Pretty-Printing JSON with PHP
Asked Answered
P

27

791

I'm building a PHP script that feeds JSON data to another script. My script builds data into a large associative array, and then outputs the data using json_encode. Here is an example script:

$data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');
header('Content-type: text/javascript');
echo json_encode($data);

The above code yields the following output:

{"a":"apple","b":"banana","c":"catnip"}

This is great if you have a small amount of data, but I'd prefer something along these lines:

{
    "a": "apple",
    "b": "banana",
    "c": "catnip"
}

Is there a way to do this in PHP without an ugly hack? It seems like someone at Facebook figured it out.

Pint answered 19/5, 2011 at 5:8 Comment(4)
For PHP before 5.4, you can use the fallback in upgradephp as up_json_encode($data, JSON_PRETTY_PRINT);Excursion
use of header('Content-Type: application/json'); makes browser pretty printStamm
As of Juy 2018, just by sending the Content-Type: application/json header Firefox will show the result using its own internal JSON parser, while Chrome shows the plain text. +1 Firefox!Vesicatory
Are you outputting your json data? Is this for debug purpose? I usually use <pre>print_all(arr)</pre> when debugging on the browser side you can do JSON.parse if needed :-)Esse
D
1501

PHP 5.4 offers the JSON_PRETTY_PRINT option for use with the json_encode() call.

https://php.net/manual/en/function.json-encode.php

<?php
...
$json_string = json_encode($data, JSON_PRETTY_PRINT);
Dyun answered 2/2, 2012 at 22:20 Comment(12)
Thanks, this is the best way to do it now. I didn't have php 5.4 back when I asked this question though...Pint
5.5.3 here, just seems to add a bit of spacing between the characters, not any actual indenting.Ophelia
JSON isn't supposed to contain HTML line breaks, whereas newline characters are valid in JSON. If you want to display JSON on a web page then do a string replacement on the newline characters yourself or else put the JSON in a <pre>...</pre> element. See json.org for the syntax reference.Dyun
One thing about this is you need the data as an array. I find @Kendall's answer is useful if you're starting out with a json string that needs to be formatted.Geffner
@Geffner That's what the json_decode function is for. There's really no need to rewrite functionality that's built into the language.Dyun
Not really, since you'd need to decode, then encode just to get pretty printing, which is a waste of CPU... That's why @Kendall's answer is useful when you're starting out with a string.Geffner
Don't forget to set response Content-Type to application/json if you want browser to display pretty-printed JSON nicely.Parent
@countfloortiles it won't work directly you need to enclose your output in <pre> tag like <?php ... $json_string = json_encode($data, JSON_PRETTY_PRINT); echo "<pre>".$json_string."<pre>";Sorrows
can i get JSON_PRETTY_PRINT with 2 space instead if 4 space?Phenobarbital
@AdiPrasetyo: Looks like you'll need to process the string after pretty printing in order to change the whitespace: php.net/manual/en/function.json-encode.php#118334Dyun
That's a really cool feature! Not a big reason to use PHP, but this makes me eager to use PHP more!Mur
You can also leave Unicode unescaped, like this: json_encode($data, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE)Nan
O
202

This function will take JSON string and indent it very readable. It also should be convergent,

prettyPrint( $json ) === prettyPrint( prettyPrint( $json ) )

Input

{"key1":[1,2,3],"key2":"value"}

Output

{
    "key1": [
        1,
        2,
        3
    ],
    "key2": "value"
}

Code

function prettyPrint( $json )
{
    $result = '';
    $level = 0;
    $in_quotes = false;
    $in_escape = false;
    $ends_line_level = NULL;
    $json_length = strlen( $json );

    for( $i = 0; $i < $json_length; $i++ ) {
        $char = $json[$i];
        $new_line_level = NULL;
        $post = "";
        if( $ends_line_level !== NULL ) {
            $new_line_level = $ends_line_level;
            $ends_line_level = NULL;
        }
        if ( $in_escape ) {
            $in_escape = false;
        } else if( $char === '"' ) {
            $in_quotes = !$in_quotes;
        } else if( ! $in_quotes ) {
            switch( $char ) {
                case '}': case ']':
                    $level--;
                    $ends_line_level = NULL;
                    $new_line_level = $level;
                    break;

                case '{': case '[':
                    $level++;
                case ',':
                    $ends_line_level = $level;
                    break;

                case ':':
                    $post = " ";
                    break;

                case " ": case "\t": case "\n": case "\r":
                    $char = "";
                    $ends_line_level = $new_line_level;
                    $new_line_level = NULL;
                    break;
            }
        } else if ( $char === '\\' ) {
            $in_escape = true;
        }
        if( $new_line_level !== NULL ) {
            $result .= "\n".str_repeat( "\t", $new_line_level );
        }
        $result .= $char.$post;
    }

    return $result;
}
Orland answered 19/3, 2012 at 19:39 Comment(0)
C
130

Many users suggested that you use

echo json_encode($results, JSON_PRETTY_PRINT);

Which is absolutely right. But it's not enough, the browser needs to understand the type of data, you can specify the header just before echo-ing the data back to the user.

header('Content-Type: application/json');

This will result in a well formatted output.

