Can you simply check whether an object's reference is assigned a value of nil
to indicate that it has been released?
No, because sending a release
message to an object and assigning nil
to a variable are two different and unrelated things.
The closest you can get is that assigning anything to a strong/retaining or copying property, which translates to an accessor message, causes the previous value of the property to be released (which is done by the setter). Even so, watching the value of the property—using KVO, say—does not mean you will know when the object is released; most especially, when the owning object is deallocated, you will not get a notification when it sends release
directly to the owned object. You will also get a warning message in your console (because the owning object died while you were observing it), and you do not want noisy warning messages from a unit test. Plus, you would have to specifically observe every property of every object to pull this off—miss one, and you may be missing a bug.
A release
message to an object has no effect on any variables that point to that object. Neither does deallocation.
This changes slightly under ARC: Weak-referencing variables will be automatically assigned nil
when the referenced object goes away. That doesn't help you much, though, because strongly-referencing variables, by definition, will not: If there's a strong reference to the object, the object won't (well, shouldn't) go away, because the strong reference will (should) keep it alive. An object dying before it should is one of the problems you're looking for, not something you'll want to use as a tool.
You could theoretically create a weak reference to every object you create, but you would have to refer to every object specifically, creating a variable for it manually in your code. As you can imagine, a tremendous pain and certain to miss objects.
Also, what guarantees do you have about the timing at which objects are actually released?
An object is released by sending it a release
message, so the object is released when it receives that message.
Perhaps you meant “deallocated”. Releasing merely brings it closer to that point; an object can be released many times and still have a long life ahead of it if each release merely balanced out a previous retain.
An object is deallocated when it is released for the last time. This happens immediately. The infamous retainCount
doesn't even go down to 0, as many a clever person who tried to write while ([obj retainCount] > 0) [obj release];
has found out.
There may actually be two answers: one that uses the autorelease pool, and another that does not.
A solution that uses the autorelease pool only works for objects that are autoreleased; by definition, objects not autoreleased do not go into the pool. It is entirely valid, and occasionally desirable, to never autorelease certain objects (particularly those you create many thousands of). Moreover, you can't look into the pool to see what's in it and what's not, or attempt to poke each object to see if it's dead.
How would you write a unit test—using OCUnit, for instance—to ensure that objects are being released/retained properly in Cocoa/Objective-C?
The best you could do is to set NSZombieEnabled
to YES
in setUp
and restore its previous value in tearDown
. This will catch over-releases/under-retains, but not leaks of any kind.
Even if you could write a unit test that thoroughly tests memory management, it would still be imperfect because it can only test the testable code—model objects and maybe certain controllers. You could still have leaks and crashes in your application caused by view code, nib-borne references and certain options (“Release When Closed” comes to mind), and so on.
There's no out-of-application test you can write that will ensure that your application is memory-bug-free.
That said, a test like you're imagining, if it were self-contained and automatic, would be pretty cool, even if it couldn't test everything. So I hope that I'm wrong and there is a way.