How to append text to an existing file in Java?
Asked Answered
R

31

779

I need to append text repeatedly to an existing file in Java. How do I do that?

Roughrider answered 26/10, 2009 at 14:43 Comment(0)
D
925

Are you doing this for logging purposes? If so there are several libraries for this. Two of the most popular are Log4j and Logback.

Java 7+

For a one-time task, the Files class makes this easy:

try {
    Files.write(Paths.get("myfile.txt"), "the text".getBytes(), StandardOpenOption.APPEND);
}catch (IOException e) {
    //exception handling left as an exercise for the reader
}

Careful: The above approach will throw a NoSuchFileException if the file does not already exist. It also does not append a newline automatically (which you often want when appending to a text file). Another approach is to pass both CREATE and APPEND options, which will create the file first if it doesn't already exist:

private void write(final String s) throws IOException {
    Files.writeString(
        Path.of(System.getProperty("java.io.tmpdir"), "filename.txt"),
        s + System.lineSeparator(),
        CREATE, APPEND
    );
}

However, if you will be writing to the same file many times, the above snippets must open and close the file on the disk many times, which is a slow operation. In this case, a BufferedWriter is faster:

try(FileWriter fw = new FileWriter("myfile.txt", true);
    BufferedWriter bw = new BufferedWriter(fw);
    PrintWriter out = new PrintWriter(bw))
{
    out.println("the text");
    //more code
    out.println("more text");
    //more code
} catch (IOException e) {
    //exception handling left as an exercise for the reader
}

Notes:

  • The second parameter to the FileWriter constructor will tell it to append to the file, rather than writing a new file. (If the file does not exist, it will be created.)
  • Using a BufferedWriter is recommended for an expensive writer (such as FileWriter).
  • Using a PrintWriter gives you access to println syntax that you're probably used to from System.out.
  • But the BufferedWriter and PrintWriter wrappers are not strictly necessary.

Older Java

try {
    PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter("myfile.txt", true)));
    out.println("the text");
    out.close();
} catch (IOException e) {
    //exception handling left as an exercise for the reader
}

Exception Handling

If you need robust exception handling for older Java, it gets very verbose:

