How do I programmatically retrieve the actual path to the "Program Files" folder? [duplicate]

Question

Possible Duplicate:
C# - How to get Program Files (x86) on Windows Vista 64 bit

I realize the odds of a user changing the Windows default of C:\Program Files is fairly slim, but stranger things have happened!

How can I get the correct path to Program Files from the system?

Davison

Odds ore not that slim - on Spanish version the default path is C:\Archivos de programa\ That's why any sane developer should retrieve the path form the system, not hardcode it. – Renaud

...and for the Swedish version the default path is c:\program\. Definitely avoid hardcoding. – Bothersome

And in Italian it's C:\Programmi – Quota

Answer 1

.NET provides an enumeration of 'special folders' for Program Files, My Documents, etc.

The code to convert from the enumeration to the actual path looks like this:

Environment.GetFolderPath(Environment.SpecialFolder.ProgramFiles)

http://msdn.microsoft.com/en-us/library/14tx8hby.aspx

Davison

There is a gotcha to this if I recall correctly: it does not distinguish between x64 and x86 versions of Windows. If you're looking for %programfiles(x86)%, you'll have to find another method. – Geosyncline

Indeed! There is a related question that covers the x64 issue: #194657 – Davison

On a 64-bit OS, this depends on the platform you compile for. E.g. if you compile for AnyCPU or x64, this will give you C:\Program Files. If you compile for x86, this will give you C:\Program Files (x86). – Gruver

Answer 2

Just to add to this.

If you're running in 32 bit mode (even on a 64 bit os), SpecialFolder.ProgramFiles and %PROGRAMFILES% will return ..Program Files (x86).

If you specifically need one and/or the other then you'll need to check as follows:

32 bit system:

SpecialFolder.ProgramFiles = ..Program Files\

64 bit system in 32 bit process: SpecialFolder.ProgramFiles = ..Program Files (x86)\ Environment.GetEnvironmentVariable("ProgramW6432") = ..Program Files\

64 bit system in 64 bit process: SpecialFolder.ProgramFiles = ..Program Files\ Environment.GetEnvironmentVariable("PROGRAMFILES(X86)") = ..Program Files (x86)\

Obviously this depends on your locale etc...

Snub

Thank you! Just as a follow up (because I needed that), there is also the CommonProgramW6432 environment variable for the common files folder. – Faradism

Answer 3

You would use GetFolderPath in the Environment class.

try {
    Environment.GetFolderPath( Environment.SpecialFolder.ProgramFiles )
catch( ArgumentException ex ) {
    Console.Out.WriteLine( ex.StackTrace );
}

Capias

Answer 4

Environment.GetFolderPath(Environment.SpecialFolder.ProgramFiles) is probably the best solution, but another possible variant is evaluating the value of the ProgramFiles environment variable. For this, you can use the GetEnvironmentVariable or ExpandEnvironmentVariables method of the Environment class:

Environment.GetEnvironmentVariable("ProgramFiles")

Environment.ExpandEnvironmentVariables("%ProgramFiles%")

Gruver

or Environment.GetEnvironmentVariable("ProgramFiles") ? – Davison

Answer 5

You can access the environment variable called: %PROGRAMFILES%

i.e:

%PROGRAMFILES%\Maxis\SimCity

in C#:

System.Environment.SpecialFolder.ProgramFiles

Czech

A correction: It should be %PROGRAMFILES%\Maxis\SimCity. The %PROGRAMFILES% variable already contains the 'C:\'. – Guildroy

Answer 6

Environment.GetEnvironmentVariable("PROGRAMFILES(X86)") ?? Environment.GetFolderPath(Environment.SpecialFolder.ProgramFiles)

gets "program files (x86)" in 64-bits Windows and "program files" in 32 bit.

Palila