I'm aware of what the issue is stating but I am confused to how my program is outputting a value that's outside of the array..
I have an array of ints which is 0 - 8 which means it can hold 9 ints, correct? I have an int which is checked to make sure the users input value is 1-9. I remove one from the integer (like so)
if (posStatus[intUsersInput-1] == 0) //if pos is empty
{
posStatus[intUsersInput-1] += 1;
}//set it to 1
then I input 9 myself and I get the error. It should access the last int in the array, so I don't see why I'm getting an error. Relevant code:
public int[] posStatus;
public UsersInput()
{
this.posStatus = new int[8];
}
int intUsersInput = 0; //this gets try parsed + validated that it's 1-9
if (posStatus[intUsersInput-1] == 0) //if i input 9 it should go to 8?
{
posStatus[intUsersInput-1] += 1; //set it to 1
}
Error:
"Index was outside the bounds of the array." "Index was outside the bounds of the array."
new int[9]
... – Biamontenew int[8]
creates an array with 8 elements so the valid indices are [0,7]. – Curtin