FileWriter fw = null;
BufferedWriter bw = null;
PrintWriter out = null;
try {
    fw = new FileWriter("myfile.txt", true);
    bw = new BufferedWriter(fw);
    out = new PrintWriter(bw);
    out.println("the text");
    out.close();
} catch (IOException e) {
    //exception handling left as an exercise for the reader
}
finally {
    try {
        if(out != null)
            out.close();
    } catch (IOException e) {
        //exception handling left as an exercise for the reader
    }
    try {
        if(bw != null)
            bw.close();
    } catch (IOException e) {
        //exception handling left as an exercise for the reader
    }
    try {
        if(fw != null)
            fw.close();
    } catch (IOException e) {
        //exception handling left as an exercise for the reader
    }
}
Delay answered 26/10, 2009 at 14:47 Comment(20)
You should either use java7 try-with-resources or put the close() in a finally block, in order to make sure that the file is closed in case of exceptionNostology
Lets imagine that new BufferedWriter(...) throws an exception; Will the FileWriter be closed ? I guess that it will not be closed, because the close() method (in normal conditions) will be invoked on the out object, which int this case will not be initialized - so actually the close() method will not be invoked -> the file will be opened, but will not be closed. So IMHO the try statement should look like this try(FileWriter fw = new FileWriter("myFile.txt")){ Print writer = new ....//code goes here } And he should flush() the writer before exiting the try block!!!Nostology
it's not work for me. in destination file, there is one "test" and many empty spaceEnsile
If you use Java 7+, then why not use a simple Files.write instead of a PrintWriter of a BufferedWriter of a FileWriter?Kelci
This answer fails to correctly handle exceptions. See @Emily's answer for proper way.Petty
Why is FileWriter treated like expensive writer?Wear
@Wear Because it has to do disk I/O operations. In the JavaDoc for BufferedWriter, it says "In general, a Writer sends its output immediately to the underlying character or byte stream. Unless prompt output is required, it is advisable to wrap a BufferedWriter around any Writer whose write() operations may be costly, such as FileWriters and OutputStreamWriters"Delay
This can be done in one line of code. Hope this helps :) Files.write(Paths.get(fileName), msg.getBytes(), StandardOpenOption.APPEND);Ruberta
The File and filename-based constructors of PrintWriter mention that they buffer automatically. But when a PrintWriter wraps another Writer, there is no comment in the docs on whether it adds another layer of buffering or not. Given the ambiguity, it seems best to include a BufferedWriter explicitly, as in this answer.Cologne
@Decoded your suggested edit was a syntax error. out is only defined in the try block. In the finally block it does not exist. You would have to move the declaration of out out of the try block. This is exactly the problem that the Java 7+ syntax resolves. As I've noted, I've left exception handling for the reader; I think it's beyond the scope of this answer.Delay
You should close only the out variable! #485425Buddhism
A couple of possible "gotchas" with the Java 7 method: (1) If the file doesn't already exist, StandardOpenOption.APPEND won't create it - kind of like a silent failure as it won't throw an exception either. (2) Using .getBytes() will mean there is no return character before or after the appended text. Have added an alternative answer to address these.Cove
@SteveChambers Thanks for the input. I couldn't believe that append mode does not create the file if it does not exist, so I had to try it to confirm. Not sure what they were thinking there... I found that it does actually throw an exception, but if you copy/paste my code and leave the catch block blank, then you don't see it. I've updated my answer to reflect these issues and I added a link to your answer.Delay
Is it safe to use the faster, buffered operations? I'm trying to log something that happens right before a crash, and I need to make sure the file is going to get written.Pileup
@Pileup when the buffered writer is closed, it will write whatever is in the buffer. Or you can explicitly call flush() to force it to flush its buffer (writing the contents) immediately.Delay
"If you need robust exception handling for older Java, it gets very verbose." If by "verbose" you mean "a horrifying abomination".Saltcellar
This works in Scala as well: try { Files.write(Paths.get("myfile.txt"), "the text".getBytes(), StandardOpenOption.APPEND) } catch { case ioe: IOException => { println("IOException thrown!") } case e: Exception => println("Non-IOException thrown!") }Antabuse
The Files.writeString() and Path.of() are both no symbol error, is it a typo?Lewallen
@Lewallen it worked when i wrote the answer but i haven't done any serious java development in quite a long time 🤷Delay
"Log4j" Haha, that part certainly didn't age well.Violinist
T
201

You can use fileWriter with a flag set to true , for appending.

try
{
    String filename= "MyFile.txt";
    FileWriter fw = new FileWriter(filename,true); //the true will append the new data
    fw.write("add a line\n");//appends the string to the file
    fw.close();
}
catch(IOException ioe)
{
    System.err.println("IOException: " + ioe.getMessage());
}
Teaser answered 26/10, 2009 at 14:48 Comment(6)
close should be placed in finally block just like shown in @etech's answer in case exception would be thrown between creation of FileWriter and invoking close.Polynices
Good answer, although its better to use System.getProperty( "line.separator" ) for a new line rather than "\n".Purehearted
@Decoded I've rolled back your edit on this answer, as it does not compile.Delay
@Kip, What was the issue? I must have entered a "typo".Sussi
@Sussi you had fw.close() in a finally block, without a nested try/catch (.close() can throw IOException)Delay
How bout try-with-resources? try(FileWriter fw = new FileWriter(filename,true)){ // Whatever }catch(IOException ex){ ex.printStackTrace(); } Cardenas
P
75

Shouldn't all of the answers here with try/catch blocks have the .close() pieces contained in a finally block?

Example for marked answer:

PrintWriter out = null;
try {
    out = new PrintWriter(new BufferedWriter(new FileWriter("writePath", true)));
    out.println("the text");
} catch (IOException e) {
    System.err.println(e);
} finally {
    if (out != null) {
        out.close();
    }
} 

Also, as of Java 7, you can use a try-with-resources statement. No finally block is required for closing the declared resource(s) because it is handled automatically, and is also less verbose:

try(PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter("writePath", true)))) {
    out.println("the text");
} catch (IOException e) {
    System.err.println(e);
}
Polar answered 24/2, 2013 at 15:48 Comment(5)
When out goes out of scope, it is automatically closed when it gets garbage-collected, right? In your example with the finally block, I think you actually need another nested try/catch around out.close() if I remember correctly. The Java 7 solution is pretty slick! (I haven't been doing any Java dev since Java 6, so I was unfamiliar with that change.)Delay
@Delay Nope, going out-of-scope does nothing in Java. The file will get closed at some random time in the future. (probably when the program closes)Shaitan
@Polar Will the second approach need the flush method?Asthenopia
This is not an answer to the question, it is a comment on the other answers, and the code provided does not compile.Gahl
@Asthenopia No. Close calls flush.Gahl
P
52

