How can I fix FastAPI application error on Apache WSGI?

I am trying to run FastAPI application on Apache running server. I have configured Apache virtual host file accordingly

<VirtualHost *:80>
        ServerAdmin [email protected]
        ServerName fastapi.example.com
        ServerAlias fastapi.example.com
        DocumentRoot /var/www/fastapi
        ErrorLog ${APACHE_LOG_DIR}/fastapi_error.log
        CustomLog ${APACHE_LOG_DIR}/fastapi_access.log combined
        WSGIScriptAlias / /var/www/fastapi/main.wsgi
        <Directory "/var/www/fastapi">
                AllowOverride All
        </Directory>
</VirtualHost>

and created main.wsgi and main.py files.

main.wsgi

#! /usr/bin/python3.7

import logging
import sys
logging.basicConfig(stream=sys.stderr)
sys.path.insert(0, '/var/www/fastapi/')
from main import app as application
application.secret_key = 'alibaba'

main.py

from typing import Optional
from fastapi import FastAPI
app = FastAPI()

@app.get("/")
def read_root():
    return {"Hello": "World"}

@app.get("/items/{item_id}")
def read_item(item_id: int, q: Optional[str] = None):
    return {"item_id": item_id, "q": q}

When i am trying to access the web, I got the 500 Internal server Error with the following log in fastapi_access.log

mod_wsgi (pid=24946): Exception occurred processing WSGI script '/var/www/fastapi/main.wsgi'.
TypeError: __call__() missing 1 required positional argument: 'send'

Could you please advice, how can I fix this problem and what am I doing wrong?

Thanks in advance.

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