Referring to Is there a static code analyzer [like Lint] for PHP files? -- I am looking at how to assess the content of PHP files before they are committed by developers. Whichever solution(s) are appropriate will be triggered via SVN hooks similar to the answer: Is it possible to check PHP file syntax from PHP?
I came across this Automatic Syntax checking of PHP files when checking into SVN which is the angle I'm going for, however ... php -l
isn't quite sufficient.
For example, given the code:
if ($foo == 'bar') {
echo $foo;
}
This results in:
2012/01/15 02:51:14 [error] 694#0: *164 FastCGI sent in stderr: "PHP Notice: Undefined variable: foo
Compared to:
if (isset($foo)) { echo $foo; }
Some of this comes down to educating coders on best practices. Unfortunately, some don't learn as quickly as others, and the only way to ensure that compliance to coding standards is met, is to reduce what is going into SVN that has been untested or isn't compliant.
From the first link in this question, I have tried:
- php -l
- doesn't notify about the problem with
$foo
- doesn't notify about the problem with
- phplint-pure-c-1.0_20110223 - PHPLint
- doesn't notify about the problem with
$foo
- doesn't notify about the problem with
if ($foo == 'bar') { \_ HERE
==== /mnt/hgfs/workspace/scratch-pad/phpinfo.php:44: Warning: comparing (unknown) == (string): cannot check the comparison between unknown types
- phpcs - PHP Code Sniffer
- doesn't notify about the problem with
$foo
despite PHP Sanity Check indicating it was the right answer
- doesn't notify about the problem with
- SimpleTest
- Is very nice, but requires the developers who are writing the bad code to write good unit tests...
All are interesting in their own way, but none are catching these problems that really are only being found at runtime.
Appreciate input / thoughts on this topic.
EDIT
There was one poster who suggested that PHPLint was the right way to go. I thought, OK! Let's try it again given that there is a new version: phplint-pure-c-1.1_20120202:
<?php
if ($foo == 'bar') {
echo $foo;
}
?>
Simple test .................... and, it works and reports 1 error, 1 warning. However, if the following is added BEFORE the if
statement:
<?php
if (isset($foo) && $foo == 'bar') { echo 'man'; }
if ($foo == 'bar') {
echo $foo;
}
?>
it does not work, and reports 0 errors, 2 warnings.