Applying a tint to an image in java
Asked Answered
I

7

23

I am trying to create several similar visual styles for my programs, each with a different color theme. To do this, I have implemented the use of icons to represent the different states of JCheckBoxs and JRadioButtons. Instead of making one full set of icons for every possible color, is there any way I can just take one set and change the hue/saturation/luminosity/alpha of the image before displaying it?

Irruptive answered 22/11, 2010 at 17:11 Comment(0)
T
13

There is a way, but you'll have to make use of some BufferedImage transformations. Once you create them, cache them or save them off to be easily reused later. Essentially, you want to start off with a black image (source color #000000) that only uses the alpha layer to turn off pixels (also providing smooth anti-aliasing). For example, in your source image, every pixel is black, but the alpha channel differs from pixel to pixel.

First, read this article for some background information: http://www.javalobby.org/articles/ultimate-image/

Once you get done with that primer, you need to load your image into a BufferedImage:

BufferedImage loadImg = ImageUtil.loadImage("C:/Images/myimg.png");

Next you need to create a new BufferedImage to make the transform into:

public BufferedImage colorImage(BufferedImage loadImg, int red, int green, int blue) {
    BufferedImage img = new BufferedImage(loadImg.getWidth(), loadImg.getHeight(),
        BufferedImage.TRANSLUCENT);
    Graphics2D graphics = img.createGraphics(); 
    Color newColor = new Color(red, green, blue, 0 /* alpha needs to be zero */);
    graphics.setXORMode(newColor);
    graphics.drawImage(loadImg, null, 0, 0);
    graphics.dispose();
    return img;
}

Essentially, the setXORMode will XOR the color you provide with the color in the source image. If the source image is black, then whatever color you provide will be written as you specify it. With the new color using "0" for the alpha channel, the original alpha channel values will be respected. The end result is the composite you are looking for.

Edit:

You can load the initial BufferedImage in one of two ways. The easiest is to use Java's newer ImageIO API: http://download.oracle.com/javase/6/docs/api/javax/imageio/ImageIO.html to load the file directly to a BufferedImage. The call would look something like this:

BufferedImage img = ImageIO.read(url); 

Alternatively, you can create a method to read the image using the ToolKit.

public BufferedImage loadImage(String url) {
    ImageIcon icon = new ImageIcon(url);
    Image image = icon.getImage();

    // Create empty BufferedImage, sized to Image
    BufferedImage buffImage = 
      new BufferedImage(
        image.getWidth(null), 
        image.getHeight(null), 
        BufferedImage.TYPE_INT_ARGB);

    // Draw Image into BufferedImage
    Graphics g = buffImage.getGraphics();
    g.drawImage(image, 0, 0, null);
    return buffImage;
}

Of course, if you pay attention, we have to do the exact same thing to read the image into a buffered image as we do to tint it. In short, if you changed the signature of the colorImage method to accept the Image object you only need to make a couple changes to the getWidth() and getHeight() methods to get it to work.

Tumult answered 22/11, 2010 at 17:46 Comment(9)
Can I use this for Images and ImageIcons?Irruptive
Also ImageUtil.loadImage(String s) does not existIrruptive
The only standard java class that has it is com.sun.imageio.plugins.common.ImageUtil and that has no loadImage methodIrruptive
Ok, did a bit more snooping around and this is what I came up with: Image img = Toolkit.getDefaultToolkit().getImage(URL or file path);Tumult
Everything else should be about the same.Tumult
How do I make a BufferedImage out of an Image or ImageIcon?Irruptive
It will be easier overall to use the Java ImageIO packages. download.oracle.com/javase/6/docs/api/javax/imageio/… But you can also do it like this: jguru.com/faq/view.jsp?EID=53328Tumult
Please note that BufferedImage.TRANSLUCENT is not a valid BufferedImage type. The actual constant value just happens to be the same as for BufferedImage.TYPE_INT_ARGB_PRETerriss
Do allow for API changes over the past 6 years. When this was written in 2010, the code was correct, Java was owned by Sun, and the world was different. If there is a new and better way to accomplish this answer than the when I wrote this 7 years ago, please provide a new updated answer rather than downvoting this one.Tumult
R
4

