How to parse dates with -0400 timezone string in Python?
Asked Answered
S

6

97

I have a date string of the form '2009/05/13 19:19:30 -0400'. It seems that previous versions of Python may have supported a %z format tag in strptime for the trailing timezone specification, but 2.6.x seems to have removed that.

What's the right way to parse this string into a datetime object?

Sonorous answered 9/7, 2009 at 2:19 Comment(0)
S
133

You can use the parse function from dateutil:

>>> from dateutil.parser import parse
>>> d = parse('2009/05/13 19:19:30 -0400')
>>> d
datetime.datetime(2009, 5, 13, 19, 19, 30, tzinfo=tzoffset(None, -14400))

This way you obtain a datetime object you can then use.

As answered, dateutil2.0 is written for Python 3.0 and does not work with Python 2.x. For Python 2.x dateutil1.5 needs to be used.

Sturgill answered 9/7, 2009 at 2:47 Comment(1)
This works fine for me (dateutil 2.1) with Python 2.7.2; Python 3 isn't required. Note that if you're installing from pip, the package name is python-dateutil.Gillis
C
61

%z is supported in Python 3.2+:

>>> from datetime import datetime
>>> datetime.strptime('2009/05/13 19:19:30 -0400', '%Y/%m/%d %H:%M:%S %z')
datetime.datetime(2009, 5, 13, 19, 19, 30,
                  tzinfo=datetime.timezone(datetime.timedelta(-1, 72000)))

On earlier versions:

from datetime import datetime

date_str = '2009/05/13 19:19:30 -0400'
naive_date_str, _, offset_str = date_str.rpartition(' ')
naive_dt = datetime.strptime(naive_date_str, '%Y/%m/%d %H:%M:%S')
offset = int(offset_str[-4:-2])*60 + int(offset_str[-2:])
if offset_str[0] == "-":
   offset = -offset
dt = naive_dt.replace(tzinfo=FixedOffset(offset))
print(repr(dt))
# -> datetime.datetime(2009, 5, 13, 19, 19, 30, tzinfo=FixedOffset(-240))
print(dt)
# -> 2009-05-13 19:19:30-04:00

where FixedOffset is a class based on the code example from the docs:

from datetime import timedelta, tzinfo

class FixedOffset(tzinfo):
    """Fixed offset in minutes: `time = utc_time + utc_offset`."""
    def __init__(self, offset):
        self.__offset = timedelta(minutes=offset)
        hours, minutes = divmod(offset, 60)
        #NOTE: the last part is to remind about deprecated POSIX GMT+h timezones
        #  that have the opposite sign in the name;
        #  the corresponding numeric value is not used e.g., no minutes
        self.__name = '<%+03d%02d>%+d' % (hours, minutes, -hours)
    def utcoffset(self, dt=None):
        return self.__offset
    def tzname(self, dt=None):
        return self.__name
    def dst(self, dt=None):
        return timedelta(0)
    def __repr__(self):
        return 'FixedOffset(%d)' % (self.utcoffset().total_seconds() / 60)
Complemental answered 17/4, 2014 at 0:21 Comment(3)
This causes a ValueError: 'z' is a bad directive in format '%Y-%m-%d %M:%H:%S.%f %z' in my case (Python 2.7).Loisloise
@Sheljohn it is not supposed to work on Python 2.7 Look at the very top of the answer.Complemental
weird, by the way, that this is NOT AT ALL mentioned on Python 2.7 docs: docs.python.org/2.7/library/…Sulfite
P
26

Here is a fix of the "%z" issue for Python 2.7 and earlier

Instead of using:

datetime.strptime(t,'%Y-%m-%dT%H:%M %z')

Use the timedelta to account for the timezone, like this:

from datetime import datetime,timedelta
def dt_parse(t):
    ret = datetime.strptime(t[0:16],'%Y-%m-%dT%H:%M')
    if t[18]=='+':
        ret-=timedelta(hours=int(t[19:22]),minutes=int(t[23:]))
    elif t[18]=='-':
        ret+=timedelta(hours=int(t[19:22]),minutes=int(t[23:]))
    return ret

Note that the dates would be converted to GMT, which would allow doing date arithmetic without worrying about time zones.

