How can I convert a float
value to char*
in C
language?
char buffer[64];
int ret = snprintf(buffer, sizeof buffer, "%f", myFloat);
if (ret < 0) {
return EXIT_FAILURE;
}
if (ret >= sizeof buffer) {
/* Result was truncated - resize the buffer and retry.
}
That will store the string representation of myFloat
in myCharPointer
. Make sure that the string is large enough to hold it, though.
snprintf
is a better option than sprintf
as it guarantees it will never write past the size of the buffer you supply in argument 2.
In Arduino:
//temporarily holds data from vals
char charVal[10];
//4 is mininum width, 3 is precision; float value is copied onto buff
dtostrf(123.234, 4, 3, charVal);
monitor.print("charVal: ");
monitor.println(charVal);
char array[10];
sprintf(array, "%f", 3.123);
sprintf: (from MSDN)
Long after accept answer.
Use sprintf()
, or related functions, as many others have answers suggested, but use a better format specifier.
Using "%.*e"
, code solves various issues:
The maximum buffer size needed is far more reasonable with
"%.*e"
, like 18 forfloat
(see below). With"%f"
, (think fixed-point),sprintf(buf, "%f", FLT_MAX);
could need 47+char
.sprintf(buf, "%f", DBL_MAX);
may need 317+char
.Using
".*"
allows code to define the number of decimal places needed to distinguish a string version offloat x
and it next highestfloat
. For details, see printf width specifier to maintain precision of floating-point valueUsing
"%e"
allows code to distinguish smallfloat
s from each other rather than all printing"0.000000"
which is the result when|x| < 0.0000005
with"%f"
.
Example usage:
#include <float.h>
#define FLT_STRING_SIZE (1+1+1+(FLT_DECIMAL_DIG-1)+1+1+ 4 +1)
// - d . dddddddd e - dddd \0
char buf[FLT_STRING_SIZE];
sprintf(buf, "%.*e", FLT_DECIMAL_DIG-1, some_float);
Ideas:
IMO, better to use 2x buffer size for scratch pads like buf[FLT_STRING_SIZE*2]
.
For added robustness, use snprintf()
.
As a 2nd alterative consider "%.*g"
. It is like "%f"
for values exponentially near 1.0 and like "%e"
for others.
char* str=NULL;
int len = asprintf(&str, "%g", float_var);
if (len == -1)
fprintf(stderr, "Error converting float: %m\n");
else
printf("float is %s\n", str);
free(str);
typedef union{
float a;
char b[4];
} my_union_t;
You can access to float data value byte by byte and send it through 8-bit output buffer (e.g. USART) without casting.
unsigned char
is highly advisable for the array in this union. –
Mare char array[10];
snprintf(array, sizeof(array), "%f", 3.333333);
// float arr to bytes
int arr_len = 3;
float x[3] = {1.123, 2.123, 3.123};
char* bytes = new char[arr_len * sizeof(float)];
memcpy(bytes, x, arr_len * sizeof(float));
// bytes to float arr
float y[3];
memcpy(y, bytes, arr_len * sizeof(float));
Convert float to binary via ascii codes
float u = 2.154328
string s = to_string(u);
char* p = (char*) s;
This stores the characters, 2, .,1, 5, ..., or in binary 00000010,00101110, 00000001, ...
C
. –
Zeist © 2022 - 2024 — McMap. All rights reserved.