How to access value of first index of array in Go templates
Asked Answered
C

1

23

So I have and html template when using this I get the object:

<div>Foobar {{ index .Doc.Users 0}}</div>

Output:

<div>Foobar {MyName [email protected]}</div>

I just want to use the Name field I have tried many iterations without success:

{{ index .Doc.Users.Name 0}}
{{ index .Doc.Users 0 .Name}}
{{ .Name index .Quote.Clients 0}}
...

What is the correct syntax for just getting .Name field (.Doc.Users[0].Name) of the first element in my array?

Cirsoid answered 6/10, 2018 at 19:27 Comment(0)
S
31

Simply group the expression and apply the .Name selector:

<div>Foobar {{ (index .Doc.Users 0).Name }}</div>

Here's a runnable, verifiable example:

type User struct {
    Name  string
    Email string
}

t := template.Must(template.New("").Parse(
    `<div>Foobar {{ (index .Doc.Users 0).Name }}</div>`))

m := map[string]interface{}{
    "Doc": map[string]interface{}{
        "Users": []User{
            {Name: "Bob", Email: "[email protected]"},
            {Name: "Alice", Email: "[email protected]"},
        },
    },
}

fmt.Println(t.Execute(os.Stdout, m))

Output (try it on the Go Playground):

<div>Foobar Bob</div><nil>

(The <nil> at the end is the error value returned by template.Execute(), telling there were no errors executing the template.)

Satiated answered 6/10, 2018 at 19:35 Comment(1)
Let us continue this discussion in chat.Vezza

© 2022 - 2024 — McMap. All rights reserved.