EDIT: Removed all code and references to UIButton
.
Thanks to @Matteo_Pacini for his answer to this question for showing us this technique. As with his answer (and comment), (1) this is rough around the edges and (2) I'm not sure this is how Apple wants us to use UIViewControllerRepresentable
and I really hope they provide a better SwiftUI
("SwiftierUI"?) replacement in a future beta.
I put in a lot of work in UIKit
because I want this to look good on an iPad, where a sourceView
is needed for the popover. The real trick is to display a (SwiftUI) View
that gets the UIActivityViewController
in the view hierarchy and trigger present
from UIKit
.
My needs were to present a single image to share, so things are targeted in that direction. Let's say you have an image, stored as a @State
variable - in my example the image is called vermont.jpg and yes, things are hard-coded for that.
First, create a UIKit
class of type `UIViewController to present the share popover:
class ActivityViewController : UIViewController {
var uiImage:UIImage!
@objc func shareImage() {
let vc = UIActivityViewController(activityItems: [uiImage!], applicationActivities: [])
vc.excludedActivityTypes = [
UIActivity.ActivityType.postToWeibo,
UIActivity.ActivityType.assignToContact,
UIActivity.ActivityType.addToReadingList,
UIActivity.ActivityType.postToVimeo,
UIActivity.ActivityType.postToTencentWeibo
]
present(vc,
animated: true,
completion: nil)
vc.popoverPresentationController?.sourceView = self.view
}
}
The main things are;
- You need a "wrapper"
UIViewController
to be able to present
things.
- You need
var uiImage:UIImage!
to set the activityItems
.
Next up, wrap this into a UIViewControllerRepresentable
:
struct SwiftUIActivityViewController : UIViewControllerRepresentable {
let activityViewController = ActivityViewController()
func makeUIViewController(context: Context) -> ActivityViewController {
activityViewController
}
func updateUIViewController(_ uiViewController: ActivityViewController, context: Context) {
//
}
func shareImage(uiImage: UIImage) {
activityViewController.uiImage = uiImage
activityViewController.shareImage()
}
}
The only two things of note are:
- Instantiating
ActivityViewController
to return it up to ContentView
- Creating
shareImage(uiImage:UIImage
) to call it.
Finally, you have ContentView
:
struct ContentView : View {
let activityViewController = SwiftUIActivityViewController()
@State var uiImage = UIImage(named: "vermont.jpg")
var body: some View {
VStack {
Button(action: {
self.activityViewController.shareImage(uiImage: self.uiImage!)
}) {
ZStack {
Image(systemName:"square.and.arrow.up").renderingMode(.original).font(Font.title.weight(.regular))
activityViewController
}
}.frame(width: 60, height: 60).border(Color.black, width: 2, cornerRadius: 2)
Divider()
Image(uiImage: uiImage!)
}
}
}
Note that there's some hard-coding and (ugh) force-unwrapping of uiImage
, along with an unnecessary use of @State
. These are there because I plan to use `UIImagePickerController next to tie this all together.
The things of note here:
- Instantiating
SwiftUIActivityViewController
, and using shareImage
as the Button action.
- Using it to also be button display. Don't forget, even a
UIViewControllerRepresentable
is really just considered a SwiftUI View
!
Change the name of the image to one you have in your project, and this should work. You'll get a centered 60x60 button with the image below it.
UIImagePickerController
#56516371 that I have working and want to integrate into my app first. Take a look at that answer - particularlyContentView
- and see f that can work for you. My concern is with getting an iPad "popover" instead of a full screen modal. I'll post my code if I get things working in the next day or two. – KarriekarryUIViewControllerRepresentable
. My only issue i that it requires aView
- I'm getting console warnings about presenting a view not in the view hierarchy. I think I should clear that up by using aCoordinator
. I'll post some code later today. – Karriekarry