Edited:
Since 3.12.0 AssertJ provides satisfiesAnyOf
which succeeds if at least one of the given assertion succeeds,
assertThat(list).satisfiesAnyOf(
listParam -> assertThat(listParam).contains(Tags.SWEETS, Tags.HIGH),
listParam -> assertThat(listParam).contains(Tags.SOUPS, Tags.RED)
);
Original answer:
No, this is an area where Hamcrest is better than AssertJ.
To write the following assertion:
Set<String> goodTags = newLinkedHashSet("Fine", "Good");
Set<String> badTags = newLinkedHashSet("Bad!", "Awful");
Set<String> tags = newLinkedHashSet("Fine", "Good", "Ok", "?");
// contains is statically imported from ContainsCondition
// anyOf succeeds if one of the conditions is met (logical 'or')
assertThat(tags).has(anyOf(contains(goodTags), contains(badTags)));
you need to create this Condition:
import static org.assertj.core.util.Lists.newArrayList;
import java.util.Collection;
import org.assertj.core.api.Condition;
public class ContainsCondition extends Condition<Iterable<String>> {
private Collection<String> collection;
public ContainsCondition(Iterable<String> values) {
super("contains " + values);
this.collection = newArrayList(values);
}
static ContainsCondition contains(Collection<String> set) {
return new ContainsCondition(set);
}
@Override
public boolean matches(Iterable<String> actual) {
Collection<String> values = newArrayList(actual);
for (String string : collection) {
if (!values.contains(string)) return false;
}
return true;
};
}
It might not be what you if you expect that the presence of your tags in one collection implies they are not in the other one.
Condition
is very similar to the HamcrestMatcher
; the difference is that Hamcrest comes with dozens of them (since that is Hamcrest’s concept, after all). Also, the Hamcrest matchers are really quite versatile, they can be used for anything and can be passed around. That is the price you have to pay for the code completion. Perhaps it would be possible to use a Hamcrest matcher in place of a condition? – Gadoid