What does a lock statement do under the hood?
Asked Answered
I

9

647

I see that for using objects which are not thread safe we wrap the code with a lock like this:

private static readonly Object obj = new Object();

lock (obj)
{
    // thread unsafe code
}

So, what happens when multiple threads access the same code (let's assume that it is running in a ASP.NET web application). Are they queued? If so how long will they wait?

What is the performance impact because of using locks?

Illassorted answered 17/5, 2011 at 10:55 Comment(1)
^ dead link, see: jonskeet.uk/csharp/threads/index.htmlSynonymy
K
536

The lock statement is translated by C# 3.0 to the following:

var temp = obj;

Monitor.Enter(temp);

try
{
    // body
}
finally
{
    Monitor.Exit(temp);
}

In C# 4.0 this has changed and it is now generated as follows:

bool lockWasTaken = false;
var temp = obj;
try
{
    Monitor.Enter(temp, ref lockWasTaken);
    // body
}
finally
{
    if (lockWasTaken)
    {
        Monitor.Exit(temp); 
    }
}

You can find more info about what Monitor.Enter does here. To quote MSDN:

Use Enter to acquire the Monitor on the object passed as the parameter. If another thread has executed an Enter on the object but has not yet executed the corresponding Exit, the current thread will block until the other thread releases the object. It is legal for the same thread to invoke Enter more than once without it blocking; however, an equal number of Exit calls must be invoked before other threads waiting on the object will unblock.

The Monitor.Enter method will wait infinitely; it will not time out.

Kasher answered 17/5, 2011 at 10:57 Comment(7)
According to MSDN "Using the lock (C#) or SyncLock (Visual Basic) keyword is generally preferred over using the Monitor class directly, both because lock or SyncLock is more concise, and because lock or SyncLock insures that the underlying monitor is released, even if the protected code throws an exception. This is accomplished with the finally keyword, which executes its associated code block regardless of whether an exception is thrown." msdn.microsoft.com/en-us/library/ms173179.aspxTripartite
What's the point of the var temp = obj; line. since it's just a ref to begin with, what good does making another one do?Amnesia
@Amnesia It allows the user to change obj without the whole system to deadlock.Kasher
Just another syntactic sugar?Reviere
@Joymon eventually, every language feature is syntactic sugar. Language features are about about making developers more productive and making applications more maintainable, as is the lock feature as well.Kasher
Does this mean that if you use the same "object" for the lock in different methods, no matter what method a thread hits, if there is another thread executing another method with the same "object" used in the lock, the thread has to wait until the "object" is released? I appreciate your time.Kinghood
Correct. This is the entire purpose of the lock-statement and Monitor: so that you can perform an operation in one thread without having to worry about another thread mucking it up.Shoelace
P
349

Its simpler than you think-

According to Microsoft: The lock keyword ensures that one thread does not enter a critical section of code while another thread is in the critical section. If another thread tries to enter a locked code, it will wait, block, until the object is released.

The lock keyword calls Enter at the start of the block and Exit at the end of the block. lock keyword actually handles Monitor class at back end.

For example:

private static readonly Object obj = new Object();

lock (obj)
{
    // critical section
}

In the above code, first the thread enters a critical section, and then it will lock obj. When another thread tries to enter, it will also try to lock obj, which is already locked by the first thread. Second thread will have to wait for the first thread to release obj. When the first thread leaves, then another thread will lock obj and will enter the critical section.

Pantoja answered 10/4, 2014 at 9:54 Comment(5)
should we create a dummy object to lock or can we lock an existing variable in the context?Imre
@batmaci - Locking on a separate private dummy object gives you a guarantee that no one else is locking in that object. If you lock on the data and that same piece of data is visible to the outside you lose that guarantee.Pantoja
What happens if more than one process is waiting for the lock to release? Are the waiting processes queued so that they will be lock the critical section in FIFO order?Ahearn
@Ahearn - They are queued, but the order is not guaranteed to be FIFO. Check out this link: albahari.com/threading/part2.aspxPantoja
Copied without attribution from net-informations.com/faq/qk/lock.htmPawl
B
58

No, they are not queued, they are sleeping

A lock statement of the form

lock (x) ... 

where x is an expression of a reference-type, is precisely equivalent to

var temp = x;
System.Threading.Monitor.Enter(temp); 
try { ... } 
finally { System.Threading.Monitor.Exit(temp); }

You just need to know that they are waiting to each other, and only one thread will enter to lock block, the others will wait...

