Is there a way to identify the iOS device CPU architecture in runtime?
Thank you.
Is there a way to identify the iOS device CPU architecture in runtime?
Thank you.
You can use sysctlbyname :
#include <sys/types.h>
#include <sys/sysctl.h>
#include <mach/machine.h>
NSString *getCPUType(void)
{
NSMutableString *cpu = [[NSMutableString alloc] init];
size_t size;
cpu_type_t type;
cpu_subtype_t subtype;
size = sizeof(type);
sysctlbyname("hw.cputype", &type, &size, NULL, 0);
size = sizeof(subtype);
sysctlbyname("hw.cpusubtype", &subtype, &size, NULL, 0);
// values for cputype and cpusubtype defined in mach/machine.h
if (type == CPU_TYPE_X86)
{
[cpu appendString:@"x86 "];
// check for subtype ...
} else if (type == CPU_TYPE_ARM)
{
[cpu appendString:@"ARM"];
switch(subtype)
{
case CPU_SUBTYPE_ARM_V7:
[cpu appendString:@"V7"];
break;
// ...
}
}
return [cpu autorelease];
}
I think this is the better way,
#import <mach-o/arch.h>
NXArchInfo *info = NXGetLocalArchInfo();
NSString *typeOfCpu = [NSString stringWithUTF8String:info->description];
//typeOfCpu = "arm64 v8"
Just adding more to @Emmanuel's answer:
- (NSString *)getCPUType {
NSMutableString *cpu = [[NSMutableString alloc] init];
size_t size;
cpu_type_t type;
cpu_subtype_t subtype;
size = sizeof(type);
sysctlbyname("hw.cputype", &type, &size, NULL, 0);
size = sizeof(subtype);
sysctlbyname("hw.cpusubtype", &subtype, &size, NULL, 0);
// values for cputype and cpusubtype defined in mach/machine.h
if (type == CPU_TYPE_X86_64) {
[cpu appendString:@"x86_64"];
} else if (type == CPU_TYPE_X86) {
[cpu appendString:@"x86"];
} else if (type == CPU_TYPE_ARM) {
[cpu appendString:@"ARM"];
switch(subtype)
{
case CPU_SUBTYPE_ARM_V6:
[cpu appendString:@"V6"];
break;
case CPU_SUBTYPE_ARM_V7:
[cpu appendString:@"V7"];
break;
case CPU_SUBTYPE_ARM_V8:
[cpu appendString:@"V8"];
break;
}
}
return cpu;
}
Here is the swift version of @Mahmut's answer.
import MachO
private func getArchitecture() -> NSString {
let info = NXGetLocalArchInfo()
return NSString(utf8String: (info?.pointee.description)!)!
}
print(getArchitecture() ?? "No architecture found")
ARM64E
What is ARM64E?Intel 80486
ARM64E
Intel x86-64h Haswell
Feel free to update this.
Alternative answer that is Swift Package Manager compliant:
public func getMachineArchitecture() -> String {
#if arch(arm)
return "arm"
#elseif arch(arm64)
return "arm64"
#elseif arch(i386)
return "i386"
#elseif arch(powerpc64)
return "powerpc64"
#elseif arch(powerpc64le)
return "powerpc64le"
#elseif arch(s390x)
return "s390x"
#elseif arch(wasm32)
return "wasm32"
#elseif arch(x86_64)
return "x86_64"
#else
return "unknown_machine_architecture"
#endif
}
I feel that this is the best answer for Swift yet:
import MachO
func getArch() -> String? {
guard let archRaw = NXGetLocalArchInfo().pointee.name else {
return nil
}
return String(cString: archRaw)
}
print("Current device architecture: \(getArch() ?? "Unknown Archetiture")")
For A11 (iPhone X, 8, 8+) and lower devices, the function above will return arm64
, However for A12 (iPhone Xs, Xs Max, XR) and newer devices, it will return arm64e
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