Or, if you like extensions you can use JSONView for Chrome.

Chimp answered 27/7, 2016 at 18:1 Comment(2)
Only set the header and Firefox will show it perfectly using its own internal JSON debugging parser, no need to touch the JSON contents at all! Thank you!!Vesicatory
Using a chromium browser with a JSON prettifier extension, my JSON output was not being formatted. Just setting the header made the extension work.Carberry
R
81

I realize this question is asking about how to encode an associative array to a pretty-formatted JSON string, so this doesn't directly answer the question, but if you have a string that is already in JSON format, you can make it pretty simply by decoding and re-encoding it (requires PHP >= 5.4):

$json = json_encode(json_decode($json), JSON_PRETTY_PRINT);

Example:

header('Content-Type: application/json');
$json_ugly = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
$json_pretty = json_encode(json_decode($json_ugly), JSON_PRETTY_PRINT);
echo $json_pretty;

This outputs:

{
    "a": 1,
    "b": 2,
    "c": 3,
    "d": 4,
    "e": 5
}
Renz answered 20/10, 2015 at 0:47 Comment(6)
thanks, it only works if i add this at the top of php block... header('Content-Type: application/json');Aldana
@Aldana If you don't use that header, PHP will tell the browser that it is sending HTML, so you would have to view the page source to see the formatted JSON string. I assumed that was understood, but I guess not. I've added it to my answer.Renz
And anyone tailing/reviewing a log/file in the unix/linux shell, this is the solution here! Good looking out, @Mike, makes it easy to read!.Astyanax
@Astyanax I'm not really sure what log files you're referring to. I've never heard of any programs that log anything in JSON.Renz
@Mike, it's a quick-n-dirty PHP I whipped up appending the request body (which is a serialized JSON string) POSTed to my PHP in to a textfile, I then tail it in the unix shell so I can watch live POSTs. I'm using your trick to format that JSON making the text file much more usable.Astyanax
Nice I didn't realize the header was necessaryTelephony
O
42

Gluing several answers together fit my need for existing json:

Code:
echo "<pre>"; 
echo json_encode(json_decode($json_response), JSON_PRETTY_PRINT); 
echo "</pre>";

Output:
{
    "data": {
        "token_type": "bearer",
        "expires_in": 3628799,
        "scopes": "full_access",
        "created_at": 1540504324
    },
    "errors": [],
    "pagination": {},
    "token_type": "bearer",
    "expires_in": 3628799,
    "scopes": "full_access",
    "created_at": 1540504324
}
Orphaorphan answered 25/10, 2018 at 21:56 Comment(1)
Here's a little wrapper function to do this: function json_print($json) { return '<pre>' . json_encode(json_decode($json), JSON_PRETTY_PRINT) . '</pre>'; }Vedda
E
40

I had the same issue.

Anyway I just used the json formatting code here:

http://recursive-design.com/blog/2008/03/11/format-json-with-php/

Works well for what I needed it for.

And a more maintained version: https://github.com/GerHobbelt/nicejson-php

Erund answered 19/5, 2011 at 5:54 Comment(2)
I tried github.com/GerHobbelt/nicejson-php and it works great in PHP 5.3.Catto
If you are on PHP7.0 (and above) and still need to pretty-print JSON with custom indentation, localheinz.com/blog/2018/01/04/… should help.Allelomorph
U
28

I have used this:

echo "<pre>".json_encode($response, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES)."</pre>";

Or use php headers as below:

header('Content-type: application/json; charset=UTF-8');
echo json_encode($response, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES);
Ungava answered 17/8, 2019 at 11:45 Comment(0)
A
13

much easier to remind: enter 128

128 is a synonyme for the constant "JSON_PRETTY_PRINT"

