how to get ALL google search results using api [duplicate]

Question

I need to get google search results for query. But using something like this

$query = 'Nikita Platonenko';
$url = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=".urlencode($query);
$body = file_get_contents($url);
$json = json_decode($body);
var_dump($json)

i get only 4 results, I've already read about google ajax search but couldn't understand it. Please advise how to get all resulsts, or just first 100 results?

Return

The same question: Google AJAX API - How do I get more than 4 Results? – Felicidad

Answer 1

<?php
$query = 'Nikita%20Platonenko';
$url = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=".$query;

$body = file_get_contents($url);
$json = json_decode($body);

for($x=0;$x<count($json->responseData->results);$x++){

echo "<b>Result ".($x+1)."</b>";
echo "<br>URL: ";
echo $json->responseData->results[$x]->url;
echo "<br>VisibleURL: ";
echo $json->responseData->results[$x]->visibleUrl;
echo "<br>Title: ";
echo $json->responseData->results[$x]->title;
echo "<br>Content: ";
echo $json->responseData->results[$x]->content;
echo "<br><br>";

}

?>

As the AJAX Api is now depreciated, you can use a third party service like SerpApi to get Google results. They have a GitHub repository, and it should be easy to integrate:

$query = [
    "q" => "Coffee",
    "google_domain" => "google.com",
];

$serp = new GoogleSearchResults();
$json_results = $serp.json($query);

Kennith

this a great example. can you tell its limitations. Thanks – Poucher

@Kennith thanks for awesome answer i have little query it is giving only 4 results how can i get more result – Porch

to get more results fire another query to server with start parameter. like http://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=$query&start=4 – Inebriety

is this still working? couldnt get it to work - get NULL json. tks – Systemic

hi , it is working for me. i only need first link from seach result. but I want to know that it is free using this link($url = "ajax.googleapis.com/ajax/services/search/…; ) or there is some restriction? – Kerwinn

No longer working as of writing this. Returns: {"responseData": null, "responseDetails": "The Google Web Search API is no longer available. Please migrate to the Google Custom Search API (developers.google.com/custom-search)", "responseStatus": 403} – Jasmin

Not Working.it gives error – Glacialist

The JSON API is newer and has not been deprecated. It can handle 10k requests daily. – Henricks

Answer 2

The answer:

Here is what I use successfully:

http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=[q]&key=[key]&cx=[account]&rsz=large&userip=[userip]&start=[start]

I don't think you have full control over how many results that can be obtained in the query. But you can control the results size (rsz=large), and where it starts.

Other notes:

In addition, it is always good to include the user's ip address there. Because, Google limits the number of queries based unique ip addresses (meaning, how many from an ip address). So if they are all coming from your server, you will be limited in how many queries you can send, but the limits go way down if you send the user's ip address. In addition, caching the results for a couple of days is an added bonus.

Afternoon

i couldn't understand where i can get key and account – Return

developers.google.com/custom-search/v1/overview – Afternoon