jqgrid: multiselect and disable check (conditional)
Asked Answered
S

5

18


I love jqGrid but sometimes things seem more complicated than they should be.
What I would like to achieve is to have a checkbox on each row so that a user can choose which rows are going to be submitted/processed.
I need, though, to block some checkboxes cause the user has no authorization on that particular row, maybe.

I've tried to set multiselect: true and then I've tried to hide the checkbox:

loadComplete: function (data) {
    if (data.rows.length > 0) {
        for (var i = 0; i < data.rows.length; i++) {
            if (data.rows[i].cell[7] == 'false') {
                $("#jqg_OrdersGrid_" + data.rows[i].id).css("visibility", "hidden");
            }
        }
    }
},

and it works well but, still, .jqGrid('getGridParam', 'selarrrow') give me the selected rows, even if they haven't been checked.
Is there any other way to have checkboxes which are enabled/disabled and a way to know which ones have been checked?

thanks

Swerve answered 10/3, 2011 at 11:53 Comment(0)
T
31

I would suggest you to disable some checkboxed from the be selectable with respect of "disabled" attribute. To make full implementation you will need

  1. set "disabled" inside of loadComplete event handle
  2. additionally prevent selection of disabled rows inside beforeSelectRow event handle
  3. to have support of "select all" checkbox in the header of the multiselect column implement onSelectAll event handle which fix selection of disabled rows.

The corresponding demo can you see here. The most important part of the code is here:

var grid = $("#list10"), i;
grid.jqGrid({
    //...
    loadComplete: function() {
        // we make all even rows "protected", so that will be not selectable
        var cbs = $("tr.jqgrow > td > input.cbox:even", grid[0]);
        cbs.attr("disabled", "disabled");
    },
    beforeSelectRow: function(rowid, e) {
        var cbsdis = $("tr#"+rowid+".jqgrow > td > input.cbox:disabled", grid[0]);
        if (cbsdis.length === 0) {
            return true;    // allow select the row
        } else {
            return false;   // not allow select the row
        }
    },
    onSelectAll: function(aRowids,status) {
        if (status) {
            // uncheck "protected" rows
            var cbs = $("tr.jqgrow > td > input.cbox:disabled", grid[0]);
            cbs.removeAttr("checked");

            //modify the selarrrow parameter
            grid[0].p.selarrrow = grid.find("tr.jqgrow:has(td > input.cbox:checked)")
                .map(function() { return this.id; }) // convert to set of ids
                .get(); // convert to instance of Array
        }
    }
);

UPDATED: Free jqGrid supports hasMultiselectCheckBox callback, which can be used to create multiselect checkboxes not for all rows of jqGrid. One can use rowattr to disable some rows additionally. As the result one will get the described above functionality in more simple way. It's recommended to use multiPageSelection: true option additionally for free jqGrid with local data (datatype: "local" or loadonce: true). The option multiPageSelection: true will hold the array selarrrow on paging. It allows "pre-select" some rows by filling the corresponding ids inselarrrow. See UPDATED part of the answer and the answer with the demo for additional information.

Thornberry answered 10/3, 2011 at 14:14 Comment(15)
Thanks Oleg. Always professional in your answers ;-) I love the fact that your code is completed with custom examples. Actually, I still would like to be able to select the row cause for me the fact the row is checked has nothing to do with the selection. I've find a work-around.I'll show you some code.Swerve
I've replied to my question but I won't accept it. It's not fair. Try to see what you think and they I'll accept yours.Swerve
@LeftyX: You code looks OK. Any kind of optimizations could be not needed if in your grids will be a few rows.Thornberry
For me, onSelectAll still seems to select the row (even w/ the beforeSelectRow), though beforeSelectRow does seem to prevent the row from being selected on click.Encamp
@RonGarrity: In which web browser you test the demo and be able select disabled rows?Thornberry
@Thornberry Can you tell I'm working on grids again Dr.? Thank you!Aegis
@StephenPatten: You are welcome! Sorry, but I didn't understand your question.Thornberry
@Thornberry I have no new questions yet :) I'm finding that you've answered everything so far. Take care Dr.Aegis
@Thornberry Once again you have helped me greatly :)Rucksack
My version of jQGrid also required me to add cbs.closest('tr').removeClass('ui-state-highlight'); to the onSelectAll function.Dodds
@Dodds @RonGarrity I have implemented what I consider a little cleaner version of the onAllSelect function. See jsfiddle.net/ndnckw1tRoderick
@Ben: Sorry, but the answer is very old. jqGrid have now many other features and I know JavaScript much better as 4 years before. Moreover there are many reasons why the rows could be "protected". In many cases one it would be just god to disable the whole rows of the grid. One can do this by adding rowattr which set ui-state-disabled class and setting pointer-events: none; additionally. See jsfiddle.net/OlegKi/aagxejj5/42 created for the answer. I'm not sure which scenario use you, but probably it could help.Thornberry
@Thornberry Awesome. Thanks! I'll use the other answer as a reference to improve the next time I do this task.Roderick
Worked for me but i have to add cbs.parent().parent().removeClass("ui-state-highlight"); to un-highlight the rows.Steato
@Dot_NETPro: Please write always which fork and version of jqGrid you use. The answer is written 8 years ago and worked for current version of jqGrid at the time. Later introduced features can required to adjust the old code. For example, if one uses idPrefix option, introduced later, then $("tr#"+rowid+... from beforeSelectRow will not work. One have to add idPrefix. If you use free jqGrid then you should use hasMultiselectCheckBox which will prevent creating unneeded checkboxes instead of making DOM modification every time.Thornberry
R
5