( PHP Docs Site)

json_encode($json,128);
//similar to
json_encode($json,JSON_PRETTY_PRINT );
Attraction answered 26/5, 2021 at 19:28 Comment(5)
Please share more details. To me, this looks like a duplicate of the answer that awhie29urh2 provided nine years ago. Is there something new you want to highlight?Escarole
Enums are not there just for the sake of it. I personally would not recommend a enum value with a number. This will of course work, but the code is less understandable.Sedation
but the name is hard to remember, you always have to go to PHP Docs 😄Attraction
php.net/manual/de/json.constants.php#115783Attraction
If verbosity is a problem and you're calling this often, I'd prefer to write a simple wrapper utility function, like json_pretty_encode() than use a magic number.Uhf
C
11

I took the code from Composer : https://github.com/composer/composer/blob/master/src/Composer/Json/JsonFile.php and nicejson : https://github.com/GerHobbelt/nicejson-php/blob/master/nicejson.php Composer code is good because it updates fluently from 5.3 to 5.4 but it only encodes object whereas nicejson takes json strings, so i merged them. The code can be used to format json string and/or encode objects, i'm currently using it in a Drupal module.

if (!defined('JSON_UNESCAPED_SLASHES'))
    define('JSON_UNESCAPED_SLASHES', 64);
if (!defined('JSON_PRETTY_PRINT'))
    define('JSON_PRETTY_PRINT', 128);
if (!defined('JSON_UNESCAPED_UNICODE'))
    define('JSON_UNESCAPED_UNICODE', 256);

function _json_encode($data, $options = 448)
{
    if (version_compare(PHP_VERSION, '5.4', '>='))
    {
        return json_encode($data, $options);
    }

    return _json_format(json_encode($data), $options);
}

function _pretty_print_json($json)
{
    return _json_format($json, JSON_PRETTY_PRINT);
}

function _json_format($json, $options = 448)
{
    $prettyPrint = (bool) ($options & JSON_PRETTY_PRINT);
    $unescapeUnicode = (bool) ($options & JSON_UNESCAPED_UNICODE);
    $unescapeSlashes = (bool) ($options & JSON_UNESCAPED_SLASHES);

    if (!$prettyPrint && !$unescapeUnicode && !$unescapeSlashes)
    {
        return $json;
    }

    $result = '';
    $pos = 0;
    $strLen = strlen($json);
    $indentStr = ' ';
    $newLine = "\n";
    $outOfQuotes = true;
    $buffer = '';
    $noescape = true;

    for ($i = 0; $i < $strLen; $i++)
    {
        // Grab the next character in the string
        $char = substr($json, $i, 1);

        // Are we inside a quoted string?
        if ('"' === $char && $noescape)
        {
            $outOfQuotes = !$outOfQuotes;
        }

        if (!$outOfQuotes)
        {
            $buffer .= $char;
            $noescape = '\\' === $char ? !$noescape : true;
            continue;
        }
        elseif ('' !== $buffer)
        {
            if ($unescapeSlashes)
            {
                $buffer = str_replace('\\/', '/', $buffer);
            }

            if ($unescapeUnicode && function_exists('mb_convert_encoding'))
            {
                // https://mcmap.net/q/55260/-how-to-decode-unicode-escape-sequences-like-quot-u00ed-quot-to-proper-utf-8-encoded-characters
                $buffer = preg_replace_callback('/\\\\u([0-9a-f]{4})/i',
                    function ($match)
                    {
                        return mb_convert_encoding(pack('H*', $match[1]), 'UTF-8', 'UCS-2BE');
                    }, $buffer);
            } 

            $result .= $buffer . $char;
            $buffer = '';
            continue;
        }
        elseif(false !== strpos(" \t\r\n", $char))
        {
            continue;
        }

        if (':' === $char)
        {
            // Add a space after the : character
            $char .= ' ';
        }
        elseif (('}' === $char || ']' === $char))
        {
            $pos--;
            $prevChar = substr($json, $i - 1, 1);

            if ('{' !== $prevChar && '[' !== $prevChar)
            {
                // If this character is the end of an element,
                // output a new line and indent the next line
                $result .= $newLine;
                for ($j = 0; $j < $pos; $j++)
                {
                    $result .= $indentStr;
                }
            }
            else
            {
                // Collapse empty {} and []
                $result = rtrim($result) . "\n\n" . $indentStr;
            }
        }

        $result .= $char;