Using Apache Commons 2.1:

import org.apache.logging.log4j.core.util.FileUtils;

FileUtils.writeStringToFile(file, "String to append", true);
Procora answered 3/12, 2010 at 13:41 Comment(4)
Oh, thank you. I was amused by the complexity of all other answers. I really do not get why people like to complicate their (developer) life.Dalia
The problem with this approach is that it opens and closes the output stream every single time. Depending on what and how often you write to your file, this could result in a ridiculous overhead.Tympanitis
@Tympanitis is right. But you can always use StringBuilder for building large chunks (that are worth writing) before writing them to file.Horsemanship
@KonstantinK but then all the content you need to write is loaded into memory.Turley
C
37

Slightly expanding on Kip's answer, here is a simple Java 7+ method to append a new line to a file, creating it if it doesn't already exist:

try {
    final Path path = Paths.get("path/to/filename.txt");
    Files.write(path, Arrays.asList("New line to append"), StandardCharsets.UTF_8,
        Files.exists(path) ? StandardOpenOption.APPEND : StandardOpenOption.CREATE);
} catch (final IOException ioe) {
    // Add your own exception handling...
}

Further notes:

  1. The above uses the Files.write overload that writes lines of text to a file (i.e. similar to a println command). To just write text to the end (i.e. similar to a print command), an alternative Files.write overload can be used, passing in a byte array (e.g. "mytext".getBytes(StandardCharsets.UTF_8)).

  2. The CREATE option will only work if the specified directory already exists - if it doesn't, a NoSuchFileException is thrown. If required, the following code could be added after setting path to create the directory structure:

    Path pathParent = path.getParent();
    if (!Files.exists(pathParent)) {
        Files.createDirectories(pathParent);
    }
    
Cove answered 1/6, 2017 at 8:3 Comment(3)
Do you need to check if the file exists? I thought.CREATE does the job for you.Immunogenic
If .CREATE is used when the file already exists it silently fails to append anything - no exception is thrown but the existing file contents remain unchanged.Cove
Using APPEND + CREATE works perfectly, no check necessary: Files.write(Paths.get("test.log"), (Instant.now().toString() + "\r\n").getBytes(), StandardOpenOption.CREATE, StandardOpenOption.APPEND);Stele
G
22

Make sure the stream gets properly closed in all scenarios.

It's a bit alarming how many of these answers leave the file handle open in case of an error. The answer https://mcmap.net/q/53921/-how-to-append-text-to-an-existing-file-in-java is on the money but only because BufferedWriter() cannot throw. If it could then an exception would leave the FileWriter object open.

A more general way of doing this that doesn't care if BufferedWriter() can throw:

  PrintWriter out = null;
  BufferedWriter bw = null;
  FileWriter fw = null;
  try{
     fw = new FileWriter("outfilename", true);
     bw = new BufferedWriter(fw);
     out = new PrintWriter(bw);
     out.println("the text");
  }
  catch( IOException e ){
     // File writing/opening failed at some stage.
  }
  finally{
     try{
        if( out != null ){
           out.close(); // Will close bw and fw too
        }
        else if( bw != null ){
           bw.close(); // Will close fw too
        }
        else if( fw != null ){
           fw.close();
        }
        else{
           // Oh boy did it fail hard! :3
        }
     }
     catch( IOException e ){
        // Closing the file writers failed for some obscure reason
     }
  }

Edit:

