Converting from HttpClient 3 to 4
Asked Answered
K

4

11

I've managed to make changes to everything but the following:

HttpClient client;
HttpPost method;   
client = new DefaultHttpClient();
method = new HttpPost(url); 

InputStream rstream;
try {
    rstream = method.getResponseBodyAsStream();
} catch (IOException e) {
    return BadSpot(e.getMessage()); 
}

What I'm not sure of is what I should replace getResponseBodyAsStream() with.

Kwiatkowski answered 4/1, 2011 at 22:0 Comment(0)
B
5
InputStream rstream;
try {
    HttpResponse response = client.execute(HttpHost, method);
    rstream = response.getEntity().getContent();
} catch (IOException e) {
    return BadSpot(e.getMessage()); 
}

above should do what you are asking.

Burley answered 4/1, 2011 at 23:1 Comment(0)
H
2

HttpResponse.getEntity(), followed by HttpEntity.getContent()

Herrenvolk answered 4/1, 2011 at 22:39 Comment(0)
T
2

The util class has some helpful methods:

EntityUtils.toString(response.getEntity());

There is also some useful stuff in the examples at apache's website

Taddeusz answered 3/4, 2013 at 14:48 Comment(0)
R
0

Use EntityUtils and check the returned entity to be not null before consuming the entity:

InputStream rstream;
try {
    HttpResponse response = client.execute(HttpHost, method);

    rstream = Optional.ofNullable(httpResponse.getEntity())
    .map(e -> response.getContent()).orElse(null);

} catch (IOException e) {
    return BadSpot(e.getMessage()); 
}

NOTE: the InputStream here can be null and most of all you have to ensure that it's consumed before you actually close the response/release the connection.

Reed answered 23/5, 2017 at 14:10 Comment(0)

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