Monitor is written fully in .net so it is enough fast, also look at class Monitor with reflector for more details

Bead answered 17/5, 2011 at 10:56 Comment(7)
Note that the code emitted for the lock statement changed slightly in C#4: blogs.msdn.com/b/ericlippert/archive/2009/03/06/…Spoliate
@ArsenMkrt, they are not kept in "Blocked" state "Queue?. I think there are some difference between Sleep and block state, is not it?Jorgenson
what difference you mean @Mohanavel?Bead
What happens if more than one process is waiting for the lock to release? Are the waiting processes queued so that they will be lock the critical section in FIFO order?Ahearn
@jstuardo, lock or monitor is not visible outside of process... it make sense only for threads in the single process... for processes Mutex, Semaphore or other Windows Core objects can be used...Bead
That was not the question. The question was regarding "lock" keyword. Suppose a process enter a "lock" section. That means that process blocks that piece of code and no other process may be able to enter that section until that lock is released. Well.... now, 2 more processes try to enter the same block. Since it is protected by "lock" keyword, they will wait, according to what was said in this forum. When the first process releases the lock. What process enters the block? the first one that tried to enter or the last one?Ahearn
I guess you mean thread instead of process... if so, than the answer is No, there is no guarantee which one will enter... more here #4229364Bead
Z
38

Locks will block other threads from executing the code contained in the lock block. The threads will have to wait until the thread inside the lock block has completed and the lock is released. This does have a negative impact on performance in a multithreaded environment. If you do need to do this you should make sure the code within the lock block can process very quickly. You should try to avoid expensive activities like accessing a database etc.

Zonation answered 17/5, 2011 at 11:1 Comment(0)
K
13

The performance impact depends on the way you lock. You can find a good list of optimizations here: http://www.thinkingparallel.com/2007/07/31/10-ways-to-reduce-lock-contention-in-threaded-programs/

Basically you should try to lock as little as possible, since it puts your waiting code to sleep. If you have some heavy calculations or long lasting code (e.g. file upload) in a lock it results in a huge performance loss.

Kesha answered 17/5, 2011 at 11:8 Comment(3)
But trying to write low-lock code can often result in subtle, hard-to-find-and-fix bugs, even if you're an expert in the field. Using a lock is often the lesser of two evils. You should lock exactly as much as you need to, no more, no less!Spoliate
@LukeH: There are some usage patterns where low-lock code can be very simple and easy [do { oldValue = thing; newValue = updated(oldValue); } while (CompareExchange(ref thing, newValue, oldValue) != oldValue]. The biggest danger is that if the requirements evolve beyond what such techniques can be handle, it may be hard to adapt the code to handle that.Fluorometer
Link has broken.Adamant
P
10

The part within the lock statement can only be executed by one thread, so all other threads will wait indefinitely for it the thread holding the lock to finish. This can result in a so-called deadlock.

Proverb answered 17/5, 2011 at 10:58 Comment(0)
A
9

The lock statement is translated to calls to the Enter and Exit methods of Monitor.

The lock statement will wait indefinitely for the locking object to be released.

Abc answered 17/5, 2011 at 10:59 Comment(0)
B
4

lock is actually hidden Monitor class.

Bugle answered 17/5, 2011 at 10:58 Comment(0)
Z
1

According to Microsoft's MSDN, the lock is equivalent to:

object __lockObj = x;
bool __lockWasTaken = false;
try
{
    System.Threading.Monitor.Enter(__lockObj, ref __lockWasTaken);
    // Your code...
}
finally
{
    if (__lockWasTaken) System.Threading.Monitor.Exit(__lockObj);
}

If you need to create locks in runtime, you can use open source DynaLock. You can create new locks in run-time and specify boundaries to the locks with context concept.

DynaLock is open-source and source code is available at GitHub

Zielinski answered 3/9, 2020 at 21:26 Comment(0)

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