        // If the last character was the beginning of an element,
        // output a new line and indent the next line
        if (',' === $char || '{' === $char || '[' === $char)
        {
            $result .= $newLine;

            if ('{' === $char || '[' === $char)
            {
                $pos++;
            }

            for ($j = 0; $j < $pos; $j++)
            {
                $result .= $indentStr;
            }
        }
    }
    // If buffer not empty after formating we have an unclosed quote
    if (strlen($buffer) > 0)
    {
        //json is incorrectly formatted
        $result = false;
    }

    return $result;
}
Christoperchristoph answered 16/1, 2014 at 12:41 Comment(3)
This is how it's done! Own implementation runs only if native is not available. If you are sure your code will only run in PHP 5.4 or above you may rest on JSON_PRETTY_PRINTAmorino
This solution gives me error (Parse error: syntax error, unexpected T_FUNCTION) on line function ($match)Visit
Composer took it from daveperrett.com/articles/2008/03/11/format-json-with-php, which is the same as https://mcmap.net/q/53857/-pretty-printing-json-with-php.Allelomorph
M
11

best way to format JSON data is like this!

header('Content-type: application/json; charset=UTF-8');
echo json_encode($response, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES);

Replace $response with your Data which is required to be converted to JSON

Mantling answered 28/3, 2020 at 7:32 Comment(1)
What makes this the best way?Uhf
C
10

Have color full output: Tiny Solution

Code:

$s = '{"access": {"token": {"issued_at": "2008-08-16T14:10:31.309353", "expires": "2008-08-17T14:10:31Z", "id": "MIICQgYJKoZIhvcIegeyJpc3N1ZWRfYXQiOiAi"}, "serviceCatalog": [], "user": {"username": "ajay", "roles_links": [], "id": "16452ca89", "roles": [], "name": "ajay"}}}';

$crl = 0;
$ss = false;
echo "<pre>";
for($c=0; $c<strlen($s); $c++)
{
    if ( $s[$c] == '}' || $s[$c] == ']' )
    {
        $crl--;
        echo "\n";
        echo str_repeat(' ', ($crl*2));
    }
    if ( $s[$c] == '"' && ($s[$c-1] == ',' || $s[$c-2] == ',') )
    {
        echo "\n";
        echo str_repeat(' ', ($crl*2));
    }
    if ( $s[$c] == '"' && !$ss )
    {
        if ( $s[$c-1] == ':' || $s[$c-2] == ':' )
            echo '<span style="color:#0000ff;">';
        else
            echo '<span style="color:#ff0000;">';
    }
    echo $s[$c];
    if ( $s[$c] == '"' && $ss )
        echo '</span>';
    if ( $s[$c] == '"' )
          $ss = !$ss;
    if ( $s[$c] == '{' || $s[$c] == '[' )
    {
        $crl++;
        echo "\n";
        echo str_repeat(' ', ($crl*2));
    }
}
echo $s[$c];
Colonist answered 6/1, 2014 at 15:28 Comment(2)
this was very helpful, even though it had a few errors in it. I fixed them and now it works like a charm, and the function is not that big at all! thanks AjayHighbred
just to comment on the fixes if anyone wants to use this... add a validation check $c > 1 in the second and and third if condition, and the last echo wrap it into an is_array($s) if. that should cover it and you shouldn't get any Uninitialized string offset error.Highbred
T
9

If you are on firefox install JSONovich. Not really a PHP solution I know, but it does the trick for development purposes/debugging.

Trakas answered 19/5, 2011 at 5:24 Comment(2)
I think this is the proper solution for when dev'ing an api. It gives the best of both worlds, easy debugging since you can read everything and you are not altering the backends behaviour, including its performance.Cognizant
Agreed, it's nicely formatted with colours and collapsible too. Much nicer than you could hope to achieve with a bit of PHPClemmy
P
8

Simple way for php>5.4: like in Facebook graph

$Data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');
$json= json_encode($Data, JSON_PRETTY_PRINT);
header('Content-Type: application/json');
print_r($json);

Result in browser

{
    "a": "apple",
    "b": "banana",
    "c": "catnip"
}
Pierrette answered 10/8, 2015 at 16:4 Comment(1)
@Madbreaks, it's prints well in php file, don't need to write in json file, same as like facebook.Pierrette
I
8

Use <pre> in combination with json_encode() and the JSON_PRETTY_PRINT option:

<pre>
    <?php
    echo json_encode($dataArray, JSON_PRETTY_PRINT);
    ?>
</pre>
Indre answered 28/4, 2016 at 7:57 Comment(0)
F
8

If you have existing JSON ($ugly_json)

echo nl2br(str_replace(' ', '&nbsp;', (json_encode(json_decode($ugly_json), JSON_PRETTY_PRINT | JSON_UNESCAPED_SLASHES))));
Fragrant answered 18/9, 2017 at 11:22 Comment(1)
Please add some explanation to your answer such that others can learn from itEscarole
F
6