As of Java 7, the recommended way is to use "try with resources" and let the JVM deal with it:

  try(    FileWriter fw = new FileWriter("outfilename", true);
          BufferedWriter bw = new BufferedWriter(fw);
          PrintWriter out = new PrintWriter(bw)){
     out.println("the text");
  }  
  catch( IOException e ){
      // File writing/opening failed at some stage.
  }
Goodnight answered 11/9, 2013 at 16:50 Comment(4)
+1 for correct ARM with Java 7. Here is good question about this tricky theme: #12553363.Petty
Hmm, for some reason PrintWriter.close() is not declared as throws IOException in the docs. Looking at its source, the close() method, indeed, cannot throw IOException, because it catches it from the underlying stream, and sets a flag. So if you're working on the code for the next Space Shuttle or an X-ray dose metering system, you should use PrintWriter.checkError() after attempting to out.close(). This should really have been documented.Cologne
If we're going to be super paranoid about closing, each of those XX.close() should be in its own try/catch, right? For example, out.close() could throw an exception, in which case bw.close() and fw.close() would never get called, and fw is the one that is most critical to close.Delay
’ButferedWriter’ can throw.Gahl
P
13

In Java-7 it also can be done such kind:

import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.nio.file.StandardOpenOption;

//---------------------

Path filePath = Paths.get("someFile.txt");
if (!Files.exists(filePath)) {
    Files.createFile(filePath);
}
Files.write(filePath, "Text to be added".getBytes(), StandardOpenOption.APPEND);
Peterman answered 5/4, 2015 at 11:3 Comment(2)
What are the imports required? Which library do these things use?Biannual
The exists/create part is literally a waste of time and space.Gahl
O
13

java 7+

In my humble opinion since I am fan of plain java, I would suggest something that it is a combination of the aforementioned answers. Maybe I am late for the party. Here is the code:

 String sampleText = "test" +  System.getProperty("line.separator");
 Files.write(Paths.get(filePath), sampleText.getBytes(StandardCharsets.UTF_8), 
 StandardOpenOption.CREATE, StandardOpenOption.APPEND);

If the file doesn't exist, it creates it and if already exists it appends the sampleText to the existing file. Using this, saves you from adding unnecessary libs to your classpath.

Opposition answered 9/2, 2018 at 6:59 Comment(0)
R
9

This can be done in one line of code. Hope this helps :)

Files.write(Paths.get(fileName), msg.getBytes(), StandardOpenOption.APPEND);
Ruberta answered 6/8, 2015 at 17:38 Comment(1)
its may be not enough:) better version is Files.write(Paths.get(fileName), msg.getBytes(), StandardOpenOption.APPEND, StandardOpenOption.CREATE);Corlisscorly
I
5

I just add small detail:

    new FileWriter("outfilename", true)

2.nd parameter (true) is a feature (or, interface) called appendable (http://docs.oracle.com/javase/7/docs/api/java/lang/Appendable.html). It is responsible for being able to add some content to the end of particular file/stream. This interface is implemented since Java 1.5. Each object (i.e. BufferedWriter, CharArrayWriter, CharBuffer, FileWriter, FilterWriter, LogStream, OutputStreamWriter, PipedWriter, PrintStream, PrintWriter, StringBuffer, StringBuilder, StringWriter, Writer) with this interface can be used for adding content

In other words, you can add some content to your gzipped file, or some http process

Influence answered 13/12, 2012 at 10:56 Comment(0)
M
5

Using java.nio.Files along with java.nio.file.StandardOpenOption

    PrintWriter out = null;
    BufferedWriter bufWriter;

    try{
        bufWriter =
            Files.newBufferedWriter(
                Paths.get("log.txt"),
                Charset.forName("UTF8"),
                StandardOpenOption.WRITE, 
                StandardOpenOption.APPEND,
                StandardOpenOption.CREATE);
        out = new PrintWriter(bufWriter, true);
    }catch(IOException e){
        //Oh, no! Failed to create PrintWriter
    }

    //After successful creation of PrintWriter
    out.println("Text to be appended");

    //After done writing, remember to close!
    out.close();

This creates a BufferedWriter using Files, which accepts StandardOpenOption parameters, and an auto-flushing PrintWriter from the resultant BufferedWriter. PrintWriter's println() method, can then be called to write to the file.

The StandardOpenOption parameters used in this code: opens the file for writing, only appends to the file, and creates the file if it does not exist.

Paths.get("path here") can be replaced with new File("path here").toPath(). And Charset.forName("charset name") can be modified to accommodate the desired Charset.

