Multiple if statements in a lambda function

Question

I am trying to use 3 if statements within a python lambda function. Here is my code:

y=lambda symbol: 'X' if symbol==True 'O' if symbol==False else ' '

I Have been able to get two if statements to work just fine e.g.

x=lambda cake: "Yum" if cake=="chocolate" else "Yuck"

Essentially, I want a lambda function to use if statements to return 'X' if the symbol is True, 'O' if it is false, and ' ' otherwise. I'm not even sure if this is even possible, but I haven't been able to find any information on the internet, so I would really appreciate any help :)

Sheff

If symbol is a boolean, it can only have two values. What could ever trip the last else? – Partly

@Partly almost anything which is not a boolean. – Acidimetry

@Acidimetry So the idea is that symbol could be of any type? – Partly

@Acidimetry is right, I have a list which contains True, False, or None. I want my code to convert None to ' ', so None would trip this else statement. I can understand why you might have found this confusing though, because it does seem like symbol is a Boolean without any context from the rest of my code. – Sheff

Answer 1

You are missing an else before 'O'. This works:

y = lambda symbol: 'X' if symbol==True else 'O' if symbol==False else ' '

However, I think you should stick to Adam Smith's approach. I find that easier to read.

Privative

Answer 2

You can use an anonymous dict inside your anonymous function to test for this, using the default value of dict.get to symbolize your final "else"

y = lambda sym: {False: 'X', True: 'Y'}.get(sym, ' ')

Froe

Thank you, this is very helpful. I ticked w0lf's answer, because it exactly answered my question, but your approach is definitely more pythonic and logical. – Sheff

@PM2Ring Whoops, right, because you're testing for equivalence to the value True and the value False, rather than testing for Truthyness or Falsyness. I'll edit – Froe

Answer 3

This is one way where you can try multiple if else in lambda function

Example,

largest_num = lambda a,b,c : a if a>b and a>c else b if b>a and b>c else c if c>a and c>b else a

largest_num(3,8,14) will return 14

Chondro