In SQL Server Reporting Services, how would I calculate the last day of the current month?
Here is the answer I came up with
=DateSerial(Year(Now()), Month(Now()), "1").AddMonths(1).AddDays(-1)
As it took me a while to Figure this out, and JC's answer was the simplest to modify and had a good logical structure. I expanded it Slightly for others searching for answers on this topic. I have found normally you don't just want the Last Day of a month / year you also want the first day of the month / year. So here they are the full lines to calculate just that. wtih the SQl version there also.
First Day of Current month
SSRS=Today.AddDays(1-Today.Day)
SQL=SELECT DATEADD(s,0,DATEADD(mm, DATEDIFF(m,0,getdate()),0))
Last day of Current Month
SSRS=Today.AddDays(1-Today.Day).AddMonths(1).AddDays(-1)
SQL=SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0))
First Day of Current year
SSRS=Today.AddMonths(1-Today.month).AddDays(1-Today.day)
SQL=SELECT DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)
Last Day of Current Year
SSRS=Today.AddDays(1-Today.Day).AddMonths(13-today.month).AddDays(-1)
SQL=SELECT DATEADD(dd,-1,DATEADD(yy,0,DATEADD(yy,DATEDIFF(yy,0,getdate())+1,0)))
I hope this helps somone.
I know you've found your own answer, but I'd suggest this alternative:
=Today.AddDays(1-Today.Day).AddMonths(1).AddDays(-1)
It's a little easier to read, in my opinion, and might have slightly better performance (though most likely unnoticeable)
And, of course, if you wanted to pad out that date to 23:59:59, as is often necessary, just modify slightly:
=Today.AddDays(1-Today.Day).AddMonths(1).AddSeconds(-1)
From the blog of a Microsoft SQL Team member:
-- returns the last day of the current month.
select dbo.Date(year(getdate()), month(getdate())+1,0)
http://weblogs.sqlteam.com/jeffs/archive/2007/01/02/56079.aspx
Hope this helps! --Dubs
You may try this expression, Just replace now with your date field.
=DateSerial(Year(Now), Month(Now), 1)
Hope this helps.
Regards
There is an even easier way as in the marked answer:
=DateSerial(Year(Now()), Month(Now())+1, 0)
Since DateSerial() accepts integers as parameters one does not have to use AddMonths() and AddDays(). As in the example an instant calculation inside DateSerial() is possible.
Furthermore day 1 is the first day of the month while the first day minus one day is the last day of the month before (1-1=0). So the example will return the date of the last day of the current month.
you can use an assembly for doing this work by adding it as a reference.
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