Here is an XSD:
<?xml version="1.0"?>
<xsd:schema
elementFormDefault='unqualified'
attributeFormDefault='unqualified'
xmlns:xsd='http://www.w3.org/2001/XMLSchema'
>
<xsd:simpleType name='TheSimpleType'>
<xsd:restriction base='xsd:string' />
</xsd:simpleType>
</xsd:schema>
Here is a second XSD that includes the one above:
<?xml version="1.0" encoding="UTF-8" ?>
<xsd:schema
elementFormDefault='unqualified'
attributeFormDefault='unqualified'
xmlns:xsd='http://www.w3.org/2001/XMLSchema'
targetNamespace='a'
xmlns='a'
>
<xsd:include schemaLocation='Include.xsd' />
<xsd:element name = "TheElement" >
<xsd:complexType>
<xsd:attribute name="Code" type="TheSimpleType" use="required"/>
</xsd:complexType>
</xsd:element>
</xsd:schema>
I need to read the (second) XSD into C# and:
- check that it is a valid XSD, and
- validate documents against it.
Here is some C# to read in the schemata:
XmlSchemaSet schemaSet = new XmlSchemaSet();
foreach (string sd in Schemas)
{
using (XmlReader r = XmlReader.Create(new FileStream(sd, FileMode.Open)))
{
schemaSet.Add(XmlSchema.Read(r, null));
}
}
schemaSet.CompilationSettings = new XmlSchemaCompilationSettings();
schemaSet.Compile();
The .Compile() fails because "Type 'a:TheSimpleType' is not declared, or is not a simple type."
However, it works if either:
- the namespace is removed from the schema, or
- the namespace is added to the include.
The question is: how do I get C# to accept it without editing the schemata?
I suspect the problem is that although I have put both schemata into the XmlSchemaSet, I still need to tell C# that one is included into the other, i.e., it hasn't worked it out for itself. Indeed, if I only tell the XmlSchemaSet about the main XSD (and not the include) (both without (or with) namespaces) then "Type 'TheSimpleType' is not declared, or is not a simple type."
Thus this seems to be a question about resolving includes: how?!