You can modify Kendall Hopkins' answer a little in the switch statement to get a pretty clean looking and nicely indented printout by passing a json string into the following:

function prettyPrint( $json ){

$result = '';
$level = 0;
$in_quotes = false;
$in_escape = false;
$ends_line_level = NULL;
$json_length = strlen( $json );

for( $i = 0; $i < $json_length; $i++ ) {
    $char = $json[$i];
    $new_line_level = NULL;
    $post = "";
    if( $ends_line_level !== NULL ) {
        $new_line_level = $ends_line_level;
        $ends_line_level = NULL;
    }
    if ( $in_escape ) {
        $in_escape = false;
    } else if( $char === '"' ) {
        $in_quotes = !$in_quotes;
    } else if( ! $in_quotes ) {
        switch( $char ) {
            case '}': case ']':
                $level--;
                $ends_line_level = NULL;
                $new_line_level = $level;
                $char.="<br>";
                for($index=0;$index<$level-1;$index++){$char.="-----";}
                break;

            case '{': case '[':
                $level++;
                $char.="<br>";
                for($index=0;$index<$level;$index++){$char.="-----";}
                break;
            case ',':
                $ends_line_level = $level;
                $char.="<br>";
                for($index=0;$index<$level;$index++){$char.="-----";}
                break;

            case ':':
                $post = " ";
                break;

            case "\t": case "\n": case "\r":
                $char = "";
                $ends_line_level = $new_line_level;
                $new_line_level = NULL;
                break;
        }
    } else if ( $char === '\\' ) {
        $in_escape = true;
    }
    if( $new_line_level !== NULL ) {
        $result .= "\n".str_repeat( "\t", $new_line_level );
    }
    $result .= $char.$post;
}

echo "RESULTS ARE: <br><br>$result";
return $result;

}

Now just run the function prettyPrint( $your_json_string ); inline in your php and enjoy the printout. If you're a minimalist and don't like brackets for some reason, you can get rid of those easily by replacing the $char.="<br>"; with $char="<br>"; in the top three switch cases on $char. Here's what you get for a google maps API call for the city of Calgary

RESULTS ARE: 

{
- - - "results" : [
- - -- - - {
- - -- - -- - - "address_components" : [
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Calgary"
- - -- - -- - -- - -- - - "short_name" : "Calgary"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "locality"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Division No. 6"
- - -- - -- - -- - -- - - "short_name" : "Division No. 6"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "administrative_area_level_2"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Alberta"
- - -- - -- - -- - -- - - "short_name" : "AB"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "administrative_area_level_1"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Canada"
- - -- - -- - -- - -- - - "short_name" : "CA"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "country"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - - ]
- - -- - -
- - -- - -- - - "formatted_address" : "Calgary, AB, Canada"
- - -- - -- - - "geometry" : {
- - -- - -- - -- - - "bounds" : {
- - -- - -- - -- - -- - - "northeast" : {
- - -- - -- - -- - -- - -- - - "lat" : 51.18383
- - -- - -- - -- - -- - -- - - "lng" : -113.8769511 }
- - -- - -- - -- - -
- - -- - -- - -- - -- - - "southwest" : {
- - -- - -- - -- - -- - -- - - "lat" : 50.84240399999999
- - -- - -- - -- - -- - -- - - "lng" : -114.27136 }
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - "location" : {
- - -- - -- - -- - -- - - "lat" : 51.0486151
- - -- - -- - -- - -- - - "lng" : -114.0708459 }
- - -- - -- - -
- - -- - -- - -- - - "location_type" : "APPROXIMATE"
- - -- - -- - -- - - "viewport" : {
- - -- - -- - -- - -- - - "northeast" : {
- - -- - -- - -- - -- - -- - - "lat" : 51.18383
- - -- - -- - -- - -- - -- - - "lng" : -113.8769511 }
- - -- - -- - -- - -
- - -- - -- - -- - -- - - "southwest" : {
- - -- - -- - -- - -- - -- - - "lat" : 50.84240399999999
- - -- - -- - -- - -- - -- - - "lng" : -114.27136 }
- - -- - -- - -- - - }
- - -- - -- - - }
- - -- - -
- - -- - -- - - "place_id" : "ChIJ1T-EnwNwcVMROrZStrE7bSY"
- - -- - -- - - "types" : [
- - -- - -- - -- - - "locality"
- - -- - -- - -- - - "political" ]
- - -- - - }
- - - ]

- - - "status" : "OK" }
Feeding answered 13/6, 2015 at 20:42 Comment(1)
This is really nice thanks. One thing I think to add slight improvement is use a var for: $indent = "-----", then use that (instead of "-----" in different places in the code)Fragrant
E
6

For those running PHP version 5.3 or before, you may try below:

$pretty_json = "<pre>".print_r(json_decode($json), true)."</pre>";

echo $pretty_json;

Ess answered 3/6, 2020 at 3:10 Comment(0)
O
6

I usually use one of these one-liners.

