Basically, I have a multidimensional array, and I need to check whether or not it is simply empty, or not.
I currently have an if
statement trying to do this with:
if(!empty($csv_array))
{
//My code goes here if the array is not empty
}
Although, that if statement
is being activated whether the multidimensional array is empty or not.
This is what the array looks like when empty:
Array
(
[0] => Array
(
)
)
This is what the array looks like when it has a few elements in it:
Array
(
[0] => Array
(
)
[1] => Array
(
[1] => question1
[2] => answer1
[3] => answer2
[4] => answer3
[5] => answer4
)
[2] => Array
(
[1] => question2
[2] => answer1
[3] => answer2
[4] => answer3
[5] => answer4
)
[3] => Array
(
[1] => question3
[2] => answer1
[3] => answer2
[4] => answer3
[5] => answer4
)
)
My array elements always start at 1, and not 0. Long story why, and no point explaining since it is off-topic to this question.
If needed, this is the code that is creating the array. It is being pulled from an uploaded CSV file.
$csv_array = array(array());
if (!empty($_FILES['upload_csv']['tmp_name']))
{
$file = fopen($_FILES['upload_csv']['tmp_name'], 'r');
}
if($file)
{
while (($line = fgetcsv($file)) !== FALSE)
{
$csv_array[] = array_combine(range(1, count($line)), array_values($line));
}
fclose($file);
}
So in conclusion, I need to modify my if statement
to check whether the array is empty or not.
Thanks in advance!
if(!empty($csv_array[0]))
? – Closed