How can I take a list of server names and append a resource URI and port to each?
Asked Answered
E

3

19

I merged two lists from an Ansible inventory:

set_fact:
  fact1: "{{ groups['group1'] + groups[group2']|list }}

The output is:

fact1:
  - server01
  - server02
  - server03

With the above results, I need to append https:// to the front, and a port number to the back of each element. Then I need to convert it to a comma delimited list for a server config.

In this example I want: https://server01:8000,https://server02:8000,https://server03:8000.

I tried using a join:

set_fact:
  fact2: "{{ fact1|join(':8000,') }}"

which partly worked but it left the last server without a port.

How can I achieve my goal?

Electroencephalograph answered 1/11, 2017 at 3:40 Comment(0)
Y
31

Solution

set_fact:
  fact2: "{{ fact1 | map('regex_replace', '(.*)', 'https://\\1:8000') | join(',') }}"

Explanation

  1. map filter applies a filter (regex_replace) to individual elements of the list;

  2. regex_replace filter (with the following regular expression) adds a prefix and suffix to a string;

    current_list | map('regex_replace', '(.*)', 'prefix\\1suffix')
    
  3. join filter converts the list to comma-delimited string in the output.


Alternative

Another possible solution (builds on what you already know) would be to use Jinja2 to directly for the target string:

set_fact:
  fact2: "{{ 'https://' + fact1|join(':8000,https://') + ':8000' }}"
Yucca answered 1/11, 2017 at 4:7 Comment(2)
Beware that on some Python versions, (.*)will match the whole string and an empty string at the end, which means it will make two replacements: docs.ansible.com/ansible/latest/user_guide/…. We should use ^(.*)$ instead.Fletafletch
Excuse me, but shouldn't that be \1 instead of \\1 there?Stogy
S
5

Also you can use ternary filter:

set_fact:
  fact2: "{% for it in fact1 %}https://{{ it }}:8000{{ loop.last | ternary('', ',') }}{% endfor %}"
Scolex answered 9/11, 2018 at 6:27 Comment(0)
L
0

i have this list of inventory i want to do like this ['servers'] server01 server02 server03 server04 in this example I want: https://server01:8000;https://server02:8000],https://server03:8000;https://server04:8000]

Lacylad answered 21/10, 2022 at 10:5 Comment(0)

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