How to create a generic method in Dart?
Asked Answered
C

2

27

I'm trying to use generic methods in Dart (1.22.0-dev.10.3). Here is a simple example:

abstract class VR<T> {
  VR();

  bool foo<T>(T value);
}

class VRInt extends VR<int> {
  VRInt();

  bool foo<int>(int n) => n > 0; // Thinks n is Object
}

class VRString extends VR<String> {
  VRString();

  bool foo<String>(String s) => s.length > 0; // Thinks s is Object
}

Both subclasses generate errors that say the argument to foo is an Object.

I'm sure this is just a syntactic error on my part, but I've searched the documentation and can't find an answer.

Credential answered 2/2, 2017 at 14:15 Comment(0)
G
25

What you are doing could be done already before generic methods were introduced because you're just using the generic type parameter of the class. For this purpose just remove the type parameters on the methods to fix the problem.

Generic methods are to allow to pass a type that specializes a method no the call site

class MyClass {
  T myMethod<T>(T param) {
    prinz(param);
  }
}

and then use it like

new MyClass().myMethod<List<String>>(['a', 'b', 'c']);
Grainy answered 2/2, 2017 at 14:23 Comment(4)
How can we say that T should implement an Interface/ClassDemirep
T myMethod<T extends SomeType>. See also #18699373Archdeaconry
@GünterZöchbauer May you could correct the output: console.log('javascript') to print('dart')Denys
Thanks @CassioSeffrin! Seems I mixed in some TypeScript :DArchdeaconry
C
12

Generic methods have type parameters that are not directly related to their class parameter types.

You can have a generic method on a class without generic:

class MyClass {
  T add<T>(T f()) => f();
}

You can also have a generic method on a class with generic:

class MyClass<A> {
  A aInstance;
  // here <T> is needed because unrelated to <A>
  T add<T>(T f(A a)) => f(aInstance);
}

In your case, you don't need the type parameter on the methods:

abstract class VR<T> {
  VR();

  bool foo(T value);
}

class VRInt extends VR<int> {
  VRInt();

  bool foo(int n) => n > 0; // Thinks n is Object
}

class VRString extends VR<String> {
  VRString();

  bool foo(String s) => s.length > 0; // Thinks s is Object
}

But there are no concept of generic method needed here.

Cognition answered 2/2, 2017 at 14:57 Comment(0)

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