To calculate average for each color component and keep original alpha:

public static void tint(BufferedImage image, Color color) {
    for (int x = 0; x < image.getWidth(); x++) {
        for (int y = 0; y < image.getHeight(); y++) {
            Color pixelColor = new Color(image.getRGB(x, y), true);
            int r = (pixelColor.getRed() + color.getRed()) / 2;
            int g = (pixelColor.getGreen() + color.getGreen()) / 2;
            int b = (pixelColor.getBlue() + color.getBlue()) / 2;
            int a = pixelColor.getAlpha();
            int rgba = (a << 24) | (r << 16) | (g << 8) | b;
            image.setRGB(x, y, rgba);
        }
    }
}

This works best for my case.

Redound answered 20/4, 2016 at 12:49 Comment(0)
R
3
public static void tint(BufferedImage img) {

    for (int x = 0; x < img.getWidth(); x++) {
        for (int y = 0; y < img.getHeight(); y++) {

            Color color = new Color(img.getRGB(x, y));

            // do something with the color :) (change the hue, saturation and/or brightness)
            // float[] hsb = new float[3];
            // Color.RGBtoHSB(color.getRed(), old.getGreen(), old.getBlue(), hsb);

            // or just call brighter to just tint it
            Color brighter = color.brighter();

            img.setRGB(x, y, brighter.getRGB());
        }
    }
}
Resile answered 22/11, 2010 at 17:54 Comment(3)
I don't want to make a new image file. I want to tint it within the programIrruptive
How do I make a BufferedImage out of an Image or ImageIcon?Irruptive
You create a BufferedImage of the same size and color resolution. Then you do a getGraphics on the BufferedImage and use that graphics context to draw the Image or ImageIcon in it at position 0,0. After that you are free to do whatever you will with the pixeldata.Graniah
T
3

The easiest way to do this would be by using the Image Filters by JH Labs. You can simply adjust HSB by calling,

public BufferedImage setHSB(BufferedImage source, float hValue, float sValue, float bValue) {        
    com.jhlabs.image.HSBAdjustFilter hsb hsb = new HSBAdjustFilter();
    BufferedImage destination = hsb.createCompatibleDestImage(source, null);
    hsb.setHFactor(hValue);
    hsb.setSFactor(sValue);
    hsb.setBFactor(bValue);
    BufferedImage result = hsb.filter(bi, destination);

    return result;
}
Tuck answered 22/1, 2014 at 4:10 Comment(1)
What does bi stand for?Duplessis
B
1

This isn't exactly tinting, its more like applying another layer on it but it works for me:

public static BufferedImage colorImage(BufferedImage loadImg, int red, int green, int blue, int alpha /*Also the intesity*/) {
    Graphics g = loadImg.getGraphics();
    g.setColor(new Color(red, green, blue, alpha));
    g.fillRect(0, 0, loadImg.getWidth(), loadImg.getHeight());
    g.dispose();
    return loadImg;
}
Bet answered 23/9, 2013 at 0:34 Comment(6)
doesn't that just return an image that is a solid color?Irruptive
No, if you set the alpha it makes it a bit see through, so instead of setting the alpha to 255, set it to something like a 100 and it works just fine.Bet
this won't work if I'm trying to tint an image with alpha already in it, as then this will fill the transparent areas with this translucent colorIrruptive
That is the problem with thissBet
If you add alpha composition, it will work. check ((Graphics2D) g).setCompositr(...) with different options.Methenamine
Set g2d.setComposite(AlphaComposite.getInstance(AlphaComposite.SRC_ATOP))Collyer
C
1

I tried every solution on this page, had no luck. The Xor one (accepted answer) didn't work for me - tinted a weird yellow color instead of the color I was giving as an argument no matter what the argument. I finally found an approach that works for me, though it is a bit messy. Figured I'd add it in case anyone else is having the same issues I am with the other solutions. Cheers!