Mcclurg answered 20/7, 2013 at 19:6 Comment(0)
U
4

Sample, using Guava:

File to = new File("C:/test/test.csv");

for (int i = 0; i < 42; i++) {
    CharSequence from = "some string" + i + "\n";
    Files.append(from, to, Charsets.UTF_8);
}
Unclassified answered 4/6, 2013 at 19:17 Comment(2)
This is horrible advice. You open a stream to the file 42 times instead of once.Toro
@Toro well, it depends. 42 is still ok, if it makes code much more readable. 42k wouldn't be acceptable.Unclassified
D
4
FileOutputStream fos = new FileOutputStream("File_Name", true);
fos.write(data);

the true allows to append the data in the existing file. If we will write

FileOutputStream fos = new FileOutputStream("File_Name");

It will overwrite the existing file. So go for first approach.

Denmark answered 7/8, 2015 at 7:45 Comment(0)
B
4
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;

public class Writer {


    public static void main(String args[]){
        doWrite("output.txt","Content to be appended to file");
    }

    public static void doWrite(String filePath,String contentToBeAppended){

       try(
            FileWriter fw = new FileWriter(filePath, true);
            BufferedWriter bw = new BufferedWriter(fw);
            PrintWriter out = new PrintWriter(bw)
          )
          {
            out.println(contentToBeAppended);
          }  
        catch( IOException e ){
        // File writing/opening failed at some stage.
        }

    }

}
Blarney answered 15/2, 2017 at 14:53 Comment(1)
The above is just a quick example implementation of the solution presented At this link. So you can copy and and run the code and immediately see how it works, be sure that the output.out file is in the same directory as the Writer.java fileBlarney
S
3
    String str;
    String path = "C:/Users/...the path..../iin.txt"; // you can input also..i created this way :P

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    PrintWriter pw = new PrintWriter(new FileWriter(path, true));

    try 
    {
       while(true)
        {
            System.out.println("Enter the text : ");
            str = br.readLine();
            if(str.equalsIgnoreCase("exit"))
                break;
            else
                pw.println(str);
        }
    } 
    catch (Exception e) 
    {
        //oh noes!
    }
    finally
    {
        pw.close();         
    }

this will do what you intend for..

Springbok answered 7/1, 2013 at 14:56 Comment(0)
P
3

You can also try this :

JFileChooser c= new JFileChooser();
c.showOpenDialog(c);
File write_file = c.getSelectedFile();
String Content = "Writing into file"; //what u would like to append to the file



try 
{
    RandomAccessFile raf = new RandomAccessFile(write_file, "rw");
    long length = raf.length();
    //System.out.println(length);
    raf.setLength(length + 1); //+ (integer value) for spacing
    raf.seek(raf.length());
    raf.writeBytes(Content);
    raf.close();
} 
catch (Exception e) {
    //any exception handling method of ur choice
}
Princely answered 29/6, 2014 at 12:35 Comment(0)
E
3

Better to use try-with-resources then all that pre-java 7 finally business

static void appendStringToFile(Path file, String s) throws IOException  {
    try (BufferedWriter out = Files.newBufferedWriter(file, StandardCharsets.UTF_8, StandardOpenOption.APPEND)) {
        out.append(s);
        out.newLine();
    }
}
Eisegesis answered 21/8, 2014 at 10:35 Comment(0)
F
3

Try with bufferFileWriter.append, it works with me.

FileWriter fileWriter;
try {
    fileWriter = new FileWriter(file,true);
    BufferedWriter bufferFileWriter = new BufferedWriter(fileWriter);
    bufferFileWriter.append(obj.toJSONString());
    bufferFileWriter.newLine();
    bufferFileWriter.close();
} catch (IOException ex) {
    Logger.getLogger(JsonTest.class.getName()).log(Level.SEVERE, null, ex);
}
Farming answered 27/5, 2015 at 11:17 Comment(3)
what is obj.toJSONString() here?Jews
@BhaskaraArani It's just a string, he put an example of a JSON object converted to a string but the idea is that it could be any string.Loudmouthed
It is the ’true` parameter that is doing the appending here, not ’BufferedWriter`.Gahl
D
3

If we are using Java 7 and above and also know the content to be added (appended) to the file we can make use of newBufferedWriter method in NIO package.

public static void main(String[] args) {
    Path FILE_PATH = Paths.get("C:/temp", "temp.txt");
    String text = "\n Welcome to Java 8";

    //Writing to the file temp.txt
    try (BufferedWriter writer = Files.newBufferedWriter(FILE_PATH, StandardCharsets.UTF_8, StandardOpenOption.APPEND)) {
        writer.write(text);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

There are few points to note:

  1. It is always a good habit to specify charset encoding and for that we have constant in class StandardCharsets.
  2. The code uses try-with-resource statement in which resources are automatically closed after the try.

