C: Cannot initialize variable with an rvalue of type void*

Question

I have the following code:

int *numberArray = calloc(n, sizeof(int));

And I am unable to understand why I receive the following error.

Cannot initialize a variable of type 'int *' with an rvalue of type 'void *'`.

Thank you.

Chittagong

int *numberArray = (int*)calloc(n, sizeof(int)); It´s called casting. – Enlarger

In C++, malloc and calloc require a type cast. – Asiatic

Is there no documentation for calloc anymore? – Ghirlandaio

Well, you can also use new if it is C++. – Asiatic

@j809 I replace calloc with new, but now he say: Expected a type – Chittagong

Answer 1

The compiler's error message is very clear.

The return value of calloc is void*. You are assigning it to a variable of type int*.

That is ok in a C program, but not in a C++ program.

You can change that line to

int* numberArray = (int*)calloc(n, sizeof(int));

But, a better alternative will be to use the new operator to allocate memory. After all, you are using C++.

int* numberArray = new int[n];

Sapajou

Answer 2

void* calloc (size_t num, size_t size);

Allocate and zero-initialize array. Allocates a block of memory for an array of num elements, each of them size bytes long, and initializes all its bits to zero.The effective result is the allocation of a zero-initialized memory block of (num*size) bytes.

On success, a pointer to the memory block allocated by the function. The type of this pointer is always void*, which can be cast to the desired type of data pointer in order to be dereferenceable. If the function failed to allocate the requested block of memory, a null pointer is returned.

To summarize, since calloc returns a void* (generic pointer) on success of memory allocation, you will have to type-cast it like this in C++:

int *numberArray = (int*)calloc(n, sizeof(int));

If it was C, you can still skip this cast.

Or, use new as:

int *numberArray = new int [n];

Asiatic

Answer 3

You're using C memory re-allocation style in a C++ code. What you want to use is new in C++

So your code will become:

int n = 10; //n = size of your array
int *narray = new int[n];
for (int i = 0; i < n; i++)
    cout << narray[i];

Alternatively you can switch back to C and use calloc with casting.

int* numberArray = (int*)calloc(n, sizeof(int));

Collenecollet

Answer 4

Syntax for calloc is:

void* calloc (size_t num, size_t size);

calloc returns void pointer. In your code , you are trying to assign void pointer to integer pointer. So you are getting Cannot initialize a variable of type 'int *' with an rvalue of type 'void *'. So typecast the void pointer before assign it like this

*numberArray = (int *) calloc(n, sizeof(int));

Carbonous