Link to Instagram profile with user ID

Question

I want to link to a profile/user account on Instagram. I have the user ID, but the I can't find the answer in the developer API documentation. I've tried instagram.com/userID and instagram.com/users/userID but these aren't working. Simple question: I have just a single <a> tag and I want to know what goes in the href to take the user to a specific instagram profile. Or possibly a window.location in javascript.

Or if there's a way to get the username from the ID, I suppose I could also do it in that round-a-bout way...

Oldtime

Do you need any more help with your question or did one of the answers already help you solve it. If so, please remember to accept it. Otherwise I'll try to help. – Raincoat

@TimBodeit The answers did not help. I ended up using the user name instead of ID. – Oldtime

Yes there is a quick way. Answered in here – Elmiraelmo

#59526637 – Tallulah

Answer 1

I am not aware of a solution, that makes it work as a simple link.

You will need to use the Instagram API and sign up your application so that you have a Client-ID.

Next, you will need to do the following request as HTTP GET:

https://api.instagram.com/v1/users/userID?client_id=YourClientID

This will return a JSON-Result, which will contain the username inside the data section.

Now you can use http://instagram.com/username as your link.

Raincoat

For redirecting to the IG user's webpage, the https://instagram.com/username seems to work well nowadays... – Subspecies

Answer 2

try

async function insta(uid) {
  let api = `https://i.instagram.com/api/v1/users/${uid}/info/`
  let info = await (await fetch(api)).json();
  return `https://www.instagram.com/${info.user.username}`;
}

async function go() {
  let url = await insta(userId.value);
  link.innerText = url;
}

Type instagram user id:
<input id="userId" value=182805585 />
<button onclick="go()">Find username</button><br>
<pre id="link"></pre>

UPDATE

According this starting form 03.12.2019 above solution stops works and returns only

{“message”: “useragent mismatch”, “status”: “fail”}

instead you can try to send request GET

https://i.instagram.com/api/v1/users/1791879548/info/

with following user-agent header:

Mozilla/5.0 (iPhone; CPU iPhone OS 12_3_1 like Mac OS X) AppleWebKit/605.1.15 (KHTML, like Gecko) Mobile/15E148 Instagram 105.0.0.11.118 (iPhone11,8; iOS 12_3_1; en_US; en-US; scale=2.00; 828x1792; 165586599)

Heartburning

Answer 3

1st Method

<a href="http://instagram.com/_u/{USERNAME}/">Link to Instagram Page</a>

• Ask user to select application to launch with

---

2nd Method

<a href="instagram://user?username={USERNAME}">Link to Instagram Profile</a>

• If user installed instagram application : Directly launch page with native application
• If user not installed instagram application : Do nothing

---

Tested on Android 4.4 Chrome

Inaptitude

instagram://user?id={user_id} confirmed to work on iOS – Lathrope

does not answer OP's question : link the profile with only user ID – Lawrence

Answer 4

https://www.instagram.com/p/" . $social_id . "/"

Exemplary

Answer 5

async function insta(uid) {
  let api = `https://i.instagram.com/api/v1/users/${uid}/info/`
  let info = await (await fetch(api)).json();
  return `https://www.instagram.com/${info.user.username}`;
}

async function go() {
  let url = await insta(userId.value);
  link.innerText = url;
}

Type instagram user id:
<input id="userId" value=182805585 />
<button onclick="go()">Find username</button><br>
<pre id="link"></pre>

Jerkin

Answer 6

async function insta(uid) {
  let api = `https://i.instagram.com/api/v1/users/${uid}/info/`
  let info = await (await fetch(api)).json();
  return `https://www.instagram.com/${info.user.username}`;
}

async function go() {
  let url = await insta(userId.value);
  link.innerText = url;
}

Type instagram user id:
<input id="userId" value=182805585 />
<button onclick="go()">Find username</button><br>
<pre id="link"></pre>

---

arifa_a235668

Duleba

As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center. – Cotquean

Answer 7

async function insta(uid) {
  let api = `https://https://instagram.com/priyasharma_officle?igshid=MzRlODBiNWFlZA==

> *

Blockquote

*

/api/v1/users/${uid}/info/`
  let info = await (await fetch(api)).json();
  return `https://www.instagram.com/${info.user.username}`;
}

async function go() {
  let url = await insta(userId.value);
  link.innerText = url;
}

Type instagram user id:
<input id="userId" value=https://instagram.com/priyasharma_officle?igshid=MzRlODBiNWFlZA==/>
<button onclick="go()">Find username</priyasharma_officle><br>
<pre id="link"></pre>

Brouwer

Your answer could be improved with additional supporting information. Please edit to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers in the help center. – Cotquean

Answer 8

You can also use this: https://instagram.com/user/?id={USER_ID}

Mascle

no, this just link to the funny guy who chose username "user", you can try any id you would like, still the same – Lawrence