Though OP has not asked but just in case we want to search for lines having some specific keyword e.g. confidential we can make use of stream APIs in Java:

//Reading from the file the first line which contains word "confidential"
try {
    Stream<String> lines = Files.lines(FILE_PATH);
    Optional<String> containsJava = lines.filter(l->l.contains("confidential")).findFirst();
    if(containsJava.isPresent()){
        System.out.println(containsJava.get());
    }
} catch (IOException e) {
    e.printStackTrace();
}
Darkling answered 22/6, 2015 at 8:43 Comment(1)
a caveat: when using BufferedWriter write(String string) if one expects a new line after each string written, newLine() should be calledPox
P
2
FileOutputStream stream = new FileOutputStream(path, true);
try {

    stream.write(

        string.getBytes("UTF-8") // Choose your encoding.

    );

} finally {
    stream.close();
}

Then catch an IOException somewhere upstream.

Pitiful answered 18/6, 2013 at 15:21 Comment(0)
A
2

Create a function anywhere in your project and simply call that function where ever you need it.

Guys you got to remember that you guys are calling active threads that you are not calling asynchronously and since it would likely be a good 5 to 10 pages to get it done right. Why not spend more time on your project and forget about writing anything already written. Properly

    //Adding a static modifier would make this accessible anywhere in your app

    public Logger getLogger()
    {
       return java.util.logging.Logger.getLogger("MyLogFileName");
    }
    //call the method anywhere and append what you want to log 
    //Logger class will take care of putting timestamps for you
    //plus the are ansychronously done so more of the 
    //processing power will go into your application

    //from inside a function body in the same class ...{...

    getLogger().log(Level.INFO,"the text you want to append");

    ...}...
    /*********log file resides in server root log files********/

three lines of code two really since the third actually appends text. :P

Acciaccatura answered 2/1, 2014 at 10:39 Comment(0)
L
2

Library

import java.io.BufferedWriter;
import java.io.File;
import java.io.FileWriter;
import java.io.IOException;

Code

public void append()
{
    try
    {
        String path = "D:/sample.txt";

        File file = new File(path);

        FileWriter fileWriter = new FileWriter(file,true);

        BufferedWriter bufferFileWriter  = new BufferedWriter(fileWriter);

        fileWriter.append("Sample text in the file to append");

        bufferFileWriter.close();

        System.out.println("User Registration Completed");

    }catch(Exception ex)
    {
        System.out.println(ex);
    }
}
Lattimer answered 24/3, 2014 at 12:36 Comment(0)
P
1

I might suggest the apache commons project. This project already provides a framework for doing what you need (i.e. flexible filtering of collections).

Petiolate answered 6/8, 2013 at 4:58 Comment(0)
A
1

This code will fulifil your need:

   FileWriter fw=new FileWriter("C:\\file.json",true);
   fw.write("ssssss");
   fw.close();
Accountable answered 27/12, 2015 at 9:10 Comment(2)
docs.oracle.com/javase/7/docs/api/java/io/…Crumple
@WestCoastProjects No it won’t, it will append.Gahl
M
1

In case you want to ADD SOME TEXT IN SPECIFIC LINES you can first read the whole file, append the text wherever you want and then overwrite everything like in the code below:

public static void addDatatoFile(String data1, String data2){


    String fullPath = "/home/user/dir/file.csv";

    File dir = new File(fullPath);
    List<String> l = new LinkedList<String>();

    try (BufferedReader br = new BufferedReader(new FileReader(dir))) {
        String line;
        int count = 0;

        while ((line = br.readLine()) != null) {
            if(count == 1){
                //add data at the end of second line                    
                line += data1;
            }else if(count == 2){
                //add other data at the end of third line
                line += data2;
            }
            l.add(line);
            count++;
        }
        br.close();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }       
    createFileFromList(l, dir);
}

public static void createFileFromList(List<String> list, File f){

    PrintWriter writer;
    try {
        writer = new PrintWriter(f, "UTF-8");
        for (String d : list) {
            writer.println(d.toString());
        }
        writer.close();             
    } catch (FileNotFoundException | UnsupportedEncodingException e) {
        e.printStackTrace();
    }
}
Mesosphere answered 19/9, 2016 at 13:2 Comment(0)
P
0