If you already have an JSON string, you can simply use a combination of echo() and print_r(). Don't forget to pass the second parameter of print_r() to true so that it returns the value rather than printing it:

echo('<pre>' . print_r($json, true) . '</pre>');

or you can use die() which is handy for debugging:

die('<pre>' . print_r($json, true) . '</pre>');

If you have an array, you need to convert it to a JSON string before. Be sure to set the second parameter of json_encode() with the JSON_PRETTY_PRINT flag so your JSON will be correctly rendered:

echo('<pre>' . print_r(json_encode($array, JSON_PRETTY_PRINT), true) . '</pre>');

or for debugging:

die('<pre>' . print_r(json_encode($array, JSON_PRETTY_PRINT), true) . '</pre>');
Ordzhonikidze answered 18/11, 2022 at 8:57 Comment(1)
Apt for rendering onto a webpage.Ephemera
E
5

This solution makes 'really pretty' JSON. Not exactly what the OP was asking for, but it lets you visualise the JSON better.

/**
 * takes an object parameter and returns the pretty json format.
 * this is a space saving version that uses 2 spaces instead of the regular 4
 *
 * @param $in
 *
 * @return string
 */
function pretty_json ($in): string
{
  return preg_replace_callback('/^ +/m',
    function (array $matches): string
    {
      return str_repeat(' ', strlen($matches[0]) / 2);
    }, json_encode($in, JSON_PRETTY_PRINT | JSON_HEX_APOS)
  );
}

/**
 * takes a JSON string an adds colours to the keys/values
 * if the string is not JSON then it is returned unaltered.
 *
 * @param string $in
 *
 * @return string
 */

function markup_json (string $in): string
{
  $string  = 'green';
  $number  = 'darkorange';
  $null    = 'magenta';
  $key     = 'red';
  $pattern = '/("(\\\\u[a-zA-Z0-9]{4}|\\\\[^u]|[^\\\\"])*"(\s*:)?|\b(true|false|null)\b|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?)/';
  return preg_replace_callback($pattern,
      function (array $matches) use ($string, $number, $null, $key): string
      {
        $match  = $matches[0];
        $colour = $number;
        if (preg_match('/^"/', $match))
        {
          $colour = preg_match('/:$/', $match)
            ? $key
            : $string;
        }
        elseif ($match === 'null')
        {
          $colour = $null;
        }
        return "<span style='color:{$colour}'>{$match}</span>";
      }, str_replace(['<', '>', '&'], ['&lt;', '&gt;', '&amp;'], $in)
   ) ?? $in;
}

public function test_pretty_json_object ()
{
  $ob       = new \stdClass();
  $ob->test = 'unit-tester';
  $json     = pretty_json($ob);
  $expected = <<<JSON
{
  "test": "unit-tester"
}
JSON;
  $this->assertEquals($expected, $json);
}

public function test_pretty_json_str ()
{
  $ob   = 'unit-tester';
  $json = pretty_json($ob);
  $this->assertEquals("\"$ob\"", $json);
}

public function test_markup_json ()
{
  $json = <<<JSON
[{"name":"abc","id":123,"warnings":[],"errors":null},{"name":"abc"}]
JSON;
  $expected = <<<STR
[
  {
    <span style='color:red'>"name":</span> <span style='color:green'>"abc"</span>,
    <span style='color:red'>"id":</span> <span style='color:darkorange'>123</span>,
    <span style='color:red'>"warnings":</span> [],
    <span style='color:red'>"errors":</span> <span style='color:magenta'>null</span>
  },
  {
    <span style='color:red'>"name":</span> <span style='color:green'>"abc"</span>
  }
]
STR;

  $output = markup_json(pretty_json(json_decode($json)));
  $this->assertEquals($expected,$output);
}

}

Eta answered 20/8, 2018 at 12:52 Comment(0)
E
4

If you used only $json_string = json_encode($data, JSON_PRETTY_PRINT);, you will get in the browser something like this (using the Facebook link from the question :) ): enter image description here

but if you used a chrome Extension like JSONView (even without the PHP option above), then you get a more pretty readable debuggable solution where you can even Fold/Collapse each single JSON object easily like this: enter image description here

Extravert answered 23/6, 2014 at 10:52 Comment(0)
S
3

You could do it like below.

