" ");
int biggerWher = bigger.indexOf("10");

I wrote this code but its returning an error and not compiling! Any advice ?

Thermo

Hope you have specific programming language? – Gnotobiotics

Looks like Java to me... – Gerrit

possible duplicate of Where is Java's Array indexOf? – Toinette

Answer 1

Use this ...

output.add("1 2 3 4 5 6 7 8 9 10");  
String bigger[] = output.get(i).split(" ");
int biggerWher = Arrays.asList(bigger).indexOf("3");

Selvage

What are the collateral effects by using asList? Is made a copy of original array on memory? – Submission

@Richard: It will create a new ArrayList object and converts from the String array, I'd guess 3-5 times the amount of memory than before. public static <T> List<T> asList(T... array) { return new ArrayList<T>(array); } – Guildroy

Answer 2

When the array is an array of objects, then:

Object[] array = ..
Arrays.asList(array).indexOf(someObj);

Another alternative is org.apache.commons.lang.ArrayUtils.indexOf(...) which also has overloads for arrays of primitive types, as well as a 3 argument version that takes a starting offset. (The Apache version should be more efficient because they don't entail creating a temporary List instance.)

Toinette

Why do I keep forgetting that most collection-methods apply to arrays too by using asList.... +1 – Gerrit

What are the collateral effects by using asList? Is made a copy of original array on memory? – Submission

@Richard - No copy is made. The 'asList' List is a wrapper for the original array. Read the javadocs!! – Toinette

Answer 3

Arrays do not have an indexOf() method; however, java.util.List does. So you can wrap your array in a list and use the List methods (except for add() and the like):

output.add("1 2 3 4 5 6 7 8 9 10");  
String bigger[] = output.get(i).split(" ");
int biggerWhere = Arrays.asList(bigger).indexOf("10");

Nonintervention

Answer 4

You can use java.util.Arrays.binarySearch(array, item); That will give you an index of the item, if any...

Please note, however, that the array needs to be sorted before searching.

Regards

Blackcap

Answer 5

There is no direct indexOf method in Java arrays.

Bolen

Answer 6

output.add("1 2 3 4 5 6 7 8 9 10");

you miss a " after 10.

Aphaeresis