/** Tints the given image with the given color.
 * @param loadImg - the image to paint and tint
 * @param color - the color to tint. Alpha value of input color isn't used.
 * @return A tinted version of loadImg */
public static BufferedImage tint(BufferedImage loadImg, Color color) {
    BufferedImage img = new BufferedImage(loadImg.getWidth(), loadImg.getHeight(),
            BufferedImage.TRANSLUCENT);
    final float tintOpacity = 0.45f;
    Graphics2D g2d = img.createGraphics(); 

    //Draw the base image
    g2d.drawImage(loadImg, null, 0, 0);
    //Set the color to a transparent version of the input color
    g2d.setColor(new Color(color.getRed() / 255f, color.getGreen() / 255f, 
        color.getBlue() / 255f, tintOpacity));

    //Iterate over every pixel, if it isn't transparent paint over it
    Raster data = loadImg.getData();
    for(int x = data.getMinX(); x < data.getWidth(); x++){
        for(int y = data.getMinY(); y < data.getHeight(); y++){
            int[] pixel = data.getPixel(x, y, new int[4]);
            if(pixel[3] > 0){ //If pixel isn't full alpha. Could also be pixel[3]==255
                g2d.fillRect(x, y, 1, 1);
            }
        }
    }
    g2d.dispose();
    return img;
}
Checker answered 20/12, 2014 at 3:5 Comment(0)
T
0

Because all methods I found didn't work for me for whatever reason, here is an easy way to approach this (no extra libs needed):

/**
 * Colors an image with specified color.
 * @param r Red value. Between 0 and 1
 * @param g Green value. Between 0 and 1
 * @param b Blue value. Between 0 and 1
 * @param src The image to color
 * @return The colored image
 */
protected BufferedImage color(float r, float g, float b, BufferedImage src) {

    // Copy image ( who made that so complicated :< )
    BufferedImage newImage = new BufferedImage(src.getWidth(), src.getHeight(), BufferedImage.TRANSLUCENT);
    Graphics2D graphics = newImage.createGraphics();
    graphics.drawImage(src, 0, 0, null);
    graphics.dispose();

    // Color image
    for (int i = 0; i < newImage.getWidth(); i++) {
        for (int j = 0; j < newImage.getHeight(); j++) {
            int ax = newImage.getColorModel().getAlpha(newImage.getRaster().getDataElements(i, j, null));
            int rx = newImage.getColorModel().getRed(newImage.getRaster().getDataElements(i, j, null));
            int gx = newImage.getColorModel().getGreen(newImage.getRaster().getDataElements(i, j, null));
            int bx = newImage.getColorModel().getBlue(newImage.getRaster().getDataElements(i, j, null));
            rx *= r;
            gx *= g;
            bx *= b;
            newImage.setRGB(i, j, (ax << 24) | (rx << 16) | (gx << 8) | (bx << 0));
        }
    }
    return newImage;
}

A black image will always stay black, but a white image will be the color you specify. This method goes through every pixel and multiply the red green and blue values of the image with parameters. This is the exact behavior of the OpenGL glColor3f() method. R, G and B params must be 0.0F to 1.0F.

This method has no problem with alpha values.

Testis answered 1/4, 2015 at 10:47 Comment(5)
This does not work. Produces an LSD hallucination instead.Duplessis
Huh? Can you post a screenshot? I've used this method myself…Testis
Yours looks like this. Mine (which is also not good) looks like this. Note that the red face looks good with your solution but it is a simple red color (255, 0, 0). The other colors are not working for some reason. The original (uncolored) looks like thisDuplessis
What I'm trying to do is adding color to a grayscale image.Duplessis
Can you post your color() method call?Testis

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