I am a beginner in gulp. I have created a task named task1 in gulp.js and when i tried to execute that task using "gulp task1" in command line, Its opening the gulp.js file on brackets editor rather than executing in command line. Can somebody help me in solving this problem
The code in my gulp file is
var gulp = require('gulp');
var jshint = require('gulp-jshint');
var jscs = require('gulp-jscs');
gulp.task('task1', function () {
return gulp
.src(['./src/**/x.js', './*.js'])
.pipe(jscs())
.pipe(jshint())
.pipe(jshint.reporter('jshint-stylish', {
verbose: true
}));
})
gulp -v
? Does it show you the gulp version? – Stickup