I have been working on similar issues, trying to avoid duplication of vertices or edges. The first is a rough example of how I check to make sure I am not duplicating a vertex:
"g.V().has('word', 'name', '%s').fold()"
".coalesce(unfold(),"
"addV('word')"
".property('name', '%s')"
".property('pos', '%s')"
".property('pk', 'pk'))"
% (re.escape(category_),re.escape(category_), re.escape(pos_))
The second one is the way I can make sure that isn't a directional edge in either direction. I make use of two coalesce statements, one nested inside the other:
"x = g.V().has('word', 'name', '%s').next()\n"
"y = g.V().has('word', 'name', '%s').next()\n"
"g.V(y).bothE('distance').has('weight', %f).fold()"
".coalesce("
"unfold(),"
"g.addE('distance').from(x).to(y).property('weight', %f)"
")"
% (word_1, word_2, weight, weight)
So, if the edge exists y -> x, it skips producing another one. If y -> x doesn't exist, then it tests to see if x -> y exists. If not, then it goes to the final option of creating x -> y
Let me know if anyone here knows of a more concise solution. I am still very new to gremlin, and would love a cleaner answer. Though, this one appears to suffice.
When I implemented the previous solutions provided, when I ran my code twice, it produced an edge for each try, because it only tests one direction before creating a new edge.
.as('v')
in the query? As I understand,__.inE('created').where(outV().as('v'))
returns any edges that has labelcreated
from the vertexripple
to another (can be any node), and then label this node asv
. So if this node is different than nodevadas
, would the original query create an edge betweenvadas
andripple
? – Delphine