CoreGraphics for retina display
Asked Answered
D

3

30

I am using the following code to perform some manipulations on the image that I loaded, but I find that the display becomes blurry when it is on the retina display

- (UIImage*)createImageSection:(UIImage*)image section:(CGRect)section

{
float originalWidth = image.size.width ;
float originalHeight = image.size.height ;
int w = originalWidth * section.size.width;
int h = originalHeight * section.size.height;

CGContextRef ctx = CGBitmapContextCreate(nil, w, h, 8, w * 8,CGImageGetColorSpace([image CGImage]), kCGImageAlphaPremultipliedLast);
CGContextClearRect(ctx, CGRectMake(0, 0, originalWidth * section.size.width, originalHeight * section.size.height)); // w + h before
CGContextTranslateCTM(ctx, (float)-originalWidth * section.origin.x, (float)-originalHeight * section.origin.y);
CGContextDrawImage(ctx, CGRectMake(0, 0, originalWidth, originalHeight), [image CGImage]);
CGImageRef cgImage = CGBitmapContextCreateImage(ctx);
UIImage* resultImage = [[UIImage alloc] initWithCGImage:cgImage];

CGContextRelease(ctx);
CGImageRelease(cgImage);

return resultImage;
}

How do I change this to make it retina compatible.

Thanks in advance for your help

Best, DV

Dissever answered 16/1, 2011 at 19:13 Comment(0)
F
48

CGImages don't take into account the Retina-ness of your device, so you have to do so yourself.

To do that, you need to multiply all of your coordinates and sizes that use in CoreGraphics routines by the input image's scale property (which will be 2.0 on Retina devices), to ensure you do all your manipulation at double resolution.

Then you need to change the initialization of resultImage to use initWithCGImage:scale:orientation: and input the same scale factor. This is what makes Retina devices render the output at native resolution rather than pixel-doubled resolution.

Frisse answered 16/1, 2011 at 19:43 Comment(4)
If you change the CTM (current transform matrix) of your context by calling CGContextScaleCTM(UIGraphicsGetCurrentContext(), 2, 2), you don't need to manually multiply your coordinates, you can just draw the same as you would with non-retina images.Christinchristina
Sorry, was too quick with the comment and too late for the edit. If you do it like this, you don't need to think of scaling all the coordinates yourself: CGFloat scale = [[UIScreen mainScreen] scale]; CGContextScaleCTM(UIGraphicsGetCurrentContext(), scale, scale);Christinchristina
So much yes. Great solution.Hard
Still have to manually fix the scale if you draw only a portion (a sub rect) inside that image.Bum
P
5

Thanks for the answer, helped me! Anyway to be clearer, the code by OP should be changed like this:

- (UIImage*)createImageSection:(UIImage*)image section:(CGRect)section        
{
    CGFloat scale = [[UIScreen mainScreen] scale]; ////// ADD

    float originalWidth = image.size.width ;
    float originalHeight = image.size.height ;
    int w = originalWidth * section.size.width *scale; ////// CHANGE
    int h = originalHeight * section.size.height *scale; ////// CHANGE

    CGContextRef ctx = CGBitmapContextCreate(nil, w, h, 8, w * 8,CGImageGetColorSpace([image CGImage]), kCGImageAlphaPremultipliedLast);
    CGContextClearRect(ctx, CGRectMake(0, 0, originalWidth * section.size.width, originalHeight * section.size.height)); // w + h before
    CGContextTranslateCTM(ctx, (float)-originalWidth * section.origin.x, (float)-originalHeight * section.origin.y);

    CGContextScaleCTM(UIGraphicsGetCurrentContext(), scale, scale); ////// ADD

    CGContextDrawImage(ctx, CGRectMake(0, 0, originalWidth, originalHeight), [image CGImage]);
    CGImageRef cgImage = CGBitmapContextCreateImage(ctx);
    UIImage* resultImage = [[UIImage alloc] initWithCGImage:cgImage];

    CGContextRelease(ctx);
    CGImageRelease(cgImage);

    return resultImage;
}
Periodic answered 21/11, 2012 at 6:36 Comment(0)
S
2

Swift version :

    let scale = UIScreen.mainScreen().scale

    CGContextScaleCTM(UIGraphicsGetCurrentContext(), scale, scale)
Suazo answered 6/1, 2016 at 9:26 Comment(0)

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