Finding control within WPF itemscontrol
Asked Answered
I

5

28

Hi i have few a single textbox within the the datatemplate for itemscontrol. When i bind the itemcontrols to a observable collection i get two text boxes. But i need to do some manipulations based on each of the text boxes for which i want to find each textbox seperatly using some id.

Can anybody help on how to find a control witin the itemscontrol in WPF.

Interlude answered 11/6, 2009 at 9:15 Comment(4)
What kind of manipulation do you need to perform? Do you need to identify the textboxes uniquely among all items of the itemscontrol or only to separate the two from each other?Danuloff
Hi Oscar I had only labels and textboxes inside my itemscontrol. I need a way to get the handle for textbox control uniquely (using some id). The basic need to set focus on textbox when the itemscontrol is loaded and need to identify which of the textboxes has focus at a given time and perform some operation. Thanks Deepak Thanks DeepakInterlude
More simply how can i iterate over the itemscontrol control collection using c#.Interlude
Similar: #1000845Helaine
H
77

Using the ItemContainerGenerator you can obtain the generated container for an item and traverse the visual tree downwards to find your TextBox. In the case of an ItemsControl it will be a ContentPresenter, but a ListBox will return a ListBoxItem, ListView a ListViewItem, etc.

ContentPresenter cp = itemsControl.ItemContainerGenerator.ContainerFromItem(item) as ContentPresenter;
TextBox tb = FindVisualChild<TextBox>(cp);
if (tb != null)
{
    // do something with tb
}

public static T FindVisualChild<T>(DependencyObject depObj) where T : DependencyObject
{
    if (depObj != null)
    {
        for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
        {
            DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
            if (child != null && child is T)
            {
                return (T)child;
            }

            T childItem = FindVisualChild<T>(child);
            if (childItem != null) return childItem;
        }
    }
    return null;
}

You can also obtain the container by index if you want by using

itemsControl.ItemContainerGenerator.ContainerFromIndex(0);
Horsefly answered 12/6, 2009 at 3:43 Comment(3)
I'm using this method, but I'm calling it in the constructor. (bad idea?) Anyhow, I had to call child.ApplyTemplate(); to get the visual tree to populate for children with templates defined in static resources.Resurrectionism
Or you can use cp.ContentTemplate.FindName to find a control by name.Buddhi
What's item in the first line?Bainite
T
5

Thanks Bryce, I tried to tick the up arrow but it says my rating is too low! Sorry!

I amended the code to return all a list of all the children of the given type as it was what I needed and thought someone else might find it useful.

Thanks again Bryce, really helpful - sorry about the rating thing!

public static List<T> FindVisualChildren<T>(DependencyObject depObj) where T : DependencyObject
    {
        List<T> list = new List<T>();
        if (depObj != null)
        {
            for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
            {
                DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
                if (child != null && child is T)
                {
                    list.Add((T)child);
                }

                List<T> childItems = FindVisualChildren<T>(child);
                if (childItems != null && childItems.Count() > 0)
                {
                    foreach (var item in childItems)
                    {
                        list.Add(item);
                    }
                }
            }
        }
        return list;
    }
Transfinite answered 25/6, 2009 at 10:45 Comment(2)
I recently posted a slight variation of what you are trying to do here: #975098Horsefly
@Clarke: A minor fix - it should be childItems.Count instead of childItems.Count().Curtis
T
2

You may want to try using VisualTreeHelper. The properties on ItemsControl itself will only allow you to get the data its bound to, not the template instances used to visualize the data, while VisualTreeHelper allows you to browse around the visual tree as WPF has rendered it.

If you iterate through the parent ItemControl's visual children (recursively), you shouldn't have any difficulty locating the text boxes you are seeing on screen.

Trailblazer answered 11/6, 2009 at 13:56 Comment(0)
A
1

Another example:

    private void DataGridBank_KeyUp(object sender, System.Windows.Input.KeyEventArgs e)
    {
        try
        {     
            switch (e.Key)
            {
                case Key.Down:

                    if ((DataGridBank.SelectedIndex + 1) <= DataGridBank.Items.Count)
                    {
                        DataGridBank.SelectedIndex = DataGridBank.SelectedIndex + 1;
                        FocusCell();
                    }
                    break;

                case Key.Up:

                    if ((DataGridBank.SelectedIndex - 1) >= 0)
                    {
                        DataGridBank.SelectedIndex = DataGridBank.SelectedIndex - 1;
                        FocusCell();
                    }
                    break;

                case Key.Enter:
                case Key.Tab:
                    FocusCell();                   

                    break;
            }
        }
        catch (Exception ex)
        {

        }
    }


    private void DataGridBank_Loaded(object sender, RoutedEventArgs e)
    {
        try
        {
            if (DataGridBank.Items.Count > 0)
            {
                DataGridBank.SelectedIndex = 0;

                FocusCell();
            }

        }catch(Exception ex)
        {

        }
    }


    private void FocusCell()
    {
        var selectedRow = (DataGridRow)DataGridBank.ItemContainerGenerator.ContainerFromItem(DataGridBank.SelectedItem);

        var textImport = FindVisualChild<TextBox>(selectedRow);
        textImport.Focus();
        textImport.SelectAll();
    }


    public static T FindVisualChild<T>(DependencyObject depObj) where T : DependencyObject
    {
        if (depObj != null)
        {
            for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
            {
                DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
                if (child != null && child is T)
                {
                    return (T)child;
                }

                T childItem = FindVisualChild<T>(child);
                if (childItem != null) return childItem;
            }
        }
        return null;
    }
Acceptance answered 7/11, 2012 at 23:53 Comment(0)
T
0

If you have data grid and template column, which contains data template, you can use the following code sample

<DataGridTemplateColumn x:Name="photoPathColumn" Header="{x:Static resx:FrmResource.Photo}">
    <DataGridTemplateColumn.CellEditingTemplate x:Uid="keyelm">
        <DataTemplate x:Name="dodo">
            <StackPanel Orientation="Horizontal" Height="Auto">
                <TextBlock x:Name="photo" x:Uid="imageFile" Text="{Binding Path=PhotoPath}" />
                <Button x:Name="Browse" Content="..." Click="Browse_Click" />
            </StackPanel>
        </DataTemplate>
    </DataGridTemplateColumn.CellEditingTemplate>

photoPathColumn.CellEditingTemplate.FindName("photo",photoPathColumn.GetCellContent(CustomersDataGrid.CurrentItem)) 
Tonsillectomy answered 17/8, 2010 at 2:50 Comment(0)

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