$array = array(
   "a" => "apple",
   "b" => "banana",
   "c" => "catnip"
);

foreach ($array as $a_key => $a_val) {
   $json .= "\"{$a_key}\" : \"{$a_val}\",\n";
}

header('Content-Type: application/json');
echo "{\n"  .rtrim($json, ",\n") . "\n}";

Above would output kind of like Facebook.

{
"a" : "apple",
"b" : "banana",
"c" : "catnip"
}
Safire answered 23/11, 2013 at 3:52 Comment(2)
What if a_val is an array or an object?Pint
I answered an example using the Json in the question, I will update my answer soon.Safire
O
3

Classic case for a recursive solution. Here's mine:

class JsonFormatter {
    public static function prettyPrint(&$j, $indentor = "\t", $indent = "") {
        $inString = $escaped = false;
        $result = $indent;

        if(is_string($j)) {
            $bak = $j;
            $j = str_split(trim($j, '"'));
        }

        while(count($j)) {
            $c = array_shift($j);
            if(false !== strpos("{[,]}", $c)) {
                if($inString) {
                    $result .= $c;
                } else if($c == '{' || $c == '[') {
                    $result .= $c."\n";
                    $result .= self::prettyPrint($j, $indentor, $indentor.$indent);
                    $result .= $indent.array_shift($j);
                } else if($c == '}' || $c == ']') {
                    array_unshift($j, $c);
                    $result .= "\n";
                    return $result;
                } else {
                    $result .= $c."\n".$indent;
                } 
            } else {
                $result .= $c;
                $c == '"' && !$escaped && $inString = !$inString;
                $escaped = $c == '\\' ? !$escaped : false;
            }
        }

        $j = $bak;
        return $result;
    }
}

Usage:

php > require 'JsonFormatter.php';
php > $a = array('foo' => 1, 'bar' => 'This "is" bar', 'baz' => array('a' => 1, 'b' => 2, 'c' => '"3"'));
php > print_r($a);
Array
(
    [foo] => 1
    [bar] => This "is" bar
    [baz] => Array
        (
            [a] => 1
            [b] => 2
            [c] => "3"
        )

)
php > echo JsonFormatter::prettyPrint(json_encode($a));
{
    "foo":1,
    "bar":"This \"is\" bar",
    "baz":{
        "a":1,
        "b":2,
        "c":"\"3\""
    }
}

Cheers

Onetoone answered 9/10, 2015 at 18:50 Comment(0)
A
1

print_r pretty print for PHP

Example PHP

function print_nice($elem,$max_level=10,$print_nice_stack=array()){
    if(is_array($elem) || is_object($elem)){
        if(in_array($elem,$print_nice_stack,true)){
            echo "<font color=red>RECURSION</font>";
            return;
        }
        $print_nice_stack[]=&$elem;
        if($max_level<1){
            echo "<font color=red>nivel maximo alcanzado</font>";
            return;
        }
        $max_level--;
        echo "<table border=1 cellspacing=0 cellpadding=3 width=100%>";
        if(is_array($elem)){
            echo '<tr><td colspan=2 style="background-color:#333333;"><strong><font color=white>ARRAY</font></strong></td></tr>';
        }else{
            echo '<tr><td colspan=2 style="background-color:#333333;"><strong>';
            echo '<font color=white>OBJECT Type: '.get_class($elem).'</font></strong></td></tr>';
        }
        $color=0;
        foreach($elem as $k => $v){
            if($max_level%2){
                $rgb=($color++%2)?"#888888":"#BBBBBB";
            }else{
                $rgb=($color++%2)?"#8888BB":"#BBBBFF";
            }
            echo '<tr><td valign="top" style="width:40px;background-color:'.$rgb.';">';
            echo '<strong>'.$k."</strong></td><td>";
            print_nice($v,$max_level,$print_nice_stack);
            echo "</td></tr>";
        }
        echo "</table>";
        return;
    }
    if($elem === null){
        echo "<font color=green>NULL</font>";
    }elseif($elem === 0){
        echo "0";
    }elseif($elem === true){
        echo "<font color=green>TRUE</font>";
    }elseif($elem === false){
        echo "<font color=green>FALSE</font>";
    }elseif($elem === ""){
        echo "<font color=green>EMPTY STRING</font>";
    }else{
        echo str_replace("\n","<strong><font color=red>*</font></strong><br>\n",$elem);
    }
}
Academy answered 27/7, 2016 at 5:19 Comment(0)
B
1

1 - json_encode($rows,JSON_PRETTY_PRINT); returns prettified data with newline characters. This is helpful for command line input, but as you've discovered doesn't look as pretty within the browser. The browser will accept the newlines as the source (and thus, viewing the page source will indeed show the pretty JSON), but they aren't used to format the output in browsers. Browsers require HTML.