Great answer from Oleg, I would also add code to deselect disabled rows, complete onSelectAll function below.

onSelectAll: function(aRowids,status) {
    if (status) {
        // uncheck "protected" rows
        var cbs = $("tr.jqgrow > td > input.cbox:disabled", grid[0]);
        cbs.removeAttr("checked");

        //modify the selarrrow parameter
        grid[0].p.selarrrow = grid.find("tr.jqgrow:has(td > input.cbox:checked)")
            .map(function() { return this.id; }) // convert to set of ids
            .get(); // convert to instance of Array

        //deselect disabled rows
        grid.find("tr.jqgrow:has(td > input.cbox:disabled)")
            .attr('aria-selected', 'false')
            .removeClass('ui-state-highlight');
    }
}
Rheology answered 24/10, 2014 at 15:54 Comment(0)
S
3

I've found a work-around. During the loadComplete event I disable the SelectAll checkbox: I don't need it. I also hide the checkbox and disable it.

loadComplete: function (data) {
    $("#cb_OrdersGrid").css("visibility", "hidden");
    if (data.rows.length > 0) {
        for (var i = 0; i < data.rows.length; i++) {
            if (data.rows[i].cell[7] == 'false') {
                $("#jqg_OrdersGrid_" + data.rows[i].id).css("visibility", "hidden");
                $("#jqg_OrdersGrid_" + data.rows[i].id).attr("disabled", true);
            }
        }
    }
}

Now, when I want to submit my data I loop through the selected rows and check if they've been disabled and put those which are enabled in a new array.

var selectedRows = myGrid.jqGrid('getGridParam', 'selarrrow');
var checkedRows = [];
var selectionLoop = 0;
for (var x = 0; x < selectedRows.length; x++) {
    var isDisabled = $('#jqg_OrdersGrid_' + selectedRows[x]).is(':disabled');
    if (!isDisabled) {
        checkedRows[selectionLoop] = selectedRows[x];
        selectionLoop++;
    }
}

What I've achieved now is to be able to select a row conditionally being able to check it or not.
I know the code is not optimized (forgive me Oleg) but I'll do it later.

Swerve answered 10/3, 2011 at 14:33 Comment(0)
O
3

For people (like me) that end up on this answer after searching on Google, there is a very easy solution to this problem since jqGrid 4.0.0.

It's enough to add the css-class 'ui-state-disabled' to the row that you don't want to be selected. See The changelog of jqGrid 4.0.0. And you could still combine that with hiding or disabling the checkbox.

    var $jqgrid = $("#jqgridselector");         
    //loop through all rows
    $(".jqgrow", $jqgrid).each(function (index, row) {
        var $row = $(row);
        if ($row === condition) {
            //Find the checkbox of the row and set it disabled
            $row.find("input:checkbox").attr("disabled", "disabled");
            //add class ui-state-disabled, because thats how jqGrid knows not to take them into account for selection
            $row.addClass("ui-state-disabled");
            //I overwrite the opactity of the ui-state-disabled class to make the row look 'normal'
            $row.css("opacity", 1);
            }
        });
Observant answered 19/1, 2015 at 11:44 Comment(0)
T
2

I'm using jqGrid 4.4.4 and I had to tweak LetfyX loadComplete just a little.

            loadComplete: function(data) {
                for (var i = 0; i < data.rows.length; i++) {
                    var rowData = data.rows[i];
                    if (rowData.cell[6] != null) {//update this to have your own check
                        var checkbox = $("#jqg_list_" + rowData.i);//update this with your own grid name
                        checkbox.css("visibility", "hidden");
                        checkbox.attr("disabled", true);
                    }
                }
            }
Trautman answered 4/3, 2013 at 18:51 Comment(0)

© 2022 - 2024 — McMap. All rights reserved.