The following method let's you append text to some file:

private void appendToFile(String filePath, String text)
{
    PrintWriter fileWriter = null;

    try
    {
        fileWriter = new PrintWriter(new BufferedWriter(new FileWriter(
                filePath, true)));

        fileWriter.println(text);
    } catch (IOException ioException)
    {
        ioException.printStackTrace();
    } finally
    {
        if (fileWriter != null)
        {
            fileWriter.close();
        }
    }
}

Alternatively using FileUtils:

public static void appendToFile(String filePath, String text) throws IOException
{
    File file = new File(filePath);

    if(!file.exists())
    {
        file.createNewFile();
    }

    String fileContents = FileUtils.readFileToString(file);

    if(file.length() != 0)
    {
        fileContents = fileContents.concat(System.lineSeparator());
    }

    fileContents = fileContents.concat(text);

    FileUtils.writeStringToFile(file, fileContents);
}

It is not efficient but works fine. Line breaks are handled correctly and a new file is created if one didn't exist yet.

Persiflage answered 18/4, 2015 at 18:26 Comment(1)
The exists/create part is literally a waste of time and space.Gahl
E
0

For JDK version >= 7

You can utilise this simple method which appends the given content to the specified file:

void appendToFile(String filePath, String content) {
  try (FileWriter fw = new FileWriter(filePath, true)) {
    fw.write(content + System.lineSeparator());
  } catch (IOException e) { 
    // TODO handle exception
  }
}

We are constructing a FileWriter object in append mode.

Etheleneethelin answered 7/7, 2020 at 13:46 Comment(0)
D
-1

My answer:

JFileChooser chooser= new JFileChooser();
chooser.showOpenDialog(chooser);
File file = chooser.getSelectedFile();
String Content = "What you want to append to file";

try 
{
    RandomAccessFile random = new RandomAccessFile(file, "rw");
    long length = random.length();
    random.setLength(length + 1);
    random.seek(random.length());
    random.writeBytes(Content);
    random.close();
} 
catch (Exception exception) {
    //exception handling
}
Damn answered 29/7, 2015 at 13:39 Comment(0)
C
-1
/**********************************************************************
 * it will write content to a specified  file
 * 
 * @param keyString
 * @throws IOException
 *********************************************************************/
public static void writeToFile(String keyString,String textFilePAth) throws IOException {
    // For output to file
    File a = new File(textFilePAth);

    if (!a.exists()) {
        a.createNewFile();
    }
    FileWriter fw = new FileWriter(a.getAbsoluteFile(), true);
    BufferedWriter bw = new BufferedWriter(fw);
    bw.append(keyString);
    bw.newLine();
    bw.close();
}// end of writeToFile()
Chap answered 13/7, 2016 at 12:23 Comment(1)
The exists/create part is literally a waste of time and space.Gahl
G
-1

You can use the follong code to append the content in the file:

 String fileName="/home/shriram/Desktop/Images/"+"test.txt";
  FileWriter fw=new FileWriter(fileName,true);    
  fw.write("here will be you content to insert or append in file");    
  fw.close(); 
  FileWriter fw1=new FileWriter(fileName,true);    
 fw1.write("another content will be here to be append in the same file");    
 fw1.close(); 
Graphomotor answered 4/10, 2017 at 12:38 Comment(0)
R
-1

1.7 Approach:

void appendToFile(String filePath, String content) throws IOException{

    Path path = Paths.get(filePath);

    try (BufferedWriter writer = 
            Files.newBufferedWriter(path, 
                    StandardOpenOption.APPEND)) {
        writer.newLine();
        writer.append(content);
    }

    /*
    //Alternative:
    try (BufferedWriter bWriter = 
            Files.newBufferedWriter(path, 
                    StandardOpenOption.WRITE, StandardOpenOption.APPEND);
            PrintWriter pWriter = new PrintWriter(bWriter)
            ) {
        pWriter.println();//to have println() style instead of newLine();   
        pWriter.append(content);//Also, bWriter.append(content);
    }*/
}
Rotten answered 27/5, 2018 at 11:34 Comment(0)

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