Replacing digits with str.replace()

Question

I want to make a new string by replacing digits with %d for example:

Name.replace( "_u1_v1" , "_u%d_v%d") 

...but the number 1 can be any digit for example "_u2_v2.tx"

Can I give replace() a wildcard to expect any digit? Like "_u"%d"_v"%d".tx"

Or do I have to make a regular expression?

Seismism

it doesn't make sense you are replacing a value with any digit. you have to define the digit. if you have some function that defines the digit or takes input, pass in the variable that holds the value. For instance, Name.replace("_u1_v1", "_u" + variableName + "_v" + variableName). – Embezzle

Answer 1

Using regular expressions:

>>> import re
>>> s = "_u1_v1"
>>> print re.sub('\d', '%d', s)
_u%d_v%d

\d matches any number 0-9. re.sub replaces the number(s) with %d

Hinduism

Answer 2

You cannot; str.replace() works with literal text only.

To replace patterns, use regular expressions:

re.sub(r'_u\d_v\d', '_u%d_v%d', inputtext)

Demo:

>>> import re
>>> inputtext = '42_u2_v3.txt'
>>> re.sub(r'_u\d_v\d', '_u%d_v%d', inputtext)
'42_u%d_v%d.txt'

Vinic

Answer 3

Just for variety, some non-regex approaches:

>>> s = "_u1_v1"
>>> ''.join("%d" if c.isdigit() else c for c in s)
'_u%d_v%d'

Or if you need to group multiple digits:

>>> from itertools import groupby, chain
>>> s = "_u1_v13"
>>> grouped = groupby(s, str.isdigit)
>>> ''.join(chain.from_iterable("%d" if k else g for k,g in grouped))
'_u%d_v%d'

(To be honest, though, while I'm generally anti-regex, this case is simple enough I'd probably use them.)

Puton

Answer 4

A solution using translate (source):

remove_digits = str.maketrans('0123456789', '%%%%%%%%%%')
'_u1_v1'.translate(remove_digits)  # '_u%_v%'

Undergo

Answer 5

If you want to delete all digits in the string you can do using translate (Removing numbers from string):

from string import digits
remove_digits = str.maketrans('', '', digits)
str = str.translate(remove_digits)

All credit goes to @LoMaPh

Rectangle

Answer 6

temp = re.findall(r'\d+', text) 
res = list(map(int, temp))

for numText in res:
    text = text.replace(str(numText), str(numText)+'U')

Bannasch

Can you please explain your solution? – Via

It would be helpful if you added some clarifying description of the solution you have suggested, instead of only providing code. Code can stand alone, but it's always better when you explain why you do something, instead of just how. Read more about writing a good answer here: stackoverflow.com/help/how-to-answer – Turgot