MVC Capture webcam image, save file path of image to the database
Asked Answered
M

1

-1

Here is the gist of what I am trying to achieve:

  • Capture a webcam image from the Edit view. (working)
  • Assign the image a file name and path. (working)
  • Save the image to the images folder. (working)
  • Store the path to the image in the database. (Not working)

Here is my Capture controller:

      public void Capture(String FileLocation)
    {
        //var FileLocation = Server.MapPath("~/Images/test.jpg");
        var stream = Request.InputStream;
        string dump;

        using (var reader = new StreamReader(stream))
            dump = reader.ReadToEnd();


        if (System.IO.File.Exists(FileLocation))
        {
            System.IO.File.Delete(FileLocation);
            System.IO.File.WriteAllBytes(FileLocation, String_To_Bytes2(dump));
        }
        else System.IO.File.WriteAllBytes(FileLocation, String_To_Bytes2(dump));


        return;

    }

And here is the Edit controller:

    [HttpPost]
    [ValidateAntiForgeryToken]
    public ActionResult Edit(TrappingEvent trappingevent)
    {

        if (ModelState.IsValid)
        {


            db.Entry(trappingevent).State = EntityState.Modified;
            db.SaveChanges();

            return RedirectToAction("Index");
        }

        ViewBag.PersonId = new SelectList(db.People, "Id", "First_Name", trappingevent.PersonId);
        return View(trappingevent);
    }

From my limited understanding it would be nice to pass the file path as a variable from the Capture void to the controller for binding to the model.

Thanks for your help.

Marquez answered 2/11, 2016 at 1:24 Comment(0)
M
0

Its working! Well I did it in a roundabout way and still happy to hear suggestions.

Heres the gist:

  • when I click the capture button i run the function:

    function CaptureAndAssignText() {
    var Div = document.getElementById("ImagePath");//ImagePath is the field
    // I want to bind to the model.
    
    newText = "ID_" + @Model.Id + ".jpg";//Here I grab the Id of 
    //the current model to use as the file name
    
    Div.value = newText;//Assign the file name to the input 
    //field ready for submission.
    
    webcam.capture();//Run the capture function
    }
    
  • Here is the Capture function(fairly standard - can someone tell me if I need document ready for this?)

    $(document).ready(function () {
                            $("#Camera").webcam({
                                width: 320,
                                height: 240,
                                mode: "save",
                                swffile: "@Url.Content("~/Scripts/jscam.swf")",
                                onTick: function () { },
                                onSave: function () {
                                },
                                onCapture: function () {
                                    webcam.save("@Url.Action("Capture", "TrapActivity", new { id = @Model.Id , pid = @Model.PersonId})");
                                },
                                debug: function () { },
                                onLoad: function () { }
                            });
                       });
    

Here is my controller, modified to accept the model ID as a string (have included the String to Bytes function for easy reference):

    public ActionResult Capture(string ID)
    {
        var path = Server.MapPath("~/Images/ID_" + ID + ".jpg" );

        //var path1 = "~/Images/test.jpg;";



        var stream = Request.InputStream;
        string dump;

        using (var reader = new StreamReader(stream))
            dump = reader.ReadToEnd();


        if (System.IO.File.Exists(path))
        {
            System.IO.File.Delete(path);
            System.IO.File.WriteAllBytes(path, String_To_Bytes2(dump));
        }
        else System.IO.File.WriteAllBytes(path, String_To_Bytes2(dump));


        return View(ID);

    }

    private byte[] String_To_Bytes2(string strInput)
    {
        int numBytes = (strInput.Length) / 2;
        byte[] bytes = new byte[numBytes];

        for (int x = 0; x < numBytes; ++x)
        {
            bytes[x] = Convert.ToByte(strInput.Substring(x * 2, 2), 16);
        }

        return bytes;
    }

Now once capture has been clicked. The form can be submitted just as if you were submitting a strongly typed form.

There is a potential issue with this method

  • This way only allows one image to be stored.
  • Im sort of storing the file path in a really strange way.

Im more than open to suggestions.

Marquez answered 2/11, 2016 at 3:55 Comment(0)

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