Pyrrho answered 17/8, 2016 at 9:25 Comment(3)
I like this, though you need to change 'seconds=' to 'minutes='.Septennial
Just as a note, if you wanted to take a timezone in a string, and convert the datetime to UTC, you would use the opposite logic listed here. If the timezone has a +, you subtract the timedelta, and vice-versa.Peeper
The transformation to UTC was wrong, if there is a + character the timedelta should be substracted, and vice-versa. I have edited and corrected the code.Felske
T
7

The problem with using dateutil is that you can't have the same format string for both serialization and deserialization, as dateutil has limited formatting options (only dayfirst and yearfirst).

In my application, I store the format string in .INI file, and each deployment can have its own format. Thus, I really don't like the dateutil approach.

Here's an alternative method that uses pytz instead:

from datetime import datetime, timedelta

from pytz import timezone, utc
from pytz.tzinfo import StaticTzInfo

class OffsetTime(StaticTzInfo):
    def __init__(self, offset):
        """A dumb timezone based on offset such as +0530, -0600, etc.
        """
        hours = int(offset[:3])
        minutes = int(offset[0] + offset[3:])
        self._utcoffset = timedelta(hours=hours, minutes=minutes)

def load_datetime(value, format):
    if format.endswith('%z'):
        format = format[:-2]
        offset = value[-5:]
        value = value[:-5]
        return OffsetTime(offset).localize(datetime.strptime(value, format))

    return datetime.strptime(value, format)

def dump_datetime(value, format):
    return value.strftime(format)

value = '2009/05/13 19:19:30 -0400'
format = '%Y/%m/%d %H:%M:%S %z'

assert dump_datetime(load_datetime(value, format), format) == value
assert datetime(2009, 5, 13, 23, 19, 30, tzinfo=utc) \
    .astimezone(timezone('US/Eastern')) == load_datetime(value, format)
Tot answered 20/3, 2013 at 5:41 Comment(0)
A
5

One liner for old Pythons out there. You can multiply a timedelta by 1/-1 depending on +/- sign, as in:

datetime.strptime(s[:19], '%Y-%m-%dT%H:%M:%S') + timedelta(hours=int(s[20:22]), minutes=int(s[23:])) * (-1 if s[19] == '+' else 1)
Afterlife answered 3/11, 2017 at 14:19 Comment(0)
J
-10

If you are on Linux, then you can use the external date command to dwim:

import commands, datetime

def parsedate(text):
  output=commands.getoutput('date -d "%s" +%%s' % text )
  try:
      stamp=eval(output)
  except:
      print output
      raise
  return datetime.datetime.frometimestamp(stamp)

This is of course less portable than dateutil, but slightly more flexible, because date will also accept inputs like "yesterday" or "last year" :-)

Juglandaceous answered 9/7, 2009 at 3:21 Comment(5)
I don't think it is good to call an external programm for this. And the next weak point: eval(): If you now that a webserver executes this code, you could do arbitrary code execution on the server!Keturahkeung
It all depends on the context: if what we're after is only a write-and-throw-away script, then these weaknesses are just irrelevant :-)Juglandaceous
Down-voting this because: 1) It makes a system call for something trivial, 2) It injects strings directly into a shell call, 3) It calls eval(), and 4) It has an exception catch-all. Basically this is an example of how not to do things.Technic
In this case, though eval is evil and shouldn't be used. an external call seems to be the easiest and most practical way to get a unix timestamp from a timezone aware datestring, where the timezone is not a numeric offset.Ignaz
Well, again, this "eval is evil" motto really depends on your context (which was not stated by the OP). When I write scripts for my own use, I use eval liberally, and it's awesome. Python is a great language for glue scripts ! Of course you can roll out convoluted general-case over-engineered solutions like in some answers above, and then claim it's-the-only-right-way-to-do-it, ala Java. But for many use-cases a quick-and-dirty solution is just as good.Juglandaceous

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