2 - use this fuction github

<?php
    /**
     * Formats a JSON string for pretty printing
     *
     * @param string $json The JSON to make pretty
     * @param bool $html Insert nonbreaking spaces and <br />s for tabs and linebreaks
     * @return string The prettified output
     * @author Jay Roberts
     */
    function _format_json($json, $html = false) {
        $tabcount = 0;
        $result = '';
        $inquote = false;
        $ignorenext = false;
        if ($html) {
            $tab = "&nbsp;&nbsp;&nbsp;&nbsp;";
            $newline = "<br/>";
        } else {
            $tab = "\t";
            $newline = "\n";
        }
        for($i = 0; $i < strlen($json); $i++) {
            $char = $json[$i];
            if ($ignorenext) {
                $result .= $char;
                $ignorenext = false;
            } else {
                switch($char) {
                    case '[':
                    case '{':
                        $tabcount++;
                        $result .= $char . $newline . str_repeat($tab, $tabcount);
                        break;
                    case ']':
                    case '}':
                        $tabcount--;
                        $result = trim($result) . $newline . str_repeat($tab, $tabcount) . $char;
                        break;
                    case ',':
                        $result .= $char . $newline . str_repeat($tab, $tabcount);
                        break;
                    case '"':
                        $inquote = !$inquote;
                        $result .= $char;
                        break;
                    case '\\':
                        if ($inquote) $ignorenext = true;
                        $result .= $char;
                        break;
                    default:
                        $result .= $char;
                }
            }
        }
        return $result;
    }
Belligerent answered 22/6, 2017 at 11:2 Comment(0)
J
1

here's the function i use myself, the api is just like json_encode, except it has a 3rd argument exclude_flags in case you want to exclude some of the default flags (like JSON_UNESCAPED_SLASHES)

function json_encode_pretty($data, int $extra_flags = 0, int $exclude_flags = 0): string
{
    // prettiest flags for: 7.3.9
    $flags = JSON_PRETTY_PRINT | JSON_UNESCAPED_SLASHES | JSON_UNESCAPED_UNICODE | (defined("JSON_UNESCAPED_LINE_TERMINATORS") ? JSON_UNESCAPED_LINE_TERMINATORS : 0) | JSON_PRESERVE_ZERO_FRACTION | (defined("JSON_THROW_ON_ERROR") ? JSON_THROW_ON_ERROR : 0);
    $flags = ($flags | $extra_flags) & ~ $exclude_flags;
    return (json_encode($data, $flags));
}
Jenicejeniece answered 11/2, 2021 at 14:9 Comment(0)
G
0

The following is what worked for me:

Contents of test.php:

<html>
<body>
Testing JSON array output
  <pre>
  <?php
  $data = array('a'=>'apple', 'b'=>'banana', 'c'=>'catnip');
  // encode in json format 
  $data = json_encode($data);

  // json as single line
  echo "</br>Json as single line </br>";
  echo $data;
  // json as an array, formatted nicely
  echo "</br>Json as multiline array </br>";
  print_r(json_decode($data, true));
  ?>
  </pre>
</body>
</html>

output:

Testing JSON array output


Json as single line 
{"a":"apple","b":"banana","c":"catnip"}
Json as multiline array 
Array
(
    [a] => apple
    [b] => banana
    [c] => catnip
)

Also note the use of "pre" tag in html.

Hope that helps someone

Gregggreggory answered 24/9, 2013 at 17:18 Comment(1)
This doesn't answer the question. You're dumping vars, not printing formatted JSON.Onetoone
C
-6

If you are working with MVC

try doing this in your controller

public function getLatestUsers() {
    header('Content-Type: application/json');
    echo $this->model->getLatestUsers(); // this returns json_encode($somedata, JSON_PRETTY_PRINT)
}

then if you call /getLatestUsers you will get a pretty JSON output ;)

Crenelate answered 23/4, 2013 at 16:1 Comment(3)
see my comment after the echo where it is being pretty printendCrenelate
MVC is a type of framework design, nothing to do with outputting JSON.Katerinekates
its an answer from 2013 people ;)Crenelate

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